/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 A roller coaster moves on a cert... [FREE SOLUTION] | 91Ó°ÊÓ

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A roller coaster moves on a certain section of its track with an average speed of \(12 \mathrm{~m} / \mathrm{s}\). How much distance does it cover in \(5.5 \mathrm{~s}\) ?

Short Answer

Expert verified
The roller coaster covers 66 meters.

Step by step solution

01

Identify Given Values

First, identify the values given in the problem. The average speed of the roller coaster is provided as \(12 \ \text{m/s}\), and the time for which it travels is \(5.5 \ \text{s}\).
02

Recall the Distance Formula

Recall the formula to find distance when speed and time are known: \[\text{Distance} = \text{Speed} \times \text{Time}\]
03

Substitute Values Into the Formula

Substitute the given values of speed and time into the distance formula. Using the values: \[\text{Distance} = 12 \ \text{m/s} \times 5.5 \ \text{s}\]
04

Calculate the Distance

Perform the multiplication to find the total distance covered by the roller coaster:\[\text{Distance} = 12 \times 5.5 = 66 \ \text{m}\]
05

Conclusion

The roller coaster covers a distance of \(66 \ \text{m}\) in \(5.5 \ \text{s}\) at an average speed of \(12 \ \text{m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Average Speed
When discussing motion, average speed is a fundamental concept that describes how fast an object is moving over a period of time. It's calculated by dividing the total distance traveled by the total time taken.
Average speed is a scalar quantity, meaning it only has magnitude and no direction. In the context of our roller coaster problem, the average speed of the coaster is given as \(12 \ \text{m/s}\). This means, on average, the roller coaster covers 12 meters every second.
In real-world scenarios, the speed is not always constant due to changes in direction, acceleration, or even stops. However, averaging gives us a simplified, general outlook on how fast something is moving over the entire trip. To calculate it, use the formula \[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \]. This formula helps to easily increase our understanding of the movement by highlighting its consistency over the given period.
Calculating Time in Physics Problems
Time is a crucial component in physics, often representing the duration of events or the interval between occurrences. In our current exercise, time is represented as \(5.5 \ \text{s}\) or 5.5 seconds, the period during which the roller coaster moves.
Physics problems often ask to analyze or compute time in relation to other variables like speed and distance. It's pivotal for solving equations related to motion, such as figuring out how long something takes to reach a certain speed or cover a particular distance.
Understanding the unit of time is essential; in physics, the second (\(\text{s}\)) is the standard. Students should remember that time, being a scalar quantity without direction, forms one side of the basic equation of motion: \( \text{Distance} = \text{Speed} \times \text{Time} \). Simplifying these relations helps grasp how changes in time affect other variables.
Applying Concepts in Physics Problems
Physics problems often require an integration of multiple concepts, such as speed, distance, and time. Solving these requires not just knowing formulas but understanding how and why to apply them.
In our roller coaster scenario, we identified given values, recalled relevant formulas, substituted values appropriately, performed calculations, and then drew conclusions.
This systematic approach can be applied to many physics problems by following these steps:
  • Identify and write down all known values carefully.
  • Recall relevant physics equations. For motion, it's often \( \text{Distance} = \text{Speed} \times \text{Time} \).
  • Substitute the known values into the formula, ensuring units match.
  • Perform the necessary calculations with attention to detail.
  • Conclude your findings and review if the solution logically fits real-world understanding.

The formulaic approach helps organize thinking and leads to successful problem-solving, especially in physics, where each calculation stems from core principles like those used in this exercise.

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Most popular questions from this chapter

Two people walking on a sidewalk have the following equations of motion: $$ \begin{aligned} &x_{1}=8.2 \mathrm{~m}+(-1.1 \mathrm{~m} / \mathrm{s}) t \\ &x_{2}=5.9 \mathrm{~m}+(1.7 \mathrm{~m} / \mathrm{s}) t \end{aligned} $$ (a) Which person is moving faster? (b) Which person will be at \(x=0\) at some time in the future?

Object 1 starts at \(25 \mathrm{~m}\) and moves with a velocity of \(-5.6 \mathrm{~m} / \mathrm{s}\). Object 2 starts at \(13 \mathrm{~m}\) and moves directly toward object 1. The two objects collide \(0.61 \mathrm{~s}\) after starting. (a) What is the velocity of object 2? (b) What is the position of the objects when they collide?

Triple Choice You travel along the \(x\) axis from the location \(x_{\mathrm{i}}=10 \mathrm{~m}\) to the location \(x_{\mathrm{f}}=25 \mathrm{~m}\). Your location \(x_{\mathrm{i}}=10 \mathrm{~m}\) to the location \(x_{\mathrm{f}}=25 \mathrm{~m}\). Your friend travels from \(x_{\mathrm{i}}=35 \mathrm{~m}\) to \(x_{\mathrm{f}}=40 \mathrm{~m}\). Is the distance you cover greater than, less than, or equal to the distance covered by your friend? Explain.

Think \& Calculate You drive in a straight line at \(20.0 \mathrm{~m} / \mathrm{s}\) for \(10.0 \mathrm{~min}\), then at \(30.0 \mathrm{~m} / \mathrm{s}\) for another \(10.0 \mathrm{~min}\). (a) Is your average speed \(25.0 \mathrm{~m} / \mathrm{s}\), more than \(25.0 \mathrm{~m} / \mathrm{s}\), or less than \(25.0 \mathrm{~m} / \mathrm{s}\) ? Explain. (b) Verify your answer to part (a) by calculating the average speed.

Object 1 starts at \(25 \mathrm{~m}\) and moves with a velocity of \(-5.6 \mathrm{~m} / \mathrm{s}\). Object 2 starts at \(13 \mathrm{~m}\) and moves directly toward object 1 . The two objects collide \(0.61 \mathrm{~s}\) after starting. (a) What is the velocity of object 2? (b) What is the position of the objects when they collide?

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