/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 62 The work done in an adiabatic ch... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The work done in an adiabatic change in a particular gas depends upon only (a) change in volume (b) change in pressure (d) none of these (c) change in temperature

Short Answer

Expert verified
The work done depends on change in temperature (Option c).

Step by step solution

01

Understanding Adiabatic Process

An adiabatic process is one where no heat is exchanged with the surroundings. In an adiabatic process, the change in internal energy is equal to the work done on or by the system. This means the work done only depends on the change in internal energy.
02

Identifying the Correct Parameter

Since work done is related to the change in internal energy, and in an adiabatic process for an ideal gas, the internal energy change is directly proportional to the change in temperature. Thus, the work done primarily depends on the change in temperature.
03

Verifying the Alternatives

Analyzing the options, we see that the work done is not dependent solely on change in volume or pressure, since both of these can change without a change in internal energy, especially in non-isothermal processes. The significant factor that affects internal energy directly in an adiabatic process is temperature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Internal Energy
In an adiabatic process, the primary concept revolves around internal energy. Think of internal energy as the energy contained within a system due to the motion and position of its molecules. This energy can change depending on whether work is done on or by the system. In mathematical terms, the change in internal energy \( \Delta U \) for an adiabatic process can be represented as the difference between the initial and final internal energies of the system. Since no heat is exchanged in an adiabatic process, any change in internal energy is equal to the work done on or by the system:
\[ \Delta U = -W \]
  • "No heat exchange" means all energy transformations are solely within the system.
  • "Internal energy changes" imply it depends on the system's temperature and state.
Understanding this relationship helps us appreciate why internal energy plays a central role in adiabatic processes.
Work Done
In the context of an adiabatic process, work done is integrally linked with changes in internal energy. Work done in such processes can either compress or expand a gas, affecting its state without heat transfer. The equation for work done \( W \) in relation to an adiabatic process is derived from altering internal energy:
\[ W = - \Delta U \]This equation reinforces that, in the absence of heat exchange, every bit of work done is reflected in the change in internal energy. The work done is also related to the physical movement, such as the volume change in a gas:
  • For a "compression" process, work is positive as energy is added to the system.
  • For an "expansion" process, work is negative, meaning energy is taken from the system.
Thus, work done revolves around the transformation and transfer of energy within the system, specifically altering internal energy under adiabatic conditions.
Change in Temperature
The change in temperature is a vital aspect of understanding adiabatic processes. It directly relates to changes in internal energy, which happens without any heat exchange in the system's environment. For gases, the internal energy is largely dependent on temperature, simplifying how we view work done in adiabatic conditions. Thus, the change in temperature \( \Delta T \) affects how work is performed in these processes through equations like
\[ \Delta U = nC_v \Delta T \]Where
  • \( n \) is the number of moles,
  • \( C_v \) is the molar heat capacity at constant volume.
The equation illustrates that the change in internal energy is proportional to the change in temperature, considering that \( C_v \) and \( n \) are constants during an adiabatic process. Therefore, as the temperature changes, so does the internal energy, directly influencing work done and exemplifying why temperature change is an essential factor in such processes.

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Most popular questions from this chapter

A copper constantan thermocouple produces an emf of 40 microvolt per degree celsius in the linear range of temperature. A galvanometer of resistance 10 ohm and capable of detecting a current of one microampere is employed. What is the smallest temperature that can be detected by this arrangement? (a) \(0.25^{\circ} \mathrm{C}\) (b) \(1.00^{\circ} \mathrm{C}\) (c) \(0.50^{\circ} \mathrm{C}\) (d) \(2.00^{\circ} \mathrm{C}\)

Find the amount of work done to increase the temperature of one mole of ideal gas by \(30^{\circ} \mathrm{C}\), if it is expanding under the condition \(V \propto T^{2 / 3}:(R=8.31 \mathrm{~J} /\) mol-K ) (a) \(16.62 \mathrm{~J}\) (b) \(166.2 \mathrm{~J}\) (c) \(1662 \mathrm{~J}\) (d) \(1.662 \mathrm{~J}\)

The temperature of the gas is a measure of (a) the average translational kinetic energy of the gas molecules (b) the average potential energy of the gas molecules (c) the average distance of the gas molecules (d) the size of the gas molecules

When heat is added to a system, which of the following is not possible? (a) Internal energy of the system increase (b) Work is done by the system (c) Neither internal energy increases nor work is done by the system (d) Internal energy increases and also work is done by the system

The temperature of a thin uniform circular disc, of one metre diameter is increased by \(10^{\circ} \mathrm{C}\). The percentage increase in moment of inertia of the disc about an axis passing through its centre and perpendicular to the circular face (linear coefficient of expansion \(\left.=11 \times 10^{-6}{ }^{\circ} \mathrm{C}^{-1}\right)\) (a) \(0.0055\) (b) \(0.011\) (c) \(0.022\) (d) \(0.044\)

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