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Vector \(\overrightarrow{\mathbf{A}}\) points along the \(+y\) axis and has a magnitude of 100.0 units. Vector \(\overrightarrow{\mathbf{B}}\) points at an angle of \(60.0^{\circ}\) above the \(+x\) axis and has a magnitude of 200.0 units. Vector \(\overrightarrow{\mathbf{C}}\) points along the \(+x\) axis and has a magnitude of 150.0 units. Which vector has (a) the largest \(x\) component and (b) the largest y component?

Short Answer

Expert verified
(a) Vector C has the largest x component. (b) Vector B has the largest y component.

Step by step solution

01

Identify Vectors and Their Components

Vector \(\overrightarrow{\mathbf{A}}\) lies along the \(+y\) axis, so it has no \(x\) component and its \(y\) component is 100.0 units: \(\overrightarrow{\mathbf{A}} = (0, 100)\). Vector \(\overrightarrow{\mathbf{B}}\) is at a \(60^{\circ}\) angle from the \(+x\) axis. Its components are given by: \(B_x = 200.0 \cos(60^{\circ})\) and \(B_y = 200.0 \sin(60^{\circ})\). Vector \(\overrightarrow{\mathbf{C}}\) lies along the \(+x\) axis, so its \(x\) component is 150.0 units and its \(y\) component is 0: \(\overrightarrow{\mathbf{C}} = (150, 0)\).
02

Calculate Components of Vector B

Compute the \(x\) and \(y\) components of Vector \(\overrightarrow{\mathbf{B}}\). Using trigonometric functions: \(B_x = 200.0 \cos(60^{\circ}) = 200.0 \times 0.5 = 100.0\) units and \(B_y = 200.0 \sin(60^{\circ}) = 200.0 \times \frac{\sqrt{3}}{2} \approx 173.2\) units. Therefore, \(\overrightarrow{\mathbf{B}} = (100, 173.2)\).
03

Compare X Components

Now compare the \(x\) components of \(\overrightarrow{\mathbf{A}}\), \(\overrightarrow{\mathbf{B}}\), and \(\overrightarrow{\mathbf{C}}\). We have: \(A_x = 0\), \(B_x = 100.0\), and \(C_x = 150.0\). The largest is \(C_x = 150.0\) units.
04

Compare Y Components

Now compare the \(y\) components of \(\overrightarrow{\mathbf{A}}\), \(\overrightarrow{\mathbf{B}}\), and \(\overrightarrow{\mathbf{C}}\). We have: \(A_y = 100.0\), \(B_y = 173.2\), and \(C_y = 0\). The largest is \(B_y = 173.2\) units.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Trigonometry in Physics
Understanding trigonometry is key when dealing with vectors in physics. Trigonometry helps us break down vectors into their components. A vector can have direction and magnitude. When a vector makes an angle with one of the axes, we use sine and cosine functions to determine its components.

For instance, in the exercise, Vector \(\overrightarrow{\mathbf{B}}\) is inclined at an angle of \(60^{\circ}\) with the +x axis. Trigonometry tells us that:
  • The \(x\)-component can be calculated using the cosine function: \(B_x = 200.0 \cos(60^{\circ})\).
  • The \(y\)-component is found using the sine function: \(B_y = 200.0 \sin(60^{\circ})\).
Why sine and cosine? Because \(\cos(\theta)\) gives us the adjacent side (which aligns with x-axis), and \(\sin(\theta)\) gives us the opposite side (aligning with y-axis) of a right-angled triangle. This systematic breakdown helps in solving vector-related problems.
Vector Addition
Vector addition allows us to find resultant vectors by summing multiple vectors' components. Each component (x and y) is treated separately.

For example:
  • If we have Vector \(\overrightarrow{\mathbf{A}} = (0, 100)\)
  • and Vector \(\overrightarrow{\mathbf{C}} = (150, 0)\)
  • and Vector \(\overrightarrow{\mathbf{B}} = (100, 173.2)\)
Their resultant vector in terms of x-component: \(0 + 150 + 100 = 250 \) units.

In terms of the y-component: \(100 + 0 + 173.2 \approx 273.2\) units. Such vector addition is crucial when determining overall force, velocity, or any vector quantity in physics, especially in multi-dimensional problems.
Angle Measurement in Physics
Angles in physics play a pivotal role in understanding vector directions and components. The concept of measuring angles helps to determine how a vector is oriented in space.

Angles are usually measured from a reference direction, often the +x-axis, in a counter-clockwise direction. This helps standardize the measurement, ensuring vectors are described consistently.
  • For Vector \(\overrightarrow{\mathbf{B}}\), the angle of \(60^{\circ}\) tells us where it points relative to the +x-axis.
  • This angle measurement aids in precisely calculating the vector's components using trigonometric identities (like sine and cosine).
Understanding angle measurement is essential for interpreting vector direction and using vectors in calculations, be it in simple mechanics or more complex physics topics.

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