Chapter 1: Problem 15
A thin ('density' of \(1 \mathrm{mg} \mathrm{cm}^{-2}\) ) target of \({ }^{24} \mathrm{Mg}\) ( \(M_{A}=24.3\) atomic mass units) is bombarded with a \(10 \mathrm{nA}\) beam of alpha particles. A detector subtending a solid angle of \(2 \times 10^{-3}\) sr records 20 protons per second. If the scattering is isotropic, determine the cross-section for the \({ }^{24} \mathrm{Mg}(\alpha, p){ }^{27} \mathrm{Al}\) reaction.
Short Answer
Step by step solution
Understanding the Given Data
Formula for Cross-Section
Convert Beam Current to Particles per Second
Determine Areal Density of the Target
Calculate the Cross-Section
Final Calculation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Isotropic Scattering
Real-world applications:
- It simplifies experimental setups because you don't have to adjust for variation in scattering angles.
- It is important when data from detectors covering small angles are extrapolated to understand the whole process.
Reaction Rate
Key Considerations:
- The reaction rate depends on the number of incoming particles, the likelihood of interaction, and the target properties.
- In calculations, it allows us to establish a relationship between experimental observations (detection rates) and theoretical predictions (cross-sections).
Beam Intensity
Points to Remember:
- Beam intensity affects the chance of nuclear reactions occurring because more particles yield more interactions.
- Knowledge of beam intensity allows researchers to adjust experimental conditions to study nuclear interactions under controlled circumstances.
Areal Density
- It is crucial for calculating the total number of atoms interacting with the beam.
- Helps in predicting the reaction outcome based on the availability of target atoms.