Chapter 11: Problem 87
The phase difference between two points separated by \(0.8 \mathrm{~m}\) in a wave of frequency \(120 \mathrm{~Hz}\) is \(0.5 \pi\). The wave velocity is (a) \(144 \mathrm{~m} / \mathrm{s}\) (b) \(256 \mathrm{~m} / \mathrm{s}\) (c) \(384 \mathrm{~m} / \mathrm{s}\) (d) \(720 \mathrm{~m} / \mathrm{s}\)
Short Answer
Step by step solution
Identify Known Quantities
Write the Phase Difference Formula
Solve for Wavelength \(\lambda\)
Use Wave Velocity Formula
Choose the Correct Option
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Phase Difference
Calculating phase difference involves the formula \( \Delta \phi = \frac{2\pi \cdot \Delta x}{\lambda} \). Here, \( \Delta x \) is the distance between two points, and \( \lambda \) is the wavelength. This formula helps us quickly determine the phase relationship between two points on a wave, crucial for applications like signal processing and understanding wave patterns.
Wavelength Calculation Made Easy
- \(\Delta \phi = \frac{2\pi \cdot \Delta x}{\lambda} \)
- Solving for \( \lambda \) gives us: \( \lambda = \frac{2\pi \cdot \Delta x}{\Delta \phi} \)
In our exercise, with a phase difference of \( 0.5 \pi \) and the distance \(0.8 \mathrm{~m} \), we found \( \lambda = 3.2 \mathrm{~m} \). Understanding wavelength is essential in various practical applications, like designing antennas or understanding light properties.
Always remember, the longer the wavelength, the lower the frequency and vice-versa. This inverse relationship tells us a lot about the wave's behavior and energy.
Decoding Wave Frequency
The frequency plays a pivotal role in calculating wave velocity with the relationship \( v = f \cdot \lambda \), where \( v \) is the wave velocity, \( f \) is the frequency, and \( \lambda \) is the wavelength. Thus, calculating wave velocity requires knowing both frequency and wavelength, underscoring the interconnectedness between these quantities.
- In our scenario, using \( f = 120 \mathrm{~Hz} \) and \( \lambda = 3.2 \mathrm{~m} \), we found the wave velocity to be \(384 \mathrm{~m/s}\).