/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 128 A small airplane tows a glider a... [FREE SOLUTION] | 91Ó°ÊÓ

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A small airplane tows a glider at constant speed and altitude. If the plane does \(2.00 \times 10^{5} \mathrm{~J}\) of work to tow the glider \(145 \mathrm{~m}\) and the tension in the tow rope is \(2560 \mathrm{~N}\), what is the angle between the tow rope and the horizontal?

Short Answer

Expert verified
The angle between the tow rope and the horizontal is approximately 57.46 degrees.

Step by step solution

01

Understand the Relationship Between Work, Force, and Distance

Work is given by the formula \( W = F \, d \, \cos(\theta) \), where \( W \) is the work done, \( F \) is the force applied, \( d \) is the distance moved in the direction of the force, and \( \theta \) is the angle between the force and the direction of motion. We are asked to find this angle \( \theta \).
02

Rearrange the Formula to Solve for Cosine of the Angle

To find \( \cos(\theta) \), rearrange the work formula: \( \cos(\theta) = \frac{W}{F \, d} \).
03

Substitute the Known Values Into the Equation

Substitute the given values into the rearranged formula: \( \cos(\theta) = \frac{2.00 \times 10^5 \text{ J}}{2560 \text{ N} \times 145 \text{ m}} \).
04

Calculate Cosine of Angle

Calculating the right side of the equation gives \( \cos(\theta) = \frac{2.00 \times 10^5}{2560 \times 145} = \frac{2.00 \times 10^5}{371200} \approx 0.538 \).
05

Find the Angle Using the Arccosine Function

To find \( \theta \), use the arccosine (inverse cosine) function: \( \theta = \arccos(0.538) \). Calculate this using a calculator to obtain \( \theta \approx 57.46^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force
Force is a fundamental concept in physics that describes an interaction that changes the motion of an object. In simple terms, it's what causes an object to accelerate. The unit for force is the newton (N).
When dealing with forces in physics problems, it’s crucial to understand that force often acts in a particular direction. This directional nature of force is why we must consider angles when force is applied in real-world situations.

In the context of work and energy, the force can be calculated or used in equations involving work. The equation \( W = F \cdot d \cdot \cos(\theta) \) involves straight-line motion where force \( F \) is applied at an angle \( \theta \) to the direction of motion.
  • \( W \): Work done by the force, measured in joules (J).
  • \( d \): The distance over which the force is applied.
  • \( \theta \): The angle between the force applied and the direction of motion.
  • \( \cos(\theta) \): The cosine of this angle accounts for the component of the force that does the work.
Understanding force and how it interacts with angles will help solve problems involving work, like towing a glider with a rope.
Angle of Inclination
The angle of inclination often appears in physics problems involving forces that are not directly aligned with the motion's direction. It represents the angle \( \theta \) between the direction of the force applied and the path it follows.

This angle is crucial when determining how much of the force actually contributes to doing work. Because forces can be applied at an angle, not all the force may be used to move the object in the desired direction. Calculating this angle accurately involves trigonometric functions.

In practice:
  • Use the formula \( \cos(\theta) = \frac{W}{F \cdot d} \) to find the cosine of the angle when work \( W \), force \( F \), and distance \( d \) are known.
  • Apply the arccosine function \( \theta = \arccos(x) \) to determine the angle \( \theta \), where \( x \) is the result of the cosine calculation.
  • Accurate measurements ensure that calculations involving inclined force give correct answers.
The concept of angle of inclination is fundamental in assessing how effectively a force moves an object along its intended path.
Cosine Function
The cosine function is one of the fundamental trigonometric functions in mathematics, used extensively in geometry, physics, and engineering. In geometry, the cosine of an angle in a right triangle is the ratio of the adjacent side's length to the hypotenuse's length, denoted by \( \cos(\theta) \).

In the context of work and force, the cosine function helps to determine what portion of a force contributes directly to doing work when a force is applied at an angle. Here's how it comes into play:
  • The work done by the force is dependent on the direction of the force in relation to the displacement.
  • \( \cos(\theta) \) adjusts the force's effective component parallel to the displacement direction.
  • If \( \theta = 0 \), the full force is in the direction of motion, and \( \cos(\theta) = 1 \).
  • If \( \theta = 90^\circ \), the force does no work in the direction of motion, and \( \cos(\theta) = 0 \).
By calculating \( \cos(\theta) \), you can find out how much of the force contributes to the work, which is useful in constructing solutions to applied force problems in physics.

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Most popular questions from this chapter

Think \& Calculate A pitcher accelerates a \(0.14\)-kg hardball from rest to \(25.5 \mathrm{~m} / \mathrm{s}\) in \(0.075 \mathrm{~s}\). (a) How much work does the pitcher do on the ball? (b) What is the pitcher's power output during the pitch? (c) Suppose the ball reaches \(25.5 \mathrm{~m} / \mathrm{s}\) in less than \(0.075 \mathrm{~s}\). Is the power produced by the pitcher in this case more than, less than, or the same as the power found in part (b)? Explain.

Apply How does the kinetic energy of an object change if its speed doubles? Triples?

Predict \& Explain The work required to accelerate a car from 0 to \(50 \mathrm{~km} / \mathrm{h}\) is \(W\). (a) Is the work required to accelerate the car from \(50 \mathrm{~km} / \mathrm{h}\) to \(150 \mathrm{~km} / \mathrm{h}\) equal to \(2 W, 3 W, 8 W\), or \(9 W ?\) (b) Choose the best explanation from among the following: A. The work to accelerate the car depends on the speed squared. B. The final speed is three times the speed that was produced by the work \(W\). C. The increase in speed from \(50 \mathrm{~km} / \mathrm{h}\) to \(150 \mathrm{~km} / \mathrm{h}\) is twice the increase in speed from 0 to \(50 \mathrm{~km} / \mathrm{h}\).

Think \& Calculate To clean a floor, a janitor pushes on a mop handle with a force of \(43 \mathrm{~N}\). (a) If the mop handle is at an angle of \(55^{\circ}\) above the horizontal, how much work is required to push the mop \(0.50 \mathrm{~m}\) ? (b) If the angle the mop handle makes with the horizontal is increased to \(65^{\circ}\), does the work done by the janitor increase, decrease, or stay the same? Explain.

Think \& Calculate A \(1100-\mathrm{kg}\) car is coasting on a horizontal road with a speed of \(19 \mathrm{~m} / \mathrm{s}\). After passing over an unpaved, sandy stretch \(32 \mathrm{~m}\) long, the car's speed has decreased to \(12 \mathrm{~m} / \mathrm{s}\). (a) Was the net work done on the car positive, negative, or zero? Explain. (b) Find the magnitude of the average net force on the car in the sandy section of the road.

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