Chapter 11: Problem 103
Two particles \(P\) and \(Q\) describe SHM of same amplitude \(a\), frequency \(\mathrm{v}\) along the same straight line. The maximum distance between the two particles is \(a \sqrt{2}\). The initial phase difference between the particles is (a) zero (b) \(\pi / 2\) (c) \(\pi / 6\) (d) \(\pi / 3\)
Short Answer
Step by step solution
Understand Harmonic Motion
Express the Maximum Distance Condition
Use Trigonometric Identity
Simplify the Expression
Determine Phase Difference
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Phase Difference
This equation tells us how the displacement varies with time. The phase term \( \phi \) is what shifts the position of this oscillation in time. When two waves are 'in phase', their phase difference \( \phi_P - \phi_Q \) is zero, meaning they reach their maximum displacement simultaneously.
The phase difference that makes the particles furthest apart in the given problem is \( \pi/2 \). This special case means that when one particle is at a maximum displacement, the other is at an equilibrium position, leading to a maximum distance between their positions. The negative sign and periodic considerations in the solution explain how we arrive at a unique value.
Amplitude
The amplitude is a measure of the extent of motion, and in physical terms, it can be thought of as the 'size' of the motion. If the amplitude is large, the particle travels a greater distance from its equilibrium position during each cycle.
In practical terms, amplitude affects the maximum potential energy of the oscillating system, as energy is proportional to the square of the amplitude. Understanding this concept is crucial when analyzing systems undergoing SHM, as it directly influences the energy and distance dynamics of oscillating particles.
Angular Frequency
This frequency is related to the more common concept of frequency \( f \), often measured in cycles per second (hertz), by the relationship \( \omega = 2\pi f \). This shows that angular frequency takes into account the circular motion aspect in SHM, emphasizing how far the particle has traveled around a circle rather than counting the number of full cycles.
In the given problem, both particles \( P \) and \( Q \) share the same angular frequency since they have the same frequency, ensuring that their cycles are synchronized in terms of speed but possibly differ due to their phase difference, which we previously explored.