/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 Displacement vector \(\overright... [FREE SOLUTION] | 91Ó°ÊÓ

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Displacement vector \(\overrightarrow{\mathbf{A}}\) points due east and has a magnitude of \(2.00 \mathrm{km} .\) Displacement vector \(\overrightarrow{\mathbf{B}}\) points due north and has a magnitude of \(3.75 \mathrm{km} .\) Displacement vector \(\overrightarrow{\mathrm{C}}\) points due west and has a magnitude of \(2.50 \mathrm{km} .\) Displacement vector \(\overrightarrow{\mathbf{D}}\) points due south and has a magnitude of \(3.00 \mathrm{km} .\) Find the magnitude and direction (relative to due west) of the resultant vector \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}+\overrightarrow{\mathbf{C}}+\overrightarrow{\mathbf{D}}.\)

Short Answer

Expert verified
Magnitude: 0.90 km, Direction: 56.31° north of west.

Step by step solution

01

Define the problem

Given four displacement vectors \( \overrightarrow{\mathbf{A}}, \overrightarrow{\mathbf{B}}, \overrightarrow{\mathbf{C}}, \text{ and } \overrightarrow{\mathbf{D}} \). We need to find the resultant vector formed by adding these vectors together, and then determine its magnitude and direction relative to due west.
02

Break down vectors into components

Convert each vector into its components. Since the vectors are aligned along cardinal directions:- \( \overrightarrow{\mathbf{A}} = (2.00, 0) \) km due east.- \( \overrightarrow{\mathbf{B}} = (0, 3.75) \) km due north.- \( \overrightarrow{\mathbf{C}} = (-2.50, 0) \) km due west.- \( \overrightarrow{\mathbf{D}} = (0, -3.00) \) km due south.
03

Sum the components

Add up the components of each vector to find the resultant vector:\[\overrightarrow{\mathbf{R}} = \overrightarrow{\mathbf{A}} + \overrightarrow{\mathbf{B}} + \overrightarrow{\mathbf{C}} + \overrightarrow{\mathbf{D}} = (2.00 - 2.50, 3.75 - 3.00) \text{ km}\]\[\overrightarrow{\mathbf{R}} = (-0.50, 0.75) \text{ km}\]
04

Calculate the magnitude of the resultant vector

The magnitude of the resultant vector \( \overrightarrow{\mathbf{R}} \) is calculated using the Pythagorean theorem: \[|\overrightarrow{\mathbf{R}}| = \sqrt{(-0.50)^2 + (0.75)^2}\]\[|\overrightarrow{\mathbf{R}}| = \sqrt{0.25 + 0.5625} = \sqrt{0.8125} \approx 0.90 \text{ km}\]
05

Determine the direction of the resultant vector

Find the angle \( \theta \) of the resultant vector with respect to the west direction using the tangent function:\[\theta = \tan^{-1}\left( \frac{0.75}{0.50} \right)\]\[\theta \approx \tan^{-1}(1.5) \approx 56.31^\circ \text{ north of west}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Addition
When dealing with multiple vectors, like in the exercise involving displacement vectors, it's essential to understand the process of vector addition. Vector addition is the method of combining two or more vectors to find a resultant vector. This process is fundamental in physics and engineering, as it helps in determining the net effect (resultant) when several forces or displacements are acting.

There are different methods to add vectors, but the most common are:
  • Graphical Method: This involves drawing vectors on a graph and using the head-to-tail method to find the resultant. This method provides a visual understanding but can be less precise.
  • Analytical Method: This method involves breaking vectors into components (using the x and y-axis) and then adding these components together. It offers greater precision and is generally more useful in calculations.
The exercise uses component addition to precisely find the resultant vector by calculating the sum of each vector's components.
Vector Components
Each vector can be broken down into its horizontal (x-axis) and vertical (y-axis) components. In our exercise, displacement vectors (\(\overrightarrow{\mathbf{A}}\), \(\overrightarrow{\mathbf{B}}\), \(\overrightarrow{\mathbf{C}}\), and \(\overrightarrow{\mathbf{D}}\)) are aligned along the cardinal directions, making it easy to express them in terms of components.

For instance:
  • \(\overrightarrow{\mathbf{A}} = (2.00, 0)\) km, representing 2 km east.
  • \(\overrightarrow{\mathbf{B}} = (0, 3.75)\) km, representing 3.75 km north.
  • \(\overrightarrow{\mathbf{C}} = (-2.50, 0)\) km, pointing 2.5 km west.
  • \(\overrightarrow{\mathbf{D}} = (0, -3.00)\) km, indicating 3 km south.
Breaking vectors into components simplifies calculations. When vectors are aligned at angles, trigonometry (using sine and cosine) can help determine their components.

