Chapter 5: Problem 20
What must the focal length of a thin negative lens be for it to form a virtual image \(50 \mathrm{cm}\) away (measured from the lens) of an ant located \(100 \mathrm{cm}\) away (measured from the lens)? Given (just as a change of pace) that the ant is to the right of the lens, locate and describe its image.
Short Answer
Step by step solution
Identify known quantities
Apply the lens formula
Solve for the focal length \(f\)
Describe the characteristics of the image
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Focal Length
Virtual Image
In the context of the thin lens formula used in the exercise, the image distance \(d_i\) is negative, signifying a virtual image. This happens because the image forms on the same side as the object, which in this case is to the right of the lens (\(d_i = -50 \text{ cm}\)). Virtual images are always upright compared to the original object and, in this situation, they also appear smaller due to the diverging effect of the lens.
Object Distance
- If an object is placed far from a lens, it might produce a clearer, real image on the opposite side.
- When close and if a converging lens is used, it can magnify the object into a virtual image.
Image Characteristics
For our exercise, the characteristics are defined as follows:
- **Nature:** The image is virtual because it forms on the same side as the object (\(d_i = -50 \text{ cm}\)). Virtual images can't be projected onto a screen given they are just apparent locations.
- **Orientation:** This image is upright, maintaining the same vertical orientation as the actual object.
- **Size:** It is smaller than the actual object, which is a consistent feature of diverging lenses as they spread light rays apart.