Chapter 9: Problem 16
A stream of electrons, each having an energy of \(0.5 \mathrm{eV}\), impinges on a pair of extremely thin slits separated by \(10^{-2} \mathrm{mm}\). What is the distance between adjacent minima on a screen \(20 \mathrm{m}\) behind the slits? \(\left(m_{e}=9.108 \times 10^{-31} \mathrm{kg}, 1 \mathrm{eV}=1.602 \times 10^{-19} \mathrm{J} .\right)\)
Short Answer
Step by step solution
Find the Wavelength of the Electrons
Apply the Double-Slit Interference Formula
Calculation for Adjacent Minima
Final Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
De Broglie Wavelength
- \( \lambda = \frac{h}{p} \)
To find the de Broglie wavelength of an electron with a kinetic energy, you need to first determine its momentum. The relationship between energy \( (E) \) and momentum \( (p) \) is given by:
- \( E = \frac{p^2}{2m} \)
- \( p = \sqrt{2mE} \)
Double-Slit Experiment
- The condition for constructive interference (bright fringes) is \( d \sin \theta = m \lambda \).
- For destructive interference (dark fringes), which are of interest in the context of finding the distance between adjacent minima, the condition is \( d \sin \theta = (m+0.5) \lambda \).
Interference Pattern
- \( y = \frac{(m + 0.5)\lambda L}{d} \)
- The adjacent minimum is found by \( \Delta y = \frac{\lambda L}{d} \)