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A collimated beam from a ruby laser \((694.3 \mathrm{nm})\) having an irradiance of \(10 \mathrm{W} / \mathrm{m}^{2}\) is incident perpendicularly on an opaque screen containing a square hole \(5.0 \mathrm{mm}\) on a side. Compute the irradiance at a point on the central axis \(250 \mathrm{cm}\) from the aperture. Check that this is near-field diffraction.

Short Answer

Expert verified
Irradiance at 250 cm is near-field; thus, approximately 10 W/m².

Step by step solution

01

Understand the Problem

We are tasked with calculating the irradiance at a point 250 cm from an aperture, specifically on the central axis. The beam from a ruby laser with a given wavelength and initial irradiance passes through a square aperture. Additionally, we need to determine whether the situation involves near-field diffraction.
02

Calculate Diffraction Angle

To solve this problem, start by determining if we're dealing with near or far-field diffraction by calculating the diffraction angle using the formula for the first minimum: \( \theta = \frac{\lambda}{a} \), where \( \lambda = 694.3 \ nm = 694.3 \times 10^{-9} \ m \) and \( a = 5 \ mm = 5 \times 10^{-3} \ m \).
03

Analyze Near-Field vs Far-Field

Comparing the distance \(d = 250 \ cm = 2.5 \ m\) against Fresnel number \(F\), where \( F = \frac{a^2}{\lambda \cdot d} \). If \( F > 1 \), the diffraction is considered near-field (Fresnel). Calculate \( F \).
04

Calculate Fresnel Number

Substitute the values into the Fresnel number formula: \( F = \frac{(5 \times 10^{-3})^2}{694.3 \times 10^{-9} \times 2.5} \). Compute \( F \) to decide the diffraction type.
05

Determine Irradiance Using Fresnel Diffraction

Given the computed Fresnel number indicating near-field diffraction, approximate the irradiance using Fresnel diffraction principles. Since exact calculation needs computing complex integrals, we consider the beam is mainly contributing straightforwardly. Assuming minimal diffraction spread, the irradiance remains close to the initial value, as energy conserves over the aperture when distance is modest.
06

Conclusion

The beam undergoes near-field (Fresnel) diffraction. Its irradiance at 250 cm remains similar to the initial value since significant spreading due to diffraction doesn't occur over such a relatively moderate distance, preserving its initial characteristics.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Near-Field Diffraction
Near-field diffraction, also known as Fresnel diffraction, occurs when light waves pass close to an obstacle or through a narrow aperture. This type of diffraction is characterized by wavefronts that do not reach the far-field or infinity, causing the light to display unique interference patterns. In our example, the beam travels only 250 cm from the aperture, a distance that supports near-field conditions because the wavefronts are still converging or diverging rather than parallel.
To determine if a situation involves near-field diffraction, we use the Fresnel number, a critical factor that governs whether the diffraction pattern will be near-field or far-field. Near-field diffraction is crucial in understanding how optical devices like lasers and microscopes behave when manipulating light in short ranges.
Overall, near-field diffraction is typical for arrangements where the observation screen is relatively close to the diffracting object, making it important for applications requiring precision light control like in laser optics.
Exploring the Fresnel Number
The Fresnel number, denoted as \( F \), is a dimensionless value that helps classify the type of diffraction in a given system. It is calculated by the formula: \[ F = \frac{a^2}{\lambda \cdot d} \]where \( a \) is the aperture dimension, \( \lambda \) is the wavelength, and \( d \) is the distance from the aperture to the point of interest.
A Fresnel number greater than one \( F > 1 \) indicates near-field diffraction. In the exercise example, the calculated Fresnel number confirms this, highlighting the conditions for Fresnel diffraction. As an engineering design tool, the Fresnel number assists in predicting how light behaves across various conditions and distances and is particularly used to ensure the spatial integrity of the light source in applications like laser cutting and precision measurements.
Understanding the Fresnel number is essential for anyone working with optical systems as it focuses on how closely spaced wavefronts will interfere and affect the resultant intensity distribution.
Irradiance Calculation in Near-Field
Irradiance is a measure of the power of electromagnetic radiation per unit area. In our given task, we needed to find the irradiance at 250 cm from the aperture after the beam passes through it. In the context of near-field diffraction, while exact calculations may involve complex integrals, a practical approach is often employed. In this case, the beam's energy distribution largely remains unchanged over moderate distances.
Given the near-field conditions confirmed by the Fresnel number, one can assume that the irradiance remains relatively consistent with the initial value of \(10\, \text{W/m}^2 \). This is due to the minimal spreading and divergence of the beam pre-radiating from the aperture. This assumption helps simplify and expedite the calculation process without delving into rigorous mathematical complexities.
By approximating within these parameters, students can solve similar physics problems involving light through apertures while gaining intuitive insights into optical physics.
Applications in Laser Physics
Laser physics involves the study of light amplification and coherent wave emissions; therefore, understanding diffraction phenomena is fundamental. Lasers, often used in precise cutting, communication, and surgeries, require a detailed understanding of how their beam interacts with different apertures and obstacles.
Our example illustrates the principle of laser beams going through apertures and being affected by diffraction, which in turn affects their irradiance. In practical settings, ensuring minimal diffraction spreading is crucial for maintaining beam quality and coherence over various distances.
Moreover, laser physicists leverage concepts like the Fresnel number and diffraction patterns to design systems that optimize beam delivery in diverse environments, whether in industry or research. By ensuring light remains confined and energy does not dissipate prematurely, lasers achieve high precision and efficiency necessary for cutting-edge technology.
Ultimately, the insights gained from diffraction and irradiance calculations aid in the sophisticated development and deployment of lasers in multiple domains, from medical devices to telecommunications.

