Chapter 15: Problem 33
A bullet of mass \(10 \times 10^{-3} \mathrm{~kg}\) moving with a speed of \(20 \mathrm{~ms}^{-1}\) hits an ice block \(\left(0^{\circ} \mathrm{C}\right)\) of \(990 \mathrm{~g}\) kept at rest on a frictionless floor and gets embedded in it. If ice takes \(50 \%\) of KE lost by the system, the amount of ice melted (in grams) approximately is: \((J=4.2 \mathrm{~J} / \mathrm{cal} ;\) latent heat of ice \(=80 \mathrm{cal} / \mathrm{g}\) ) (a) 6 (b) 3 (c) \(6 \times 10^{-3}\) (d) \(3 \times 10^{-3}\)
Short Answer
Step by step solution
Understand the Problem
Calculate Initial Kinetic Energy
Calculate Final Speed Post-collision
Calculate Final Kinetic Energy
Determine Kinetic Energy Lost
Calculate Energy Received by Ice
Convert Energy to Calories
Calculate Amount of Ice Melted
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Kinetic Energy
- \( m \) is the mass of the object in kilograms.
- \( v \) is the velocity of the object in meters per second.