/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 139 Think \& Calculate A sled sl... [FREE SOLUTION] | 91Ó°ÊÓ

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Think \& Calculate A sled slides without friction down a small, ice-covered hill. If the sled starts from rest at the top of the hill, its speed at the bottom is \(7.50 \mathrm{~m} / \mathrm{s}\). (a) On a second run, the sled starts with a speed of \(1.50 \mathrm{~m} / \mathrm{s}\) at the top. When it reaches the bottom of the hill, is its speed \(9.00 \mathrm{~m} / \mathrm{s}\), more than \(9.00 \mathrm{~m} / \mathrm{s}\), or less than \(9.00 \mathrm{~m} / \mathrm{s}\) ? Explain. (b) Find the speed of the sled at the bottom of the hill after the second run.

Short Answer

Expert verified
The speed is less than \(9.00 \, m/s\); it is approximately \(7.65 \, m/s\).

Step by step solution

01

Understand the Problem

The sled initially slides down a hill without friction. In the first scenario, it starts from rest and achieves a speed of \(7.50 \ m/s\) at the bottom. In the second scenario, it starts with a speed of \(1.50 \ m/s\), and we need to determine if the speed at the bottom is \(9.00 \, m/s\), more, or less, and then find that speed.
02

Utilize Conservation of Energy

Since there is no friction, mechanical energy is conserved. Thus, the potential energy at the top converts into kinetic energy at the bottom. For the first scenario:\[\frac{1}{2} m v_1^2 = mgh = \frac{1}{2} m (7.50)^2\]The term \(mgh\) represents the gravitational potential energy at the top, and \(v_1 = 7.50 \, m/s\) is the speed at the bottom.
03

Analyze the Second Run

In the second scenario, the sled has an initial kinetic energy due to the speed \(v_0 = 1.50 \, m/s\). Total mechanical energy at the top:\[\frac{1}{2} m v_0^2 + mgh\]And at the bottom:\[\frac{1}{2} m v_2^2\]Since energy is conserved:\[\frac{1}{2} m v_0^2 + mgh = \frac{1}{2} m v_2^2\]
04

Equate and Solve for Speed at the Bottom

Substitute the known values and solve for \(v_2\):\[\frac{1}{2} (1.50)^2 + \frac{1}{2} (7.50)^2 = \frac{1}{2} v_2^2\]Simplify and solve:\[\frac{1}{2} \, m (1.50^2 + 7.50^2) = \frac{1}{2} \, m v_2^2\]\[v_2^2 = 1.50^2 + 7.50^2\]\[v_2 = \sqrt{2.25 + 56.25} = \sqrt{58.50}\]\[v_2 \approx 7.65 \, m/s\]
05

Conclusion

Given the result of the calculation, the speed of the sled at the bottom is approximately \(7.65 \, m/s\), which is less than \(9.00 \, m/s\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy
Kinetic energy is a fundamental concept in physics that relates to the energy an object possesses due to its motion. It is mathematically expressed as \( KE = \frac{1}{2} m v^2 \), where \( m \) represents the mass of the object and \( v \) is its velocity. Hence, the faster an object moves or the more massive it is, the more kinetic energy it has.
This energy is essential in analyzing situations where motion is involved, like the case of our sled sliding down the hill. In both scenarios discussed, the sled gains kinetic energy as it descends, with its initial potential energy converting into kinetic energy, allowing it to move faster. The equation reveals the key relationship between speed and kinetic energy, demonstrating that a slight increase in speed results in a significant increase in kinetic energy, thanks to the squaring of velocity.
In the exercise, we see that even with an initial push (not starting from rest), the sled achieves a specific speed due to the conservation of energy, which is fully explained using its kinetic energy changes.
Potential Energy
Potential energy refers to the energy stored in an object due to its position relative to other objects, stress within itself, its electric charge, or other factors. The most common form is gravitational potential energy, which can be expressed as \( PE = mgh \), where \( m \) is mass, \( g \) is the acceleration due to gravity, and \( h \) is the height above a reference point.
This concept is crucial in understanding how energy is transformed in scenarios like the sled on the hill. At the very top, the sled has maximum potential energy due to its height. As it slides down, this potential energy decreases and is converted into kinetic energy, increasing the sled's speed.
In our exercise, the potential energy at the top of the hill in both scenarios plays a significant role. For the sled starting from rest, all of its initial energy is potential, which fully converts to kinetic at the bottom. Meanwhile, when starting at a velocity, part of this potential energy combines with the initial kinetic energy to determine its speed at the end of the descent.
Mechanical Energy
Mechanical energy is the sum of both kinetic and potential energy in a system. It is expressed as \( ME = KE + PE \). This conserved energy is a pivotal part of understanding systems like a sled sliding without friction.
In an isolated system with no energy loss, like frictionless sliding, the total mechanical energy remains constant, allowing us to predict the behavior of moving objects. The conservation of mechanical energy means that the decrease in potential energy results in an identical increase in kinetic energy, maintaining the energy balance of the system.
This principle was applied in our exercise to solve for the speed of the sled at the hill's bottom. For both scenarios, we calculated the sled's mechanical energy at the top and equated it to the kinetic energy at the bottom. By doing so, we demonstrated that, when starting with extra initial kinetic energy, the sled ultimately attained a slightly increased speed at the bottom, despite not reaching 9.00 m/s.

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Most popular questions from this chapter

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