/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 A proton moves with a speed of \... [FREE SOLUTION] | 91Ó°ÊÓ

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A proton moves with a speed of \(1500 \mathrm{~m} / \mathrm{s}\). What is its de Broglie wavelength?

Short Answer

Expert verified
The de Broglie wavelength is approximately \(2.64 \times 10^{-10} \ \mathrm{m}\).

Step by step solution

01

Identify the de Broglie Wavelength Formula

The de Broglie wavelength \( \lambda \) of a particle is given by the formula \( \lambda = \frac{h}{mv} \), where \( h \) is Planck's constant \( 6.626 \times 10^{-34} \ \mathrm{m^2 \cdot kg/s} \), \( m \) is the mass of the particle (proton mass = \( 1.6726 \times 10^{-27} \ \mathrm{kg} \)), and \( v \) is the velocity of the particle.
02

Substitute Known Values

Substitute the given values into the de Broglie wavelength formula: \[ \lambda = \frac{6.626 \times 10^{-34} \ \mathrm{m^2 \cdot kg/s}}{1.6726 \times 10^{-27} \ \mathrm{kg} \times 1500 \ \mathrm{m/s}} \]
03

Calculate the de Broglie Wavelength

Perform the calculation by first computing the denominator, \( 1.6726 \times 10^{-27} \times 1500 = 2.5089 \times 10^{-24} \ \mathrm{kg \cdot m/s} \). Now divide the numerator by this result:\[ \lambda = \frac{6.626 \times 10^{-34}}{2.5089 \times 10^{-24}} = 2.64 \times 10^{-10} \ \mathrm{m} \].
04

Present the Final Wavelength

The de Broglie wavelength of the proton moving at \(1500 \ \mathrm{m/s}\) is approximately \(2.64 \times 10^{-10} \ \mathrm{m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Planck's constant
Planck's constant, denoted by the letter \( h \), is a fundamental constant in quantum mechanics. It is a tiny value that is used for calculations involving particles at atomic and subatomic scales. The value of Planck's constant is \( 6.626 \times 10^{-34} \ \mathrm{m^2 \cdot kg/s} \). This constant is crucial for linking the energy of a photon to the frequency of its electromagnetic wave, described by the equation \( E = hf \). Here, \( E \) is the energy, \( h \) is Planck's constant, and \( f \) represents frequency.

In the context of de Broglie wavelength, Planck's constant helps in determining the wave properties of matter. According to de Broglie, every particle has a wavelength, and this wavelength can be calculated using the equation \( \lambda = \frac{h}{mv} \) where \( \lambda \) is the wavelength, \( m \) is mass, and \( v \) is velocity. This concept is essential for understanding the wave-particle duality, a fundamental principle of quantum mechanics.
Proton mass
The proton mass is another vital component when calculating the de Broglie wavelength of a particle. A proton is a subatomic particle found in the nucleus of an atom, and it's part of what makes up the atomic nucleus alongside neutrons. In the de Broglie wavelength formula, \( m \) stands for the mass of the particle, which in the case of a proton is approximately \( 1.6726 \times 10^{-27} \ \mathrm{kg} \).

This very small mass reflects the subatomic scale on which protons and other particles operate. Since mass is directly involved in calculating the wavelength of moving particles, even minute particles like protons can exhibit significant wave properties.
  • Understanding proton mass is key to performing accurate calculations of subatomic particle wavelengths.
  • It allows us to explore phenomena such as particle collisions and quantum field theory.
This fundamental property of protons helps solidify our understanding of the microscopic world and the behavior of matter at its most essential level.
Particle velocity
Particle velocity is an important concept when determining the de Broglie wavelength, as it signifies how fast a particle is moving through space. In the formula \( \lambda = \frac{h}{mv} \), \( v \) stands for velocity, which shows up in the denominator. In the original exercise, the proton is moving at a velocity of \( 1500 \ \mathrm{m/s} \).

To calculate the wavelength of the moving proton, we utilize both its mass and its velocity, recognizing that even small changes in velocity can have significant effects on the resulting wavelength due to the small scales involved.
  • It affects the wave properties, ultimately influencing how we observe and measure the proton's characteristics.
  • It's essential when considering factors like temperature, external forces, and potential energy, which might alter velocity.
Understanding particle velocity helps us predict particle behavior under various conditions, making it central to many areas of physics, ranging from classical mechanics to quantum mechanics.

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Most popular questions from this chapter

Predict \& Explain The radiation emitted by blackbody A peaks at a longer wavelength than that of blackbody \(B\). (a) Is the temperature of blackbody A greater than or less than the temperature of blackbody B? (b) Choose the best explanation from among the following: A. Blackbody A has the higher temperature because the higher the temperature, the greater the wavelength. B. Blackbody B has the higher temperature because an increase in temperature means an increase in frequency, which corresponds to a decrease in wavelength.

Calculate Photons with a frequency of \(9.3 \times 10^{14} \mathrm{~Hz}\) strike the surface of a metal with a work function of \(3.6 \mathrm{eV}\). What is the maximum kinetic energy of the ejected electrons?

Firefly Light Fireflies, like the one shown in Figure \(\mathbf{2 4 . 2 5}\), are often said to give off "cold" light. Given that the peak in a firefly's radiation occurs at about \(5.4 \times 10^{14} \mathrm{~Hz}\), determine the temperature of a blackbody that would have the same peak frequency. From your result, would you say that firefly radiation is well approximated by blackbody radiation? Explain.

Concept Check Betelgeuse is a red-giant star in the constellation Orion; Rigel is a bluish star in the same constellation. Which star has the greater surface temperature? Explain.

Think \& Calculate Modern halogen lightbulbs have filaments that operate at a higher temperature than the filaments in standard incandescent bulbs. For comparison, the filament in a standard lightbulb operates at about \(2900 \mathrm{~K}\), whereas the filament in a halogen bulb operates at \(3400 \mathrm{~K}\). (a) Which bulb has the higher peak frequency? (b) The human eye is most sensitive to a frequency around \(5.5 \times 10^{14} \mathrm{~Hz}\). Which bulb produces a peak frequency closer to this value?

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