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A school bus has a mass of \(18,200 \mathrm{~kg}\). The bus moves at \(12.5 \mathrm{~m} / \mathrm{s}\). How fast must a \(0.142-\mathrm{kg}\) baseball move in order to have the same momentum as the bus?

Short Answer

Expert verified
The baseball must move at approximately 1,602,113.38 m/s to have the same momentum as the bus.

Step by step solution

01

Understand Momentum

Momentum is a measure of the mass of an object in motion, and it is represented by the product of mass and velocity. The formula for momentum (p) is \( p = m \cdot v \), where \( m \) is mass and \( v \) is velocity.
02

Calculate the Bus's Momentum

To find the momentum of the bus, we will multiply its mass by its velocity. Using the formula \( p = m \cdot v \), where \( m = 18,200 \text{ kg} \) and \( v = 12.5 \text{ m/s} \), we have:\[ p = 18,200 \times 12.5 = 227,500 \text{ kg m/s} \]
03

Set Equal Momentum for the Baseball

We want the baseball to have the same momentum as the bus. So, set \( p_{baseball} = p_{bus} \). We know the mass of the baseball is \( 0.142 \text{ kg} \), so the equation becomes:\[ 0.142 \cdot v_{baseball} = 227,500 \]
04

Solve for the Baseball's Velocity

To find the velocity of the baseball, divide both sides of the equation by 0.142:\[ v_{baseball} = \frac{227,500}{0.142} \approx 1,602,113.38 \text{ m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass and Velocity
Understanding mass and velocity is essential when dealing with momentum. Mass refers to how much matter an object contains. It is measured in kilograms (kg). Meanwhile, velocity describes how fast an object moves in a particular direction and is measured in meters per second (m/s). While speed tells you how fast something is moving, velocity provides direction as well. When thinking about a school bus, its mass greatly impacts its momentum because it takes a lot of force to move such a large mass. Conversely, a smaller object like a baseball depends more heavily on its velocity to achieve the same momentum as a larger object. In the original exercise, noting the mass and velocity helps students understand how changes in one can alter the outcome of momentum. A heavier object needs less velocity to achieve the same momentum as a lighter object. Understanding this relationship lays the foundation for momentum calculation.
Momentum Calculation
Momentum is a fundamental concept in physics that combines mass and velocity. It is represented as the formula: \( p = m \cdot v \). This equation means that momentum (p) is the product of an object's mass (m) and its velocity (v). To calculate the momentum of an object:
  • Identify the object's mass.
  • Find its velocity.
  • Multiply these two values together.
In the exercise, we calculated the bus's momentum using its mass of 18,200 kg and velocity of 12.5 m/s. We multiplied these to find a momentum of 227,500 kg m/s. This method gives a quantitative description of how much motion an object carries. This calculation also illustrates how you can compare different objects' momentum by evening out one variable. By setting the momentum of the baseball equal to that of the bus, we learn how velocity compensates for a much smaller mass to achieve the same momentum.
Physics Problem Solving
Solving physics problems often involves understanding core concepts and systematically applying formulas. In this problem, the goal was to determine the velocity a baseball needs to match the momentum of a large school bus. To do this, students first determined the momentum of the school bus using the given mass and velocity. After understanding momentum and calculating it for the bus, students realized that the baseball needed an equal momentum. The problem-solving process involved setting the baseball's momentum equal to the bus's momentum, allowing for an equation where its velocity could be solved. To find the required velocity for the baseball:
  • Set the momentum formula for the baseball equal to the bus's momentum.
  • Use the mass of the baseball and solve for its velocity.
  • Divide the known momentum by the mass of the baseball to find its velocity.
This systematic approach ensures accuracy and understanding by using consistent physics principles. Approaching problems step-by-step builds confidence and clears up complex topics for students.

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Most popular questions from this chapter

An 82-kg football player is running in the positive \(y\) direction with a speed of \(3.1 \mathrm{~m} / \mathrm{s}\). A \(96-\mathrm{kg}\) player from the opposing team is running in the negative \(x\) direction with a speed of \(2.4 \mathrm{~m} / \mathrm{s}\) when the tackle is made. Assuming that the players remain together, what is their speed immediately after the tackle?

Two curling stones collide on an ice rink. Stone 1 has a mass of \(16 \mathrm{~kg}\) and an initial velocity of \(1.5 \mathrm{~m} / \mathrm{s}\) to the north. Stone 2 was at rest initially. The stones collide dead center, giving stone 2 a final velocity of \(0.69 \mathrm{~m} / \mathrm{s}\) to the north. (a) What was the mass of stone 2? (b) What was the final velocity of stone 1 ?

A \(732-\mathrm{kg}\) car stopped at an intersection is rear-ended by a \(1720-\mathrm{kg}\) truck moving with a speed of \(15.5 \mathrm{~m} / \mathrm{s}\). If the car was in neutral and its brakes were off, so the collision is approximately elastic, find the final speed of both vehicles after the collision.

Two cars collide at an intersection. If the cars do not stick together, can you conclude that the collision was elastic? Explain.

At a busy intersection a \(1540-\mathrm{kg}\) car traveling west with a speed of \(12 \mathrm{~m} / \mathrm{s}\) collides head-on with a minivan traveling east with a speed of \(9.4 \mathrm{~m} / \mathrm{s}\). The cars stick together and move with an initial velocity of \(1.5 \mathrm{~m} / \mathrm{s}\) to the east after the collision. What is the mass of the minivan?

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