/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Suppose a mass is moving in a ci... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose a mass is moving in a circular path on a frictionless table as shown in figure. In the Earth's frame of reference, there is no centrifugal force pulling the mass away from the centre of rotation, yet there is a very real force stretching the string attaching the mass to the nail. Using concepts related to centripetal force and Newton's third law, explain what force stretches the string, identifying its physical origin.

Short Answer

Expert verified
The string stretches due to the tension created by the inertia of the mass, which is an effect of the mass's tendency to move in a straight line at a constant velocity (Newton's first law). Newton's third law explains that the mass exerts an equal and opposite outward force on the string in reaction to the centripetal force exerted by the string.

Step by step solution

01

Understanding Centripetal Force

Centripetal force is the net force causing the uniform circular motion of an object. It is directed towards the center of the circular path. The term 'centripetal' means 'seeking the center' or 'towards the center'. For an object moving in a circular path on a frictionless table, the centripetal force needed to keep the object in motion is provided by the tension in the string.
02

Identifying the Origin of the Force

The physical origin of the tension in the string is the inertia of the mass. According to Newton's first law, an object in motion wants to continue in a straight line at constant velocity. The string attached to the nail prevents the mass from moving in a straight line, forcing it into circular motion. This causes the string to stretch, thus exerting tension which acts as the centripetal force.
03

Application of Newton's Third Law

According to Newton's third law, for every action, there is an equal and opposite reaction. While the string pulls on the mass toward the center of the circle (providing the centripetal force), the mass pulls on the string outward with an equal force. This outward force is what stretches the string. However, it is important to understand that this outward force is not a 'centrifugal force' but rather the reaction force to the centripetal force exerted by the string.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Circular Motion
When an object moves in a circle at a steady speed, it is undergoing what we call uniform circular motion. This kind of motion is fascinating because, although the speed of the object remains constant, its direction is continuously changing.

Imagine a ball whirling around on a string—every point on its path is a delicate balance of motion and force. The force that keeps the ball moving in a circle and not flying off in a straight line is called centripetal force. This force is always directed towards the center of the circle. Now, if we cut the string, the ball would move in a straight line at the point of release. This is a clear demonstration of inertia—the tendency of an object to resist changes to its state of motion, which we'll dive deeper into later in this article.
Newton's Third Law
Sir Isaac Newton's third law of motion tells us that for every action, there's an equal and opposite reaction. This law is beautifully exemplified in the scenario of an object in uniform circular motion.

Consider a stone tied to a string and spun around; the stone applies a force on the string that is directed outward, which might make us think there's a force pushing the stone away from the center. This, however, is not a real force acting on the mass but rather the reaction to the centripetal force—our stone pulling on the string as the string pulls inwards on it. This is the law in action, the action being the pull of the string on the stone, and the reaction being the stone's pull on the string.
Tension in the String
The term 'tension' might evoke an image of two people pulling on opposite ends of a rope. In physics, tension is the force conducted through a string, rope, or wire, when it is pulled tight by forces acting from opposite ends.

In the context of our mass spinning on a frictionless table, tension is the hero keeping our protagonist—the spinning mass—on its circular track. The string exerts an inward force toward the nail at the center, which is the centripetal force needed for circular motion. In response, the mass 'tries' to continue in a straight path due to its inertia, stretching the string and thereby increasing the tension within it. This balance of forces is crucial for maintaining uniform circular motion.
Inertia
A cornerstone concept in physics is inertia—the resistance of any physical object to a change in its state of motion or rest. It's why we lean back when a vehicle starts moving and lurch forward when it stops suddenly.

In our circular motion scenario, inertia plays a key role. The mass, due to its inertia, strives to move in a straight line. This is where the tension in the string comes into play. The string, being attached to a fixed nail, forces the mass to deviate from its straight-line path and into a circular one. This interplay between inertia wanting to propel the mass straight and the string pulling it into a circle is what sets the scene for the beautiful dance of uniform circular motion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You are told that a basketball player spins the ball with an angular acceleration of \(100 \mathrm{rad} / \mathrm{s}^{2}\). (a) What is the ball's final angular velocity if the ball starts from rest and the acceleration lasts \(2.00 \mathrm{~s} ?\) (b) What is unreasonable about the result? (c) Which premises are unreasonable or inconsistent?

At takeoff, a commercial jet has a \(60.0 \mathrm{~m} / \mathrm{s}\) speed. Its tires have a diameter of \(0.850 \mathrm{~m}\). (a) At how many rev/min are the tires rotating? (b) What is the centripetal acceleration at the edge of the tire? (c) With what force must a determined \(1.00 \times 10^{-15} \mathrm{~kg}\) bacterium cling to the rim? (d) Take the ratio of this force to the bacterium's weight.

Olympic ice skaters are able to spin at about \(5 \mathrm{rev} / \mathrm{s}\). (a) What is their angular velocity in radians per second? (b) What is the centripetal acceleration of the skater's nose if it is \(0.120 \mathrm{~m}\) from the axis of rotation? (c) An exceptional skater named Dick Button was able to spin much faster in the 1950 s than anyone since-at about 9 rev/s. What was the centripetal acceleration of the tip of his nose, assuming it is at \(0.120 \mathrm{~m}\) radius? (d) Comment on the magnitudes of the accelerations found. It is reputed that Button ruptured small blood vessels during his spins.

In circular motion, a tangential acceleration can change the magnitude of the velocity but not its direction. Explain your answer.

Taking the age of Earth to be about \(4 \times 10^{9}\) years and assuming its orbital radius of \(1.5 \times 10^{11} \mathrm{~m}\) has not changed and is circular, calculate the approximate total distance Earth has traveled since its birth (in a frame of reference stationary with respect to the Sun)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.