By comparing only x-components together and only y-components together, we can easily sum values to prepare for finding a resultant vector.
Resultant Vector
The resultant vector is the single vector that has the same effect as the combination of the original vectors. It's essentially the sum of all vectors in the system, representing the overall displacement or force.

In the problem at hand, when we sum the components of all given vectors, we find (\(\overrightarrow{\mathbf{R}} = (-0.50, 0.75)\)) km.This means the resultant displacement is 0.50 km west and 0.75 km north.

Calculating the resultant vector is crucial in many real-world applications. Engineers use this concept to design structures that can withstand certain forces, while navigators use it to plan the most efficient travel routes.

The resultant vector not only tells us the effective direction and magnitude but also how vectors interact with each other in different planes.
Vector Magnitude and Direction
Once we have the resultant vector from vector addition, determining its magnitude and direction is key. These quantities tell us 'how much' and 'in which direction'.

The magnitude of a vector is calculated using the Pythagorean Theorem for its components. So for (\(\overrightarrow{\mathbf{R}}\)), we compute:\[|\overrightarrow{\mathbf{R}}| = \sqrt{(-0.50)^2 + (0.75)^2} \approx 0.90 \text{ km}\]This represents the overall length or distance of the displacement.

The direction is found using trigonometric functions like tangent, which compares the ratio of y-component to x-component.The angle \(\theta\) with respect to the west is given by:\[\theta = \tan^{-1}\left( \frac{0.75}{0.50} \right) \approx 56.31^\circ \text{ north of west}\]Understanding vector magnitude and direction helps in determining the exact course and effectiveness of the resultant vector in practical situations, like navigation and physics experiments.

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Most popular questions from this chapter

An ocean liner leaves New York City and travels \(18.0^{\circ}\) north of east for \(155 \mathrm{km}\). How far east and how far north has it gone? In other words, what are the magnitudes of the components of the ship's displacement vector in the directions (a) due east and (b) due north?

A person is standing at the edge of the water and looking out at the ocean (see the drawing). The height of the person's eyes above the water is \(h=1.6 \mathrm{m},\) and the radius of the earth is \(R=6.38 \times 10^{6} \mathrm{m}\) (a) How far is it to the horizon? In other words, what is the distance \(d\) from the person's eyes to the horizon? (Note: At the horizon the angle between the line of sight and the radius of the earth is \(90^{\circ} .\)) (b) Express this distance in miles.

Two bicyclists, starting at the same place, are riding toward the same campground by two different routes. One cyclist rides \(1080 \mathrm{m}\) due east and then turns due north and travels another \(1430 \mathrm{m}\) before reaching the campground. The second cyclist starts out by heading due north for \(1950 \mathrm{m}\) and then turns and heads directly toward the campground. (a) At the turning point, how far is the second cyclist from the campground? (b) In what direction (measured relative to due east) must the second cyclist head during the last part of the trip?

The route followed by a hiker consists of three displacement vectors \(\overrightarrow{\mathbf{A}}, \overrightarrow{\mathbf{B}},\) and \(\overrightarrow{\mathrm{C}} .\) Vector \(\overrightarrow{\mathbf{A}}\) is along a measured trail and is \(1550 \mathrm{m}\) in a direction \(25.0^{\circ}\) north of east. Vector \(\overrightarrow{\mathbf{B}}\) is not along a measured trail, but the hiker uses a compass and knows that the direction is \(41.0^{\circ}\) east of south. Similarly, the direction of vector \(\overrightarrow{\mathbf{C}}\) is \(35.0^{\circ}\) north of west. The hiker ends up back where she started. Therefore, it follows that the resultant displacement is zero, or \(\overrightarrow{\mathbf{A}}+\overrightarrow{\mathbf{B}}+\overrightarrow{\mathbf{C}}=0 .\) Find the magnitudes of (a) vector \(\overrightarrow{\mathbf{B}}\) and \((\mathrm{b})\) vector \(\overrightarrow{\mathbf{C}}\).

Bicyclists in the Tour de France reach speeds of 34.0 miles per hour \((\mathrm{mi} / \mathrm{h})\) on flat sections of the road. What is this speed in (a) kilometers per hour \((\mathrm{km} / \mathrm{h})\) and \((\mathrm{b})\) meters per second \((\mathrm{m} / \mathrm{s}) ?\)

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