Chapter 4: Problem 64
A vector \(\overrightarrow{\mathrm{A}}\) has a magnitude of \(40.0 \mathrm{~m}\) and points in a direction \(20.0^{\circ}\) below the positive \(x\) axis. A second vector, \(\overrightarrow{\mathbf{B}}\), has a magnitude of \(75.0 \mathrm{~m}\) and points in a direction \(50.0^{\circ}\) above the positive \(x\) axis. Sketch the vectors \(\vec{A}, \vec{B}\), and \(\vec{C}=\vec{A}+\vec{B}\).
Short Answer
Step by step solution
Decompose Vector A into Components
Decompose Vector B into Components
Find Components of Vector C
Calculate Magnitude and Direction of Vector C
Sketch the Vectors
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnitude
To calculate the magnitude of a vector, we use the Pythagorean theorem for components on the xy-plane:
- For vector \(\overrightarrow{\mathrm{C}}\), we find it by \[ C = \sqrt{C_x^2 + C_y^2} \approx 96.00 \mathrm{~m} \]
It's like finding the hypotenuse of a right-angled triangle. This is a universal method for any vector if components are known.
Remember, the magnitude is always a non-negative number, as it represents a length. Even if the vector points in a negative direction, like below the x-axis, the magnitude remains positive.
Direction
For example, the direction of vector \(\overrightarrow{\mathrm{A}}\) in the exercise is "20° below the positive x-axis," and \(\overrightarrow{\mathrm{B}}\) is "50° above the positive x-axis." These directions specify the orientation of each vector, allowing accurate representation in diagrams.
To determine the direction of a resultant vector, like \(\overrightarrow{\mathrm{C}}\), the tangent inverse function is handy:
- \[ \theta = \tan^{-1}\left(\frac{C_y}{C_x}\right) \approx 27.09^{\circ} \]
Direction, just like magnitude, is crucial for understanding how vectors interact or combine.
Component Vectors
For instance, vector \(\overrightarrow{\mathrm{A}}\) with a magnitude of 40.0 m can be split into components \(A_x\) and \(A_y\) using trigonometric functions:
- \( A_x = 40.0 \cdot \cos(-20.0^{\circ}) \)
- \( A_y = 40.0 \cdot \sin(-20.0^{\circ}) \)
- \( B_x = 75.0 \cdot \cos(50.0^{\circ}) \)
- \( B_y = 75.0 \cdot \sin(50.0^{\circ}) \)
These components allow for easier vector addition, as we simply sum the x-components together and the y-components together to find the resultant vector, \(\overrightarrow{\mathrm{C}}\). Components transform complex vector problems into simpler arithmetic, aiding in both calculation and conceptual understanding.