/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 34 Using energy arguments, show tha... [FREE SOLUTION] | 91Ó°ÊÓ

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Using energy arguments, show that the amplitude of a cylindri- cal wave must vary inversely with \(\sqrt{r} .\) Draw a diagram indicating what's happening.

Short Answer

Expert verified
Cylindrical wave amplitude varies inversely with \(\sqrt{r}\).

Step by step solution

01

Understand Cylindrical Wave Propagation

Cylindrical waves propagate in a plane, diverging equally in all directions around a line source. As the wave travels outward, it covers an expanding cylindrical surface of radius \(r\). The energy of the wave is distributed over this surface area.
02

Describe Energy Conservation

The total power (energy per unit time) \(P\) emitted by the source is conserved as the wave propagates. The intensity \(I\), which is power per unit area, reduces with increasing radius due to the expansion of the cylindrical surface area over which the energy is spread.
03

Relate Intensity to Amplitude

For cylindrical waves, intensity \(I\) is proportional to the square of the amplitude \(A\), i.e., \(I \propto A^2\). This relationship holds because intensity is related to the energy density of the wave.
04

Calculate Intensity with Radius

The surface area of a cylinder is proportional to its circumference, which is \(2\pi r\). Therefore, the intensity \(I\) is inversely proportional to the circumference, so \(I \propto \frac{1}{r}\).
05

Derive Amplitude Variation with Radius

Since \(I \propto A^2\) and \(I \propto \frac{1}{r}\), we combine these to find \(A^2 \propto \frac{1}{r}\). Solving for \(A\), we find \(A \propto \frac{1}{\sqrt{r}}\), showing that the amplitude decreases inversely with the square root of the radius.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Propagation
Wave propagation is the process by which waves travel through space or various media. In the case of cylindrical waves, their propagation differs from other types, such as spherical waves, because they emanate from a line source rather than a point source. As the waves move outward, they spread across a cylindrical surface. This surface expands as the radius increases, causing the energy of the wave to be distributed over a larger area. Think of dropping a stone in a long straight pond versus a round one. Waves in the long pond spread in straight lines, mirroring cylindrical wave behavior. This expansion is critical to understand how the wave's properties, like intensity and amplitude, change with distance from the source.
Energy Conservation
Energy conservation is a fundamental principle stating that the total energy in a closed system remains constant over time. For cylindrical waves, the principle of energy conservation implies that the total power emitted by the source remains unchanged, even as the waves spread across a larger area. Because the energy is conserved, as the radius of the wave's propagation increases, the energy must be spread more thinly across the expanding cylindrical surface. This broader distribution is why the intensity of the wave decreases with increasing radius. The total energy isn't lost; instead, it causes a change in how it is shared across the larger surface, maintaining the law of energy conservation.
Wave Intensity
Wave intensity refers to the power per unit area carried by the wave. As you move farther from the source of a cylindrical wave, the intensity decreases. This reduction occurs because the energy that was once concentrated over a smaller area now spreads across a much larger cylindrical surface. Mathematically, the surface area of the cylindrical wave grows linearly with its radius — more specifically it is proportional to the circumference, which is given by the formula \(2\pi r\). Therefore, the intensity \(I\) can be expressed as inversely proportional to the radius \(r\), so \(I \propto \frac{1}{r}\). This relationship helps us understand how quickly the wave's intensity diminishes as it travels further from its source.
Amplitude Variation
Amplitude variation describes how the maximum extent of a wave's oscillation changes with distance from the source. For cylindrical waves, as we have established, intensity is related to amplitude by the relation \(I \propto A^2\). So why does amplitude vary inversely with the square root of the radius? Since \(I \propto \frac{1}{r}\), we can equate and rearrange these expressions: \(A^2 \propto \frac{1}{r}\). Solving for \(A\) gives \(A \propto \frac{1}{\sqrt{r}}\), meaning the amplitude decreases in an inverse square root manner as the wave travels outward. This subtle decrease ensures that the energy configuration adapts to maintain energy conservation across growing distances. Such a relationship reveals the elegant balance in the physics of wave propagation.

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