/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Updrafts of air allow hawks and ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Updrafts of air allow hawks and eagles to glide effortlessly, all the while gaining altitude. What causes the updrafts?

Short Answer

Expert verified
Updrafts are caused by thermal heating, orographic lifting, and frontal lifting.

Step by step solution

01

Understanding Updrafts

Updrafts are upward air currents that occur when air rises from the ground into the atmosphere. This phenomenon is particularly beneficial to birds like hawks and eagles, enabling them to gain altitude without much effort while gliding.
02

Causes of Updrafts - Thermal Heating

One common cause of updrafts is thermal heating. When the sun heats the ground, the air above it warms up and becomes less dense. This warmed air then rises, creating an updraft.
03

Causes of Updrafts - Orographic Lifting

Another cause is orographic lifting, where air is forced to rise over an obstacle like a mountain range. As it ascends, the air cools and condenses, but the initial lifting creates updrafts that birds can exploit.
04

Causes of Updrafts - Frontal Lifting

A third cause involves frontal lifting, which occurs when air masses with different temperatures collide. The warmer, less dense air is pushed upwards over the colder, denser air, forming an updraft.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Heating
Thermal heating is a process driven by the sun's energy. When the sun shines on the Earth's surface, it causes the ground to become warm. This, in turn, heats the air just above the ground. As the air warms, its density decreases, making it lighter than the surrounding cooler air.
This difference in density causes the warmer air to rise, generating an upward-moving air current known as a thermal updraft.
  • This type of updraft provides ideal conditions for birds to glide without flapping their wings.
  • The rising warm air gives them lift as they soar through the sky.
Thermal updrafts are commonly observed in areas with large flat surfaces that heat up quickly, such as fields, deserts, or parking lots. Birds, such as hawks and eagles, masterfully leverage these updrafts to conserve energy while traveling long distances or gaining height swiftly.
Orographic Lifting
Orographic lifting describes an atmospheric event that occurs as air flows over terrain features like mountains or hills. When the wind encounters a physical barrier, such as a mountain range, it is forced to ascend.
  • As the air rises, it cools. This cooling can lead to condensation, cloud formation, and sometimes precipitation.
  • The initial lift over the terrain can form updrafts.
These updrafts are crucial for gliding birds that operate in mountainous regions. By riding the orographic lift, hawks and eagles can effortlessly gain altitude without significant energy expenditure.
In addition, orographic lifting significantly influences local climates and weather patterns, as it affects wind patterns and precipitation distribution.
Frontal Lifting
Frontal lifting occurs when two contrasting air masses meet—typically, where warm and cold fronts converge. During this interaction, the warmer, less dense air is forced to rise above the colder, denser air.
This lifting creates a sustained updraft, often accompanied by cloud formation and precipitation.
  • This mechanism is often noticeable at weather fronts, where temperature differences are more pronounced.
  • These areas of rising air can be exploited by birds for gliding.
Frontal lifting not only aids birds in flight but also plays a critical role in weather formation. It is particularly relevant in influencing storm development and patterns. Birds instinctively use the air rising at these boundaries to move efficiently across large expanses of territory.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The Cricket Thermometer The rate of chirping of the snowy tree cricket (Oecanthus fultoni Walker) varies with temperature in a predictable way. A linear relationship provides a good match to the chirp rate, but an even more accurate relationship is the following: $$ N=\left(5.63 \times 10^{10}\right) e^{-(6290 K) / T} $$ In this expression, \(N\) is the number of chirps in \(13.0 \mathrm{~s}\) and \(T\) is the temperature in kelvins. If a cricket is observed to chirp 185 times in \(60.0 \mathrm{~s}\), what is the temperature in degrees Celsius?

Assess Your friend claims that stirring a glass of water with a spoon increases the temperature of the water. Is he right? Explain.

At the county fair you watch as a blacksmith drops a \(0.50-\mathrm{kg}\) iron horseshoe into a bucket containing \(25 \mathrm{~kg}\) of water. If the initial temperature of the horseshoe is \(450^{\circ} \mathrm{C}\) and the initial temperature of the water is \(23^{\circ} \mathrm{C}\), what is the equilibrium temperature of the system? Assume that no thermal energy is exchanged with the surroundings.

What is the temperature \(1.0 \mathrm{~K}\) equivalent to on the Celsius scale?

Some cookware has a stainless steel interior \(\left(\alpha=17.3 \times 10^{-6} \mathrm{~K}^{-1}\right)\) and a copper bottom \(\left(\alpha=17.0 \times 10^{-6} \mathrm{~K}^{-1}\right)\) for better heat distribution. Suppose a \(21-\mathrm{cm}\)-diameter pot of this type is heated to \(610^{\circ} \mathrm{C}\) on a stove. If the initial temperature of the pot was \(22^{\circ} \mathrm{C}\), what is the difference in diameter change for the copper and the steel?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.