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The yellow light from a helium discharge tube has a wavelength of \(587.5 \mathrm{~nm}\). When this light shines on a certain diffraction grating, it produces a first-order principal maximum ( \(m=1\) ) at an angle of \(1.250^{\circ}\). Calculate the slit spacing for this grating.

Short Answer

Expert verified
The slit spacing is approximately \(2.69 \times 10^{-5}\,\text{m}\).

Step by step solution

01

Understanding the problem

We need to find the slit spacing, denoted as \(d\), for a diffraction grating given a wavelength \(\lambda = 587.5\,\text{nm}\) and a diffracted angle \(\theta = 1.250^{\circ}\) for the first-order maximum \(m=1\).
02

Formula for diffraction grating

The formula for the diffraction grating is given by the equation \(d \sin\theta = m\lambda\), where \(d\) is the slit spacing, \(\theta\) is the angle, \(m\) is the order number (which is 1 in this case), and \(\lambda\) is the wavelength of the light.
03

Convert angle to radians

Convert the angle from degrees to radians since trigonometric functions in physics often use radians. \[\theta = 1.250^{\circ} \times \frac{\pi}{180^{\circ}} = 0.0218 \, \text{radians}\]
04

Re-arrange the equation to solve for slit spacing

To find \(d\), rearrange the formula: \[d = \frac{m\lambda}{\sin\theta}\].
05

Substitute values into the equation

Substitute \(m = 1\), \(\lambda = 587.5\,\text{nm} = 587.5 \times 10^{-9}\,\text{m}\), and \(\theta = 0.0218\, \text{radians}\) into the equation: \[d = \frac{1 \times 587.5 \times 10^{-9}}{\sin(0.0218)}\]
06

Calculate the slit spacing

Perform the calculation to find \(d\): \[d = \frac{587.5 \times 10^{-9}}{0.0218}\] After calculation, \[d \approx 2.69 \times 10^{-5}\,\text{m}\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength
Wavelength is a fundamental concept when analyzing light and its behavior in different environments. It is the distance between consecutive peaks or troughs in a wave, typically measured in nanometers (nm) for light. In the context of diffraction grating, wavelength plays a crucial role in determining how a wave front will spread out after passing through narrow slits.
When light of a specific wavelength, such as 587.5 nm from a helium discharge tube, interacts with a diffraction grating, its ability to create visible interference patterns is directly linked to this property.
Wavelength determines the color of the light and is pivotal in calculating other factors such as slit spacing and diffraction angle. It forms the basis for equations used in optics, providing necessary input to calculate and predict the behavior of light in various experiments.
  • Unit of Measure: Nanometers (nm)
  • Determines Color of Light
  • Fundamental for Diffraction Calculations
Slit Spacing
Slit spacing, represented by the symbol \(d\), refers to the distance between adjacent slits in a diffraction grating. It is a critical parameter that influences how light waves interfere with one another to form distinctive diffraction patterns.
The calculation of slit spacing involves using the diffraction grating equation \(d \sin\theta = m\lambda\). Here, you rearrange the equation to find \(d\) and solve by substituting known values of wavelength, the order of the maximum, and the angle of diffraction.
Slit spacing affects the overall resolution and the spread of the interference patterns produced by the grating. Smaller slit spacings result in more spread-out diffraction patterns, while larger spacings lead to patterns that are closer together, directly impacting the observed angles
  • Determines Pattern Spread
  • Calculated using known variables
  • Essential for Interference Analysis
  • Angle of Diffraction
    The angle of diffraction, denoted as \(\theta\), is the angle at which light emerges from a diffraction grating relative to the original direction of the incoming wave. This angle is essential in predicting where maximum intensities, or bright spots, will occur on a screen.
    To convert angles from degrees to radians, which is often necessary for calculation purposes in physics, use the conversion factor \( \frac{\pi}{180} \). For the exercise, this conversion provides a usable figure in the diffraction equation, resulting in \(\theta = 0.0218\, \text{radians}\).
    The angle of diffraction impacts the ability to precisely locate interference patterns and is deeply entwined with wavelength and slit spacing. It allows physicists to fine-tune grating setups for desired experimental outcomes.
    • Measured in Degrees or Radians
    • Critical for Determining Maximum Intensity Locations
    • Converted for Calculation in Radians
    First-Order Maximum
    The first-order maximum refers to the first bright fringe on either side of the central maximum in a diffraction pattern. It's denoted by \(m = 1\) in diffraction equations, marking the first position where constructive interference is observed.
    When calculating the first-order maximum for a particular wavelength and grating setup, it helps to identify the initial set of non-central bright fringes that are often the most intense and defined.
    Understanding this concept is vital for anyone studying diffraction patterns, as it provides a basis to explore higher orders (like second-order, third-order) and predict additional interference phenomena.
    • Corresponds to \(m = 1\)
    • Indicates First Bright Fringe
    • Foundation for Further Pattern Analysis

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    Most popular questions from this chapter

    Does a diffraction grating have many slits or only one or two?

    Two plates of glass are separated by an air-filled space with a thickness of \(5.1 \times 10^{-5} \mathrm{~m}\). What wavelength of light experiences constructive interference for \(m=250\) ?

    Resolving Lines on an HDTV The American Television Systems Committee (ATSC) sets the standards for highdefinition television (HDTV). One of the approved HDTV formats is \(1080 \mathrm{p}\), which means 1080 horizontal lines scanned progressively (p) - that is, one line after another in sequence from top to bottom. Another standard is \(1080 \mathrm{i}\), or 1080 interlace. With this format it takes two scans of the screen to show a complete picture-the first scan shows the "even" horizontal lines, the second scan shows the "odd" horizontal lines. For the following problems, assume that 1080 horizontal lines are displayed on a television with a screen that is \(39.9 \mathrm{~cm}\) high (32-in diagonal) and that the light coming from the screen has a wavelength of \(474 \mathrm{~nm}\) inside your eyes. Also, assume that the pupils of your eyes have a diameter of \(5.50 \mathrm{~mm}\). What is the minimum angle (in degrees) your eye can resolve for the given wavelength and pupil diameter? (This is the angle to the first-order dark fringe of the diffraction pattern.) A. \(0.240 \times 10^{-3}\) B. \(4.05 \times 10^{-3}\) C. \(4.94 \times 10^{-3}\) D. \(6.02 \times 10^{-3}\)

    Two sources emit waves that are coherent and in phase and have a wavelength of \(26.0 \mathrm{~m}\). Do the waves interfere constructively or destructively at a point \(85.0 \mathrm{~m}\) from one source and \(124 \mathrm{~m}\) from the other source?

    \- If the wavelength of the light used in a two-slit experiment is decreased, does the spacing between the bright fringes increase, decrease, or stay the same? Explain.

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