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A plane EM wave of wave intensity \(10 \mathrm{~W} / \mathrm{m}^{2}\) strikes a small mirror of area \(20 \mathrm{~cm}^{2}\), held perpendicular to the approaching wave. The radiation force on the mirror will be (a) \(6.6 \times 10^{-11} \mathrm{~N}\) (b) \(1.33 \times 10^{-11} \mathrm{~N}\) (c) \(1.33 \times 10^{-10} \mathrm{~N}\) (d) \(6.6 \times 10^{-10} \mathrm{~N}\)

Short Answer

Expert verified
(c) \(1.33 \times 10^{-10} \mathrm{~N}\)

Step by step solution

01

Understand the given values

We have a given wave intensity \(I = 10 \mathrm{~W} / \mathrm{m}^{2}\) and the area of the mirror \(A = 20 \mathrm{~cm}^{2}\). Note that \(20 \mathrm{~cm}^{2} = 0.002 \mathrm{~m}^{2}\) as we need the area in square meters.
02

Formula for radiation pressure

The radiation pressure \(P\) on a perfectly reflecting surface is given by:\[ P = \frac{2I}{c} \] where \(c = 3 \times 10^{8} \mathrm{~m/s}\) is the speed of light. This formula accounts for the wave being reflected.
03

Compute radiation pressure

Substitute the given intensity into the formula to find the pressure:\[ P = \frac{2 \times 10}{3 \times 10^{8}} \] This results in: \[ P = \frac{20}{3 \times 10^{8}} = 6.67 \times 10^{-8} \mathrm{~N/m}^{2} \]
04

Calculate radiation force

The force \(F\) exerted by the radiation is calculated by multiplying the pressure by the area of the surface: \[ F = P \times A \] Substituting the known values gives: \[ F = 6.67 \times 10^{-8} \times 0.002 = 1.33 \times 10^{-10} \mathrm{~N} \]
05

Choose the correct option

The calculated radiation force \(F = 1.33 \times 10^{-10} \mathrm{~N}\) matches option (c).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Waves
Electromagnetic waves are fundamental to understanding both radiation pressure and radiation force. These waves are formed by the coupling of electric and magnetic fields, hence the name 鈥渆lectromagnetic.鈥 They propagate through space at the speed of light and encompass a vast spectrum beginning from long radio waves up to high-energy gamma rays.

A key characteristic of electromagnetic waves is their ability to carry energy and momentum. This is important when discussing their interaction with objects, like mirrors, where they can exert a force. Electromagnetic waves can reflect, refract, or get absorbed when they encounter different materials. In the case of the original exercise, the wave is reflecting off a mirror, which is essential in calculating radiation pressure.
Radiation Force
Radiation force is the force exerted by electromagnetic waves on a surface. This happens due to the momentum transfer from the wave to the object it hits. Although typically very small, this force becomes significant in contexts such as solar sails used in space propulsion.

The main formula for calculating radiation force is based on radiation pressure, which is the pressure exerted by the electromagnetic wave. For a perfectly reflecting surface, the formula is: \[ P = \frac{2I}{c} \]This formula reflects the change in momentum as the wave bounces back off the surface. To find the force, you would then multiply the pressure by the area of the surface that the waves hit:
  • \( F = P \times A \)
This simplification helps us calculate the small yet measurable impact forces that electromagnetic waves can have.
Wave Intensity
Wave intensity, denoted by \(I\), is a measure of the power carried by the wave per unit area. It is measured in watts per square meter (\(\mathrm{W/m^2}\)). Higher wave intensity means more energy is being transported, and this is directly proportional to the force exerted when the wave strikes a surface.

The relationship between intensity and other wave properties is crucial for understanding interactions like the one described in the original exercise.
  • Intensity is proportional to the square of the wave amplitude.
  • A higher wave intensity results in greater energy transfer.
Thus, intensity plays a significant role in determining the radiation force, since it's directly used to calculate radiation pressure on a surface.
Speed of Light
The speed of light, denoted by \(c\), is a fundamental physical constant. It is considered the fastest speed at which all energy, matter, and information in the universe can travel. The speed of light in a vacuum is approximately \(3 \times 10^8 \) meters per second (\(\mathrm{m/s}\)).

When calculating radiation pressure, the speed of light becomes a crucial factor as it divides the wave intensity in the formula:\[ P = \frac{2I}{c} \]This formula illustrates the inverse relationship between the speed of light and radiation pressure for a given intensity. As such, understanding the concept and value of light speed is pivotal when working with equations that describe the forces exerted by electromagnetic waves.

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Most popular questions from this chapter

A beam of light travelling along \(x\) -axis is described by the electric field, \(E_{y}=\left(600 \mathrm{Vm}^{-1}\right) \sin \omega(t-x / c)\) then maximum magnetic force on a charge \(q=2 e\) moving along \(y\) -axis with a speed of \(3.0 \times 10^{7} \mathrm{~ms}^{-1}\) is \(\left(e=1.6 \times 10^{-19} \mathrm{C}\right)\) (a) \(19.2 \times 10^{-17} \mathrm{~N}\) (b) \(1.92 \times 10^{-17} \mathrm{~N}\) (c) \(0.192 \mathrm{~N}\) (d) none of these

The average energy density of an electromagnetic wave given by \(E=(50 \mathrm{~N} / \mathrm{C}) \sin (\omega t-k x)\) will be nearly: (a) \(10^{-8} \mathrm{~J} / \mathrm{m}^{3}\) (b) \(10^{-7} \mathrm{~J} / \mathrm{m}^{3}\) (c) \(10^{-6} \mathrm{~J} / \mathrm{m}^{3}\) (d) \(10^{-5} \mathrm{~J} / \mathrm{m}^{3}\)

In an electromagnetic wave, the average energy density is associated to (a) electric field only (b) magnetic field only (c) equally with electric and magnetic fields (d) average energy density is zero

A free electron is placed in the path of a plane electromagnetic wave. The electron will start moving (a) along the electric field (b) along the magnetic filed (c) along the direction of propagation of the wave (d) in a plane containing the magnetic field and the direction of propagation

The correct sequence of the increasing wavelength of the given radiation sources is (a) radioactive sources, X-ray tube, crystal oscillator, sodium vapour lamp (b) radioactive sources, X-ray tube, sodium vapour lamp, crysta oscillator (c) X-ray tube, radioactive sources, sodium vapour lamp, crystal oscillator (d) X-rays tube, crystal oscillator, radioactive sources, sodium vapour lamp

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