/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 One hazard of space travel is de... [FREE SOLUTION] | 91Ó°ÊÓ

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One hazard of space travel is debris left by previous missions. There are several thousand objects orbiting Earth that are large enough to be detected by radar, but there are far greater numbers of very small objects, such as flakes of paint. Calculate the force exerted by a \(0.100\) -mg chip of paint that strikes a spacecraft window at a relative speed of \(4.00 \times 10^{3} \mathrm{~m} / \mathrm{s}\), given the collision lasts \(6.00 \times 10^{-8} \mathrm{~s}\)

Short Answer

Expert verified
The force exerted by the paint chip is 6.67 x 10^{3} N.

Step by step solution

01

- Convert mass to kg

First, we need to convert the mass of the paint chip from milligrams to kilograms, as the standard unit of mass in physics is the kilogram. We have that 1 mg is equivalent to 1x10^{-6} kilograms. So a 0.100 mg mass is 0.100 x 10^{-6} kg, or 1.00 x 10^{-7} kg.
02

- Calculate the change in momentum

For the paint chip hitting the window, the momentum changes from its initial value to zero since we assume it sticks to the window and stops moving relative to the spacecraft. Momentum is mass times velocity, so the change in momentum (which is also the impulse) is equal to mass times the change in velocity. For the paint chip, this is (1.00 x 10^{-7} kg) * (4.00 x 10^{3} m/s). Therefore, the change in momentum is 4.00 x 10^{-4} kg*m/s.
03

- Calculate the average force

The force exerted on the window by the paint chip can be found by using the formula for impulse, which relates force, time, and change in momentum: impulse = force x time. Rearranging for force gives force = impulse / time. The impulse is the change in momentum which is 4.00 x 10^{-4} kg*m/s and the time is 6.00 x 10^{-8} s. Therefore, the force is (4.00 x 10^{-4} kg*m/s) / (6.00 x 10^{-8} s), which equals 6.67 x 10^{3} N.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Change Calculation
Understanding the concept of a momentum change is crucial in physics, particularly in analyzing collisions. Momentum, a measure of a body's tendency to continue moving with the same velocity, is calculated as the product of an object's mass and its velocity, represented by the equation: \( \text{{momentum}} = \text{{mass}} \times \text{{velocity}} \). In scenarios like space debris collisions, computing the change in momentum helps in determining the impact of the collision.

For an object like a small paint chip hitting a spacecraft window, we assume the object comes to a halt upon impact. The change in momentum is then the difference between the initial momentum before the impact and the final momentum, which is zero since the final velocity is zero after sticking to the window. In the given problem, a 0.100-mg paint chip strikes at 4000 m/s and stops, thus, the momentum change is represented as \( \text{{momentum change}} = \text{{mass}} \times \text{{velocity change}} \).
Impulse-Force Relationship
The concept of impulse in physics is intimately linked to the idea of momentum. Impulse is defined as the change in momentum of an object when a force is applied over a period of time. The impulse-force relationship is described by the equation: \( \text{{impulse}} = \text{{force}} \times \text{{time}} \).

Understanding Impulse


When a force acts on a body for a certain time, it changes the body's velocity and thus its momentum. Impulse is both a measure of the force and the duration over which it acts. In our exercise with the paint chip and spacecraft window, the time duration is extremely short at \(6.00 \times 10^{-8} \) seconds.

This relationship allows us to then solve for the force if we know the impulse ((change in momentum) and the time over which the collision happens, leading us to understand how even a tiny chip of paint can exert a significant force on impact due to the high relative speeds involved in space.
Unit Conversion Physics
In physics problems, particularly those involving equations and calculations, it's vital to start off with consistent units. Most physical equations require mass to be in kilograms when working within the International System of Units (SI). However, measurements are often not provided in these units, necessitating conversion.

Why Convert Units?


Converting units ensures that the calculations are accurate and that the outcome is in the desired unit of measure. For example, in the space debris problem, we're given the mass in milligrams but require it to be in kilograms for computing momentum change.

Unit conversion for mass from milligrams to kilograms involves multiplying the mass value by \(10^{-6}\). Through correct conversion and ensuring uniform units across all parameters used in a physics equation, we prevent errors in our final results and obtain an accurate assessment of quantities such as force in problems like the one discussed.

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Most popular questions from this chapter

(a) What is the mass of a large ship that has a momentum of \(1.60 \times 10^{9} \mathrm{~kg} \cdot \mathrm{m} / \mathrm{s}\), when the ship is moving at a speed of \(48.0 \mathrm{~km} / \mathrm{h}\) ? (b) Compare the ship's momentum to the momentum of a 1100-kg artillery shell fired at a speed of \(1200 \mathrm{~m} / \mathrm{s}\)

Under what circumstances is momentum conserved?

(a) During an ice skating performance, an initially motionless \(80.0-\mathrm{kg}\) clown throws a fake barbell away. The clown's ice skates allow her to recoil frictionlessly. If the clown recoils with a velocity of \(0.500 \mathrm{~m} / \mathrm{s}\) and the barbell is thrown with a velocity of \(10.0 \mathrm{~m} / \mathrm{s}\), what is the mass of the barbell? (b) How much kinetic energy is gained by this maneuver? (c) Where does the kinetic energy come from?

Suppose a clay model of a koala bear has a mass of \(0.200 \mathrm{~kg}\) and slides on ice at a speed of \(0.750 \mathrm{~m} / \mathrm{s}\). It runs into another clay model, which is initially motionless and has a mass of \(0.350 \mathrm{~kg}\). Both being soft clay, they naturally stick together. What is their final velocity?

Two football players collide head-on in midair while trying to catch a thrown football. The first player is \(95.0 \mathrm{~kg}\) and has an initial velocity of \(6.00 \mathrm{~m} / \mathrm{s}\), while the second player is \(115 \mathrm{~kg}\) and has an initial velocity of \(-3.50 \mathrm{~m} / \mathrm{s}\). What is their velocity just after impact if they cling together?

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