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Two equal -ve charges \(-q\) are fixed at the point \((0, a)\) and \((0,-a)\) on the \(y\) -axis. A positive charge \(Q\) is released from rest at the point \((2 a, 0)\) on the \(x\) -axis. The charge will (a) execute SHM about the origin (b) move to the origin and remain at rest (c) move to infinity (d) execute oscillatory but not SHM

Short Answer

Expert verified
The charge will execute SHM about the origin (option a).

Step by step solution

01

Understanding the Setup

We have two negative charges \( -q \) located at \( (0, a) \) and \( (0, -a) \) on the y-axis. A positive charge \( Q \) is initially positioned at \( (2a, 0) \) on the x-axis. We need to determine the motion of this charge.
02

Analyzing the Forces

The forces acting on the positive charge \( Q \) are due to both negative charges \( -q \). Because \( Q \)'s initial position is on the x-axis and symmetric with respect to the y-axis, the y-components of the forces cancel each other, leaving a resultant force directed towards the origin on the x-axis.
03

Determining the Nature of Motion

At the initial position, the resultant force on \( Q \) is towards the origin, following Coulomb's law. As \( Q \) moves towards the origin, the forces always direct it back towards the origin due to symmetry. This forms a restoring force, similar to that in simple harmonic motion about the origin.
04

Effectively Identifying the Motion

Given that the restoring force operates through symmetric forces linearly directed to the origin, \( Q \) will indeed execute oscillatory motion as it moves back and forth. This aligns with the conditions for simple harmonic motion (SHM) since the net force is proportional and opposite to the displacement from the origin.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coulomb's Law
Coulomb's Law is all about understanding how charged particles interact. According to Coulomb's Law, the force between any two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. It is described by the formula:
  • \( F = k \frac{|q_1 \, q_2|}{r^2} \)
where:
  • \( F \) is the electrostatic force between the charges,
  • \( q_1 \) and \( q_2 \) are the magnitudes of the charges,
  • \( r \) is the distance between the centers of the two charges, and
  • \( k \) is Coulomb's constant, approximately equal to \( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \).
This law helps us determine the magnitude and direction of the force experienced by a charged particle. In the given scenario, the positive charge \( Q \) experiences forces from the two fixed negative charges \( -q \). Because these negative charges are symmetrically placed above and below the x-axis, their individual forces on \( Q \) combine, leading to a net force toward the origin along the x-axis.
Simple Harmonic Motion
Simple Harmonic Motion (SHM) is a type of oscillatory motion characterized by a restoring force proportional to displacement. In SHM, if you displace an object from its equilibrium position, the system exerts a force to bring it back. This force is described as:
  • \( F = -kx \)
Here:
  • \( F \) is the restoring force,
  • \( k \) is a constant related to the stiffness of the system, and
  • \( x \) is the displacement from equilibrium.
In this exercise, the positive charge \( Q \) experiences such a restoring force due to the symmetrical positioning of the fixed charges. When \( Q \) moves along the x-axis, it experiences a force that is always aimed toward the origin, behaving like SHM. The symmetrical forces ensure that, as \( Q \) is displaced from the origin, the system acts to restore it back, explaining why the charge goes into oscillation.
Forces on Charges
The forces on charged particles are essential for analyzing their motion. In electrostatics, analyzing forces involves examining interactions between multiple charges. Here, the situation is straightforward because of symmetry. Each negative charge \(-q\) exerts a force on the positive charge \(Q\). The forces have both x and y-components:
  • The y-components are equal and opposite, thus cancel each other out.
  • The x-components add up, giving a net force towards the origin.
This net force causes the positive charge \( Q \) to move towards the origin when released from rest. As \( Q \) passes through the origin, the forces continue directing it toward the opposite side. This results in a continuous back-and-forth motion characteristic of SHM. Understanding the resultant force's direction is crucial in predicting the nature of motion for the charged object.

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