Chapter 11: Problem 17
The equation of motion of a particle executing simple harmonic motion is \(a+16 \pi^{2} x=0 .\) In this equation, \(a\) is the linear acceleration in \(\mathrm{m} / \mathrm{s}^{2}\) of the particle at a displacement \(x\) in metre. The time period in simple harmonic motion is (a) \(\frac{1}{4}\) second (b) \(\frac{1}{2}\) second (c) 1 second (d) 2 seconds
Short Answer
Step by step solution
Understand the equation of motion
Relate acceleration to displacement
Compare the equations to determine \( \omega^2 \)
Calculate the time period \( T \)
Verify the result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equation of Motion
- \(a\) - the linear acceleration of the particle.
- \(x\) - the displacement from an equilibrium position.
Angular Frequency
- Angular frequency has units of radians per second, indicating how many radians an oscillatory motion completes per second.
- From the given equation \(a = -16\pi^2 x \), we can deduce that \(\omega^2 = 16\pi^2\), therefore \(\omega = 4\pi\).
Time Period
- \[ T = \frac{2\pi}{4\pi} = \frac{1}{2} \ \text{seconds} \]
Acceleration and Displacement Relationship
- Acceleration is directly proportional to the displacement.
- The negative sign indicates that the acceleration is in the opposite direction of the displacement, enforcing a restoring force.