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At what angle should a ray of light be incident on the face of a prism of refracting angle \(60^{\circ}\) so that it just suffers total internal reflection at the other face? The refractive index of the material of the prism is \(1.524 .\)

Short Answer

Expert verified
The angle of incidence should be approximately \(29.7^{\circ}\).

Step by step solution

01

Identify Critical Angle

Total internal reflection occurs when the angle of incidence inside the prism is greater than the critical angle. To find the critical angle \( \theta_c \) we use the formula: \[ \sin(\theta_c) = \frac{1}{n} \] where \( n = 1.524 \).Thus, \[ \sin(\theta_c) = \frac{1}{1.524} \approx 0.656 \]Now, calculate \( \theta_c \) using \( \sin^{-1}(0.656) \).\[ \theta_c \approx 41.1^{\circ} \]
02

Apply Snell's Law at the First Face

The angle of refraction at the first face \( r \) must be such that the incident light ray inside the prism meets the second face at the critical angle. According to Snell's law at the first face:\[ n_1 \sin(i) = n_2 \sin(r) \]Here, \( n_1 = 1 \), \( n_2 = 1.524 \), and \( \sin(r) = \sin(60^{\circ} - \theta_c) \) which helps to satisfy the condition for total internal reflection.Calculate \( r = 60^{\circ} - \theta_c = 60^{\circ} - 41.1^{\circ} = 18.9^{\circ} \)
03

Calculate Angle of Incidence

Use the angle of refraction \( r = 18.9^{\circ} \) to find the angle of incidence \( i \). Rewriting Snell's law,\[ \sin(i) = 1.524 \times \sin(18.9^{\circ}) \]Calculate \( \sin(i) \) and then find \( i \) using the inverse sine function. \[ \sin(i) \approx 1.524 \times 0.324 \] \[ \sin(i) \approx 0.494 \]\( i = \sin^{-1}(0.494) \approx 29.7^{\circ} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Angle
In optics, the critical angle is the angle of incidence above which total internal reflection occurs when light is traveling from a medium with a higher refractive index to one with a lower refractive index. This concept is essential when determining how light behaves as it passes from one medium to another, such as from glass to air. The critical angle can be calculated using the formula:
  • \( \sin(\theta_c) = \frac{1}{n} \)
Here, \( \theta_c \) is the critical angle and \( n \) is the refractive index of the denser medium. For total internal reflection to happen, the light must hit the boundary inside a medium at an angle greater than the critical angle. Otherwise, it will refract out of the medium. In our example, the refractive index is given as 1.524. When we insert this into the critical angle formula, we get:
  • \( \sin(\theta_c) \approx 0.656 \)
Using the inverse sine function, we find \( \theta_c \approx 41.1^{\circ} \). This means that for any angle of incidence greater than 41.1 degrees, total internal reflection will occur.
Snell's Law
Snell's Law is a fundamental principle that describes how light rays bend as they pass through different media. It establishes the relationship between the angles of incidence and refraction with respect to the refractive indices of the two media. Mathematically, Snell's Law is represented as:
  • \( n_1 \sin(i) = n_2 \sin(r) \)
In this context, \( i \) is the angle of incidence, \( r \) is the angle of refraction, and \( n_1 \) and \( n_2 \) are the refractive indices of the two media, respectively. When light crosses from a less dense to a more dense medium (like from air into glass), it bends towards the normal. Conversely, when light exits the denser medium back to the less dense medium, it bends away from the normal. Snell's Law is crucial in determining how much bending occurs. In our example, Snell's Law helps calculate the angle of refraction inside the prism to ensure the light meets the second face exactly at the critical angle, allowing total internal reflection to occur.
Refractive Index
The refractive index, often denoted by the symbol \( n \), is a dimensionless number that describes how fast light travels through a medium compared to a vacuum. It's significant because it affects the bending or refraction of light as it moves between different substances.
  • For a given medium, the refractive index can be calculated using the equation:\[ n = \frac{c}{v} \]
where \( c \) is the speed of light in a vacuum and \( v \) is the speed of light in the medium. In our exercise, the refractive index of the prism material is 1.524, indicating the light moves slower in the prism compared to air. A higher refractive index means the medium is optically denser, and light will bend more as it enters the medium. The refractive index is crucial in calculating both the critical angle and applying Snell's Law. It defines how much the light will refract when entering or exiting a medium and dictates the angle at which total internal reflection occurs.

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