/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 Can a component of a vector be g... [FREE SOLUTION] | 91Ó°ÊÓ

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Can a component of a vector be greater than the vector's magnitude?

Short Answer

Expert verified
No, a component of a vector cannot be greater than the vector's magnitude.

Step by step solution

01

Understanding Vector Magnitude and Components

A vector has both magnitude and direction. The magnitude of a vector is a measure of its length, which can be computed using the Pythagorean theorem for its components. If a vector is represented as \( \vec{v} = (v_x, v_y) \), its magnitude \( \|\vec{v}\| \) is given by the formula \( \|\vec{v}\| = \sqrt{v_x^2 + v_y^2} \).
02

Analyzing Components vs. Magnitude

The components of a vector, \( v_x \) and \( v_y \), are the projections of the vector along the coordinate axes. These components are individually \( v_x = \|\vec{v}\| \cos \theta \) and \( v_y = \|\vec{v}\| \sin \theta \), where \( \theta \) is the angle the vector makes with the horizontal axis.
03

Applying Inequalities to Magnitude and Components

Since \( \cos \theta \) and \( \sin \theta \) are both always between \(-1\) and \(1\), each component of the vector is less than or equal to the magnitude of the vector. Therefore, neither \( v_x \) nor \( v_y \) can exceed \( \|\vec{v}\| \).
04

Conclusion Based on Analysis

From the relationship that each component is a result of multiplying the magnitude by a cosine or sine which is bound between \(-1\) and \(1\), it follows that the component of a vector cannot be greater than the magnitude of the vector.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
Vector components are crucial for understanding how vectors behave in a coordinate system. A vector in a plane can be expressed using its components along the coordinate axes. Let's break it down: imagine a vector as an arrow; this arrow can be represented in terms of how much it stretches along the horizontal axis ( \(v_x\)) and the vertical axis ( \(v_y\)).

Each component is a projection of the vector onto the respective axis:
  • The horizontal component ( \(v_x\)) shows how far the vector moves along the x-axis.
  • The vertical component ( \(v_y\)) reflects the vector's movement along the y-axis.
By separating the vector into these components, one can easily analyze and solve problems using the characteristics of these individual movements.
Pythagorean Theorem
The Pythagorean theorem is a foundational principle in geometry, particularly when calculating the magnitude of vectors. In the context of vectors, if you have a right triangle formed by the vector and its components, the Pythagorean theorem allows for calculating the vector's magnitude.

For a vector \(\vec{v} = (v_x, v_y)\), the magnitude \(\|\vec{v}\|\) is computed as:\[\|\vec{v}\| = \sqrt{v_x^2 + v_y^2}\]This equation shows that the magnitude or length of the vector is the hypotenuse of a right triangle with sides \(v_x\) and \(v_y\). This relationship makes it clear that the magnitude is always the longest side, meaning neither component can be greater than the magnitude itself.
Trigonometric Functions
Trigonometric functions, specifically sine and cosine, play a key role in determining vector components. When a vector is expressed in terms of its direction and magnitude, the angle \(\theta\) it makes with the horizontal axis helps in calculating its components.
  • The cosine of the angle (\(\cos \theta\)) helps determine the horizontal component \(v_x = \|\vec{v}\| \cos \theta\).
  • The sine of the angle (\(\sin \theta\)) is used to find the vertical component \(v_y = \|\vec{v}\| \sin \theta\).
These functions are bounded between -1 and 1, ensuring that the components' values stay within the limits defined by the vector's magnitude. Thus, these trigonometric functions efficiently translate a vector's direction and length into actionable horizontal and vertical movements.
Vector Analysis
Vector analysis involves dissecting a vector into its components and comprehending the relationships among these components, their magnitude, and direction. This analysis informs whether a vector component can ever be greater than the vector's magnitude itself.
  • Each component's value derives from a combination of both the vector's magnitude and a trigonometric function.
  • The mathematical properties of sine and cosine mean that when multiplied by any magnitude, the resulting component is inherently bound to be less than or equal to the magnitude.
Understanding these principles makes it clear why neither the horizontal nor the vertical component can exceed the vector's magnitude. It's like ensuring the sum of the squares of a right triangle's legs upholds the triangle's hypotenuse length, illustrating the interconnected structure of vectors, components, and trigonometry.

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Most popular questions from this chapter

Two divers run horizontally off the edge of a low cliff. Diver 2 runs with twice the speed of diver 1. (a) When the divers hit the water, is the horizontal distance covered by diver 2 twice as much as, four times as much as, or equal to the horizontal distance covered by diver 1? (b) Choose the best explanation from among the following: A. The drop time is the same for both divers. B. Drop distance depends on \(t^{2}\). C. All divers in free fall cover the same distance.

A softball is thrown from the origin of an \(x-y\) coordinate system with an initial speed of \(18 \mathrm{~m} / \mathrm{s}\) at an angle of \(35^{\circ}\) above the horizontal. (a) Find the \(x\) and \(y\) positions of the softball at the times \(t=0.50 \mathrm{~s}, 1.0 \mathrm{~s}, 1.5 \mathrm{~s}\), and \(2.0 \mathrm{~s}\). (b) Plot the results from part (a) on an \(x-y\) coordinate system, and sketch the parabolic curve that passes through them.

Which of the following shapes is seen in the path of a projectile: straight line, parabola, circle, ellipse, hyperbola?

An air traffic controller observes two airplanes approaching the airport. The displacement from the control tower to plane 1 is given by the vector \(\overrightarrow{\mathbf{A}}\), which has a magnitude of \(220 \mathrm{~km}\) and points in a direction \(32^{\circ}\) north of west. The displacement from the control tower to plane 2 is given by the vector \(\overrightarrow{\mathbf{B}}\), which has a magnitude of \(140 \mathrm{~km}\) and points \(65^{\circ}\) east of north. (a) Sketch the vectors \(\overrightarrow{\mathbf{A}},-\overrightarrow{\mathbf{B}}\), and \(\overrightarrow{\mathbf{D}}=\overrightarrow{\mathbf{A}}-\overrightarrow{\mathbf{B}}\). Notice that \(\overrightarrow{\mathbf{D}}\) is the displacement from plane 2 to plane 1 . (b) Use components to find the magnitude and the direction of the vector \(\overrightarrow{\mathrm{D}}\).

A quarterback can throw a receiver a high, lazy lob pass or a low, quick bullet pass. These passes are indicated by curves 1 and 2 , respectively, in Figure 4.43. (a) The lob pass is thrown with an initial speed of \(21.5 \mathrm{~m} / \mathrm{s}\), and its time of flight is \(3.97 \mathrm{~s}\). What is its launch angle? (b) The bullet pass is thrown with a launch angle of \(25.0^{\circ}\). What is the initial speed of this pass? (c) What is the time of flight of the bullet pass?

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