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Most popular questions from this chapter

The Mount Palomar telescope has an objective mirror with a \(508-\mathrm{cm}\) diameter. Determine its angular limit of resolution at a wavelength of \(550 \mathrm{nm}\), in radians, degrees, and seconds of arc. How far apart must two objects be on the surface of the Moon if they are to be resolvable by the Palomar telescope? The Earth-Moon distance is \(3.844 \times 10^{8} \mathrm{m} ;\) take \(\lambda_{0}=550 \mathrm{nm} .\) How far apart must two objects be on the Moon if they are to be distinguished by the eye? Assume a pupil diameter of \(4.00 \mathrm{mm}\).

Light having a frequency of \(4.0 \times 10^{14} \mathrm{Hz}\) is incident on a grating formed with 10000 lines per centimeter. What is the highestorder spectrum that can be seen with this device? Explain.

If you peered through a 0.75 -mm hole at an eye chart, you would probably notice a decrease in visual acuity. Compute the angular limit of resolution, assuming that it's determined only by diffraction; take \(\lambda_{0}=550 \mathrm{nm} .\) Compare your results with the value of \(1.7 \times 10^{-4} \mathrm{rad}\) which corresponds to a 4.0 -mm pupil.

Imagine two aperture screens arranged to produce two Fraunhofer diffraction patterns. One contains 8 very narrow closely spaced parallel slits, the other 16 such slits. All else being equal, compare the two irradiance distributions. That is, how many subsidiary maxima between consecutive principal maxima will each pattern contain? If the irradiance of the zeroth-order peak of the 16 -slit pattern is set equal to \(1.0,\) how big will the corresponding peak be for the 8 -slit pattern? Which arrangement produces wider principal maxima? Draw a rough sketch of each.

A narrow single slit (in air) in an opaque screen is illuminated by infrared from a He-Ne laser at \(1152.2 \mathrm{nm}\), and it is found that the center of the tenth dark band in the Fraunhofer pattern lies at an angle of \(6.2^{\circ}\) off the central axis. Determine the width of the slit. At what angle will the tenth minimum appear if the entire arrangement is immersed in water \(\left(n_{w}=1.33\right)\) rather than air \(\left(n_{a}=1.00029\right) ?\)

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