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What is the acceleration of an object whose positiontime graph is a straight line? Explain.

Short Answer

Expert verified
The acceleration is 0 because the position-time graph is a straight line, indicating constant velocity.

Step by step solution

01

Interpret the Position-Time Graph

Understand that a straight line on a position-time graph indicates that the object's velocity is constant throughout the period. This means the slope of the line, which represents velocity, does not change.
02

Conclude Constant Velocity

A straight line implies that the velocity is not changing over time. Thus, the velocity of the object is constant. In other words, its position changes at a uniform rate.
03

Relate Velocity to Acceleration

Acceleration is defined as the rate of change of velocity with respect to time. Mathematically, it is expressed as \( a = \frac{dv}{dt} \), where \( v \) is velocity and \( t \) is time.
04

Determine the Acceleration

Since the velocity is constant (as indicated by the straight line), the change in velocity \( dv \) over any time interval \( dt \) is zero. Therefore, the acceleration is 0. Mathematically, this means \( a = \frac{dv}{dt} = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Position-Time Graph
A position-time graph visually represents how the position of an object changes over time. On this graph, the horizontal axis typically represents time, while the vertical axis represents position. If you see a straight line on this graph, it tells you that the object's velocity is constant.

For instance, if the line is diagonal and straight, it indicates uniform motion. The object's speed does not change, and it's moving at a constant rate. A flat, horizontal line means the object is stationary, as its position does not change over time.
  • Diagonal straight line: Constant velocity
  • Horizontal line: No movement
Understanding a position-time graph is critical for analyzing motion, as it provides a clear picture of how an object's position changes with time.
Constant Velocity
Constant velocity means that an object moves at a steady speed in a straight line. In other words, its speed and direction remain unchanged.

When an object travels at constant velocity, its acceleration is zero since there is no change in velocity over time. Constant velocity can be easily observed in a position-time graph as a straight line. This straight line indicates that the object covers equal distances in equal intervals of time.
  • Constant speed
  • Unchanging direction
  • No acceleration
Recognizing constant velocity helps in predicting future motion patterns and understanding the object's trajectory over time.
Rate of Change of Velocity
The rate of change of velocity is more commonly known as acceleration. Acceleration measures how quickly an object's velocity changes with time. It is expressed mathematically by the formula \( a = \frac{dv}{dt} \).

When an object's velocity changes, its rate of change is non-zero, indicating acceleration. Conversely, if the velocity remains constant, as in the case of a straight line on a position-time graph, the acceleration is zero because there is no velocity change. This concept is vital in physics as it explains how objects speed up, slow down, or maintain speed.
  • Acceleration: Change in velocity over time
  • Constant velocity: Zero acceleration
The rate of change of velocity is central when analyzing various motions in physics.
Slope
In the context of a position-time graph, the slope represents the velocity of an object. The slope is calculated by dividing the change in position (vertical change) by the change in time (horizontal change).

A steeper slope indicates a higher velocity, while a gentler slope points to a lower velocity. If the line is flat (horizontal), it signifies no movement—meaning the object's velocity is zero.
  • Steep slope: High velocity
  • Gentle slope: Low velocity
  • Horizontal line: Zero velocity
Understanding the concept of slope on a position-time graph is crucial as it helps in determining how fast or slow an object is moving at different points in time.
Uniform Motion
Uniform motion refers to the movement of an object at a constant speed in a straight line. In uniform motion, the object's velocity does not change, meaning it has zero acceleration. On a position-time graph, this motion is represented by a straight line.

Here are key aspects of uniform motion:
  • Constant speed: Equal distances over equal time intervals
  • Straight path: No direction change
  • Zero acceleration: Steady velocity
Uniform motion is an essential concept in physics because it simplifies the analysis of an object's movement, making it predictable and easy to model. It serves as a baseline for understanding more complex motions involving varying speeds and directions.

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Most popular questions from this chapter

Analyze \& Extend A car starts from rest and moves with an acceleration \(a_{0}\) for a time \(t_{0^{-}}\)In that time it covers a distance of \(5 \mathrm{~m}\). How much distance does the car cover if it starts from rest and has the following acceleration and time: (a) \(2 a_{0}\) and \(2 t_{0}\) and (b) \(4 a_{0}\) and \(0.5 t_{0}\) ?

Triple Choice An object is dropped at \(t=0\) and allowed to fall freely toward the ground. Is the distance covered by the object between \(t=0\) and \(t=1 \mathrm{~s}\) greater than, less than, or equal to the distance covered by the object between \(t=1 \mathrm{~s}\) and \(t=2 \mathrm{~s}\) ? Explain.

Surviving a Large Deceleration On July 13, 1977, while on a test drive at Britain's Silverstone racetrack, the throttle on David Purley's car stuck wide open. The resulting crash subjected Purley to the greatest \(g\)-force ever survived by a human-he decelerated from \(173 \mathrm{~km} / \mathrm{h}\) to zero in a distance of only about \(0.66 \mathrm{~m}\). Calculate the magnitude of the acceleration experienced by Purley (assuming it to be constant), and express your answer as a multiple of the acceleration due to gravity, \(g=9.81 \mathrm{~m} / \mathrm{s}^{2}\).

A horse accelerates from rest for \(1 \mathrm{~s}\) and covers a distance \(D\). If, instead, the horse accelerates from rest with the same acceleration for \(2 \mathrm{~s}\), will the distance it covers be equal to \(2 D, 4 D\), or \(9 D ?\) Explain.

At the end of a baseball game Zoe drops her glove to the ground. Mickey tosses his glove into the air. While the gloves are still in the air, is the acceleration of Zoe's glove greater than, less than, or equal to the acceleration of Mickey's glove? Explain.

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