Chapter 7: Problem 18
Two circular discs \(A\) and \(B\) are of equal masses and thicknesses but made of
metal with densities \(d_{A}\) and \(d_{B}\left(d_{A}>d_{B}\right)\). If their
moments of inertia about an axis passing through their centres and
perpendicular to circular faces be \(I\), and \(I_{B}\), then
(a) \(I_{A}=I_{B}\)
(b) \(I_{A}>I_{B}\)
(c) \(I_{A}
Short Answer
Step by step solution
Understanding Disc Properties
Density and Volume Relationship
Calculating Radii of Discs
Formula for Moment of Inertia
Comparing Moments of Inertia
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Density
- \[ d = \frac{M}{V} \]
- Where \(d\) is the density, \(M\) is the mass, and \(V\) is the volume.
Circular Disc
Rotational Dynamics
- \[ I = \frac{1}{2} M R^2 \]
- Where \(I\) denotes the moment of inertia, \(M\) is the mass, and \(R\) is the radius.
Mass and Volume Relationship
- \[ V = \frac{M}{d} \]
- Where \(V\) is volume, \(M\) is mass, and \(d\) is density.