/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Light with a wavelength of \(546... [FREE SOLUTION] | 91Ó°ÊÓ

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Light with a wavelength of \(546 \mathrm{~nm}\) passes through two slits and forms an interference pattern on a screen \(8.75 \mathrm{~m}\) away. If the vertical distance from the central bright fringe to the first bright fringe above it on the screen is \(5.36 \mathrm{~cm}\), what is the separation of the slits?

Short Answer

Expert verified
The separation of the slits is approximately \( 0.891 \mathrm{~mm} \).

Step by step solution

01

Understand the Problem

The problem describes an interference pattern created by light passing through two slits. We need to find the separation between the slits, given the wavelength of light, the distance to the screen, and the distance from the central bright fringe to the first bright fringe.
02

Recall the Interference Formula

For two-slit interference patterns, the position of the bright fringes is given by the formula: \( y = \frac{m \lambda D}{d} \), where \( y \) is the distance from the central maximum to the \( m \)-th bright fringe, \( \lambda \) is the wavelength, \( D \) is the distance to the screen, \( d \) is the separation of the slits, and \( m \) is the fringe order.
03

Identify Known Variables

From the problem, we know \( \lambda = 546 \ \mathrm{nm} = 546 \times 10^{-9} \mathrm{~m} \), \( D = 8.75 \mathrm{~m} \), and \( y = 5.36 \mathrm{~cm} = 0.0536 \mathrm{~m} \). The fringe order \( m \) for the first bright fringe is 1.
04

Rearrange the Formula for Slit Separation

We need to solve for \( d \). Rearrange the formula to get \( d = \frac{m \lambda D}{y} \).
05

Calculate Slit Separation

Substitute the known values into the rearranged formula: \( d = \frac{1 \times 546 \times 10^{-9} \mathrm{~m} \times 8.75 \mathrm{~m}}{0.0536 \mathrm{~m}} \). This simplifies to \( d \approx 8.91 \times 10^{-4} \mathrm{~m} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wavelength of Light
Light travels in waves, much like the ripples in a pond. When discussing light, a key characteristic is its wavelength. The **wavelength of light** is the distance between two consecutive peaks of light waves and is usually measured in nanometers (nm). A shorter wavelength corresponds to more energy and a higher frequency, whereas a longer wavelength means less energy and lower frequency.
If you imagine light as a ripple in water, imagine each crest of the ripple being equidistant. If the wavelength is 546 nm, that means the distance from one crest of a wave to the next is 546 nanometers. This specific wavelength is very important for our understanding of light behavior in experiments like the double-slit interference, as it directly affects the spacing and appearance of the interference pattern on a screen. Understanding the wavelength helps us predict and explain the resulting pattern observed on the screen.
Interference Pattern
An **interference pattern** is a phenomenon that occurs when waves overlap and combine. For light passing through two slits, this leads to a fascinating display of alternating bright and dark stripes or fringes.
Here's how it works:
  • The light waves from each slit spread out and overlap on the screen.
  • At certain points, the crests of one wave align with the troughs of another, canceling them out, resulting in dark fringes.
  • At other points, the crests align with crests, and troughs with troughs, reinforcing each other, creating bright fringes.
The central bright fringe is the point where the distance travels by light from both slits is exactly equal. As you move outward on the screen, the pattern repeats, creating further bright fringes. The distances of these bright fringes from the central maximum depend on several factors, such as the wavelength of light and the separation between the slits.
Slit Separation
The distance between the two slits is referred to as the **slit separation**. This parameter is crucial because it influences the positioning and spacing of the interference fringes.
Here's how slit separation plays a critical role:
  • Closer slits cause the bright fringes to be more widely spaced on the screen.
  • Further apart slits result in fringes appearing closer together.
To calculate the slit separation in an interference experiment, we use the formula: \[ d = \frac{m \lambda D}{y} \]where:
  • \( d \) is the slit separation.
  • \( m \) is the order of the fringe (for the first bright fringe \( m = 1 \)).
  • \( \lambda \) is the wavelength of the light.
  • \( D \) is the distance from the slits to the screen.
  • \( y \) is the distance from the central maximum to the fringe.
In our example, using the known variables and this formula, we determined the slit separation to be approximately 0.000891 m, showing how these values interplay to reveal unknowns.

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Most popular questions from this chapter

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