Chapter 26: Problem 30
30\. The radioactive isotope \({ }_{95}^{241} \mathrm{Am}\), with a half-life of \(432 \mathrm{y}\), is essential to the operation of many smoke detectors. Suppose such a detector will no longer function if the activity of the \({ }_{95}^{241} \mathrm{Am}\) it contains drops below \(\frac{1}{525}\) of the initial activity. How long will this kind of smoke detector work?
Short Answer
Step by step solution
Understanding Half-Life
Formulating the Decay Equation
Setting the Desired Activity Level
Equating the Activity Levels
Solving for Time
Calculating the Time
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Radioactive Decay
Activity Calculation
- \(A(t)\) is the activity at time \(t\)
- \(A_0\) is the initial activity
- \(T_{1/2}\) is the half-life of the isotope
- \(t\) represents time.