Chapter 7: Problem 39
An ionized gas or plasma is a dispersive medium for EM waves. Given that the dispersion equation is $$\omega^{2}=\omega_{p}^{2}+c^{2} k^{2}$$ where \(\omega_{p}\) is the constant plasma frequency, determine expressions for both the phase and group velocities and show that \(v v_{g}=c^{2}\).
Short Answer
Expert verified
Phase velocity \(v = \sqrt{\frac{\omega_{p}^{2}}{k^2} + c^2}\) and group velocity \(v_g = \frac{c^{2} k}{\omega}\); \(v v_g = c^2\).
Step by step solution
01
Review given dispersion equation
We are provided with the dispersion equation for an ionized gas or plasma: \(\omega^{2}=\omega_{p}^{2}+c^{2} k^{2}\), where \(\omega\) is the angular frequency, \(\omega_{p}\) is the plasma frequency, \(c\) is the speed of light, and \(k\) is the wave number.
02
Define Phase Velocity
The phase velocity \(v\) of a wave is given by \(v = \frac{\omega}{k}\). Using the dispersion relation \(\omega^{2}=\omega_{p}^{2}+c^{2} k^{2}\), solve for \(\omega\) to express \(v\) in terms of given variables.
03
Solve for \(\omega\) to Find \(v\)
From the dispersion equation, we get \(\omega = \sqrt{\omega_{p}^{2} + c^2 k^2}\). Substituting this into the phase velocity formula gives us \(v = \frac{\sqrt{\omega_{p}^{2} + c^2 k^2}}{k}\). Simplifying, this becomes \(v = \sqrt{\frac{\omega_{p}^{2}}{k^2} + c^2}\).
04
Define Group Velocity
The group velocity \(v_g\) is defined as \(v_g = \frac{d\omega}{dk}\). Differentiate the dispersion relation \(\omega^{2} = \omega_{p}^{2} + c^{2}k^{2}\) with respect to \(k\) to find \(v_g\).
05
Differentiate to Find \(v_g\)
Differentiate \(\omega = \sqrt{\omega_{p}^{2} + c^2 k^2}\) with respect to \(k\) to obtain \(\frac{d\omega}{dk} = \frac{c^{2} k}{\sqrt{\omega_{p}^{2} + c^{2} k^{2}}}\). Therefore, \(v_g = \frac{c^{2} k}{\omega}\).
06
Verify relationship \(v v_g = c^2\)
Multiply the expressions for phase velocity \(v\) and group velocity \(v_g\): \(v \times v_g = \left(\sqrt{\frac{\omega_{p}^{2}}{k^2} + c^2}\right) \times \left(\frac{c^{2} k}{\omega}\right)\). Substitute \(\omega = \sqrt{\omega_{p}^{2} + c^{2} k^{2}}\) to see that \(v \times v_g = c^2\). This shows that the relationship holds true.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Phase Velocity
When we talk about phase velocity, it means how fast a certain phase in the wave (like a crest) is moving. This is crucial in understanding the dispersion of waves in plasma. In simple terms, phase velocity, denoted as \(v\), is the rate at which a given phase of the wave travels through space. It's mathematically expressed as:
- \(v = \frac{\omega}{k}\)
- \(v = \sqrt{\frac{\omega_{p}^{2}}{k^2} + c^2}\)
Group Velocity
Group velocity is all about the speed at which the overall shape of the wave's envelope or a pulse travels through space. This might be a bit tricky, but it's what often carries the actual energy and information. The group velocity, denoted \(v_g\), is defined by how the frequency \(\omega\) changes with the wave number \(k\):
- \(v_g = \frac{d\omega}{dk}\)
- \(v_g = \frac{c^{2} k}{\sqrt{\omega_{p}^{2} + c^{2} k^{2}}}\)
Dispersion Equation
Dispersion in plasma is dictated by the dispersion equation \(\omega^{2} = \omega_{p}^{2} + c^{2} k^{2}\). This describes how the angular frequency \(\omega\) of waves depends on their wave number \(k\). To break it down:
- \(\omega\) is the angular frequency—how many oscillations or cycles per second.
- \(\omega_p\) is the plasma frequency, a constant representing the natural frequency of oscillations in the plasma.
- \(c\) is the speed of light, a fundamental constant.
- \(k\) is the wave number, indicating how the wavelength relates to the spatial variation.