/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 An AC circuit has an rms current... [FREE SOLUTION] | 91Ó°ÊÓ

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An AC circuit has an rms current of \(3.2 \mathrm{~A}\). What is the average power dissipated in a \(180-\Omega\) resistor?

Short Answer

Expert verified
The average power dissipated is 1843.2 watts.

Step by step solution

01

Identify Given Values

The problem provides the rms current, denoted as \( I_{rms} \), which is \( 3.2\, \text{A} \). It also provides the resistance of the resistor, \( R = 180\, \Omega \).
02

Use Power Formula

The average power dissipated in the resistor can be calculated using the formula \( P_{avg} = I_{rms}^2 \times R \), where \( P_{avg} \) is the average power, \( I_{rms} \) is the rms current, and \( R \) is the resistance.
03

Calculate the Power

Substitute the given values into the formula: \( P_{avg} = (3.2)^2 \times 180 \). This simplifies to \( P_{avg} = 10.24 \times 180 \).
04

Compute the Result

Multiplying the values, you get \( P_{avg} = 1843.2\, \text{W} \). Thus, the average power dissipated is 1843.2 watts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

RMS Current
The root mean square (RMS) current is a crucial concept when dealing with alternating current (AC) circuits. In AC circuits, the current varies over time, usually in a sinusoidal pattern. To make it easier to work with these variations, we use the RMS value. This is a kind of "average" value that simplifies calculations by giving us a single, constant figure that represents the current's effective power. When you see RMS current like the one in the example, which is 3.2 A, it stands for the effective current flowing through the circuit. This value is especially useful when calculating power in an AC circuit because it allows us to apply the same formulas as we would in a direct current (DC) circuit. To find the RMS value, you typically take the square root of the arithmetic mean of the squares of the original values. This is especially handy in physics and engineering because it reflects the true energy content of the AC signal.
Average Power Dissipation
Average power dissipation in a resistor is a measure of how much energy is converted to heat within the resistor over time. This is critically important in AC circuits, as it helps in understanding how much power a circuit component will need to handle, ensuring it won't overheat or get damaged.In the context of AC circuits, this is calculated using the formula: \[ P_{avg} = I_{rms}^2 \times R \] Here, \( P_{avg} \) represents the average power, \( I_{rms} \) is the RMS current, and \( R \) is the resistance. This formula helps you determine the effective power being used, even as the current varies. Using this formula, you replace the given values into the equation to compute the power dissipated. If you've ever worked with electronics, knowing how to calculate power helps in component selection and assessing efficiency.
Resistor Power Formula
The resistor power formula is a staple for determining how much power a resistor in a circuit is handling. In both AC and DC circuits, the power dissipated by a resistor is usually determined by one of three formulas, depending on the known quantities:
  • \( P = I^2 \times R \)
  • \( P = V^2 / R \)
  • \( P = V \times I \)
In the case of an AC circuit, we specifically use the first formula with RMS values for current, like in the worked example. Each formula shows the clear relationship between power, voltage, current, and resistance, demonstrating how each of these electrical properties affects the others.Understanding these equations helps predict whether a resistor can handle a particular setup without overheating, and enables engineers to design circuits that are both safe and efficient. Hence, choosing the right formula depends on your given values and the specific parameters of your circuit setup.

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