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Imagine that you are staring at a star. You have dilated pupils, each with a diameter of \(6.00 \mathrm{mm}\). The retina is about \(21.0 \mathrm{mm}\) from the pupil in a typical eye. Considering that the index of refraction of the vitreous humor is 1.337 , determine the size of the Airy disk on your retina. Assume a mean vacuum wavelength of \(550 \mathrm{nm}\).

Short Answer

Expert verified
The Airy disk on the retina is approximately 3.53 μm.

Step by step solution

01

Understand the Airy Disk Formula

The Airy disk is the central bright region of the diffraction pattern created when light passes through a circular aperture, such as the pupil of an eye. The diameter of the Airy disk can be determined using the formula \( d = \frac{2.44 \times \lambda \times f}{D} \), where \( \lambda \) is the wavelength of light, \( f \) is the focal length of the system (distance from pupil to retina), and \( D \) is the diameter of the pupil.
02

Calculate the Wavelength in the Eye

The wavelength of light in a medium is given by \( \lambda_{medium} = \frac{\lambda_{vacuum}}{n} \), where \( n \) is the index of refraction. Here, \( \lambda_{vacuum} = 550 \mathrm{nm} \) and \( n = 1.337 \). Calculate the wavelength of light in the vitreous humor as follows: \[ \lambda_{eye} = \frac{550 \mathrm{nm}}{1.337} \approx 411.18 \mathrm{nm}. \]
03

Insert Values into the Airy Disk Formula

We have: \( \lambda = 411.18 \mathrm{nm} = 411.18 \times 10^{-9} \mathrm{m} \), \( f = 21.0 \mathrm{mm} = 0.021 \mathrm{m} \), and \( D = 6.00 \mathrm{mm} = 0.006 \mathrm{m} \).Insert these into the formula: \[ d = \frac{2.44 \times 411.18 \times 10^{-9} \times 0.021}{0.006}. \]
04

Calculate the Diameter of the Airy Disk

Now calculate \( d: \) \[ d = \frac{2.44 \times 411.18 \times 10^{-9} \times 0.021}{0.006} \approx 3.53 \times 10^{-6} \mathrm{m}. \] Convert into micrometers by multiplying by \( 10^6 \): \[ d \approx 3.53 \mathrm{\mu m}. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Diffraction Pattern
When light waves encounter an obstacle or a slit that is comparable in size to their wavelength, they bend around it and create patterns of light and dark fringes known as diffraction patterns.
These patterns are crucial in optics because they show how light interacts with objects and apertures.
The Airy disk, for example, is part of this pattern. It is the bright central disk seen when light passes through a circular aperture, such as the eye's pupil. Understanding diffraction patterns helps us comprehend the limit of resolution for optical systems. For a circular aperture like the eye, the ability to resolve fine details is limited by the size of this Airy disk.
  • The smaller the aperture, the larger the Airy disk, and hence, the less detail that can be resolved.
  • This concept is vital in understanding phenomena in both natural vision and artificial optical systems like cameras and telescopes.
Wavelength of Light
The wavelength of light is the distance between consecutive peaks of a wave, usually measured in nanometers (nm). It is a fundamental property of light that affects its color.
The visible spectrum ranges from about 400 nm (violet) to 700 nm (red).In the context of optics, when light enters a different medium, its speed changes, altering its wavelength. The formula \[ \lambda_{\text{medium}} = \frac{\lambda_{\text{vacuum}}}{n} \]where \( n \) is the index of refraction, allows us to calculate the adjusted wavelength in the medium. In our exercise, the vacuum wavelength is 550 nm, which reduces when passing into the eye's vitreous humor (with an index of refraction of 1.337) to about 411.18 nm.
  • Light's wavelength directly influences diffraction patterns, with shorter wavelengths producing smaller Airy disks.
  • This relationship emphasizes the need to consider both medium and wave properties in optical calculations.
Index of Refraction
The index of refraction \( n \) is a measure of how much a medium slows down light compared to its speed in a vacuum. Defined as the ratio between the speed of light in a vacuum and the speed of light in a medium, it has no unit.In the context of this exercise, the index for the vitreous humor is 1.337.A higher index of refraction means light travels slower in the medium and bends more upon entering or exiting.
  • This property is essential for lenses and optics, as it affects focal length and, consequently, the size of images formed.
  • In the human eye, this affects how light is focused on the retina, influencing things like clarity and focus.
Understanding the index of refraction is crucial for applications ranging from designing corrective eyewear to creating precise scientific instruments.
Circular Aperture
A circular aperture is simply an opening with a round shape, such as the pupil of an eye or the lens of a camera.
The size of this opening plays a crucial role in how light is processed. In the context of diffraction and the Airy disk, the diameter of the circular aperture determines the size of the diffraction pattern created. This pattern dictates the resolution and clarity of images produced. The narrower the aperture, the larger the diffraction pattern, which can blur the image. For the human eye, the pupil acts as this aperture. When dilated, it can let in more light, but can also increase the Airy disk size, leading to slightly less sharp vision in low light.
  • Understanding circular apertures helps in grasping concepts like depth of field and exposure in photography.
  • It is also vital in designing optical instruments to balance light gathering and resolution.
This principle underlies many scientific and everyday optical phenomena.

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Most popular questions from this chapter

The angular distance between the center and the first minimum of a single-slit Fraunhofer diffraction pattern is called the half-angular breadth; write an expression for it. Find the corresponding half-linear width when no focusing lens is present and the distance from the slit to the viewing screen is \(L\). Notice that the half-linear width is also the distance between the successive minima.

Imagine an opaque screen containing 30 randomly located circular holes. The light source is such that every aperture is coherently illuminated by its own plane wave. Each wave in turn is completely incoherent with respect to all the others. Describe the resulting far-field diffraction pattern.

A 2.4 -cm-diameter positive lens with a focal length of \(100 \mathrm{cm}\) forms an image of a small far-away red \((656 \mathrm{nm})\) hydrogen lamp. Determine the linear size of the central circular spot appearing on the focal plane.

The Mount Palomar telescope has an objective mirror with a \(508-\mathrm{cm}\) diameter. Determine its angular limit of resolution at a wavelength of \(550 \mathrm{nm}\), in radians, degrees, and seconds of arc. How far apart must two objects be on the surface of the Moon if they are to be resolvable by the Palomar telescope? The Earth-Moon distance is \(3.844 \times 10^{8} \mathrm{m} ;\) take \(\lambda_{0}=550 \mathrm{nm} .\) How far apart must two objects be on the Moon if they are to be distinguished by the eye? Assume a pupil diameter of \(4.00 \mathrm{mm}\).

Sunlight impinges on a transmission grating that is formed with 5000 lines per centimeter. Does the third-order spectrum overlap the second-order spectrum? Take red to be \(780 \mathrm{nm}\) and violet to be \(390 \mathrm{nm}\)

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