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In a composite rod, when two rods of different lengths and of the same area of cross-section are joined end to end, then if \(K\) is the effective coefficient of thermal conductivity, \(\frac{l_{1}+l_{2}}{K}\) is equal to: (a) \(\frac{l_{1}}{K_{1}}-\frac{l_{2}}{K_{2}}\) (b) \(\frac{l_{1}}{K_{2}}-\frac{l_{2}}{K_{1}}\) (c) \(\frac{l_{1}}{K_{1}}+\frac{l_{2}}{K_{2}}\) (d) \(\frac{l_{1}}{K_{2}}+\frac{l_{2}}{K_{1}}\)

Short Answer

Expert verified
The correct answer is (c) \(\frac{l_1}{K_1} + \frac{l_2}{K_2}\).

Step by step solution

01

Understand the System

We have a composite rod made of two different materials, each with different thermal conductivities. The rods are joined end-to-end, which means they have the same area of cross-section.
02

Formula for Effective Thermal Conductivity

When two rods of thermal conductivities \(K_1\) and \(K_2\) are joined end-to-end, the system behaves as a series of resistances in thermal conduction. The formula for effective thermal conductivity \(K\) is given by:\[\frac{l_1 + l_2}{K} = \frac{l_1}{K_1} + \frac{l_2}{K_2}.\]
03

Solution Comparison

Using the formula \(\frac{l_1 + l_2}{K} = \frac{l_1}{K_1} + \frac{l_2}{K_2}\), we need to identify the matching option:- Option (c) is \(\frac{l_1}{K_1} + \frac{l_2}{K_2}\).- The other options do not match this formulation.
04

Final Answer Selection

The correct option that reflects the derived formula is (c), which matches \(\frac{l_1}{K_1} + \frac{l_2}{K_2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Composite Rod
When discussing thermal conductivity, a composite rod is an interesting phenomenon. Imagine combining two rods made of different materials. Each rod might have its own thermal conducting ability, meaning they conduct heat at different rates. In our scenario, these rods are joined end-to-end, meaning they form a longer continuous path for heat to travel. Both rods have the same cross-sectional area, which is essential for determining how heat transfers through them.

The concept of a composite rod is helpful for examining how thermal resistance operates in series, similar to resistors in electrical circuits. This system allows us to explore how different materials interact when it comes to conducting heat. Understanding a composite rod's behavior helps in designing materials for various applications, like heat exchangers or insulated systems, where temperature regulation is crucial.
Effective Thermal Conductivity
When dealing with a composite rod, understanding effective thermal conductivity is key. It combines the thermal properties of different sections of the rod. The effective thermal conductivity, denoted later by \( K \), is a measure of how effectively the entire system conducts heat as a whole rather than as individual elements.

For example, consider rods with lengths \( l_1 \) and \( l_2 \), each with thermal conductivities \( K_1 \) and \( K_2 \), respectively. The concept of effective thermal conductivity allows us to calculate \( K \) through the formula for series resistance:
  • \[ \frac{l_1 + l_2}{K} = \frac{l_1}{K_1} + \frac{l_2}{K_2} \]
This equation shows that the overall effectiveness of heat conduction depends on the properties of each segment. It also indicates that composite rods can behave in ways that differ significantly from their individual components. This is particularly valuable for engineers and scientists working on systems where specific thermal management is required.
Series Resistance in Thermal Conductivity
Thermal resistance operates similarly to electrical resistance, except in the context of heat flow. When components are joined end-to-end, each part adds resistance to the overall system, making it harder for heat to travel through the entire composite rod.

Series resistance in thermal conductivity requires us to view each segment of our composite rod as a piece of the larger puzzle. The formula
  • \[ \frac{l_1 + l_2}{K} = \frac{l_1}{K_1} + \frac{l_2}{K_2} \]
illustrates how the resistances combine to affect the system's thermal conductance. Each length \( l_1 \) and \( l_2 \) divided by their respective conductivities \( K_1 \) and \( K_2 \) contribute separately to the total resistance, much like resistors in an electronic circuit.

Effectively, using this concept allows us to compute the overall thermal performance of a system. This is crucial when dealing with layered materials or insulated pipes, where the goal is to control the heat transfer rates effectively.

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