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A small candle, \(2.5 \mathrm{~cm}\) in size is placed at \(27 \mathrm{~cm}\) in front of a concave mirror of radius of curvature \(36 \mathrm{~cm}\). At what distance from the mirror should a screen be placed in order to obtain a sharp image? Describe the nature and size of the image. If the candle is moved closer to the mirror, how would the screen have to be moved?

Short Answer

Expert verified
Place the screen at 10.8 cm from the mirror. The image is real, inverted, and smaller. Move the screen further if the candle is closer.

Step by step solution

01

- Identify Given Data and Required Information

The problem provides us with the following information:- Object height: \(h_o = 2.5 \, \text{cm}\)- Object distance from the mirror: \(u = -27 \, \text{cm}\) (negative as per sign convention used in optics)- Radius of Curvature: \(R = 36 \, \text{cm}\) We need to find:1. The distance of the image \(v\) from the mirror for a sharp image.2. The nature (real or virtual) and size (magnified or diminished) of the image.3. How the screen's position needs to change if the object is moved closer.
02

- Calculate the Focal Length of the Mirror

For a concave mirror, the focal length \(f\) is half of the radius of curvature:\[ f = \frac{R}{2} = \frac{36 \mathrm{~cm}}{2} = 18 \mathrm{~cm} \]
03

- Apply the Mirror Formula

The mirror formula is given by:\[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]Plugging the values we have:\[ \frac{1}{18} = \frac{1}{v} + \frac{1}{-27} \]Solve for \(\frac{1}{v}\):\[ \frac{1}{v} = \frac{1}{18} + \frac{1}{27} \]
04

- Simplify and Solve for the Image Distance

Let's simplify the equation:\[ \frac{1}{v} = \frac{3}{54} + \frac{2}{54} \]Combine the terms:\[ \frac{1}{v} = \frac{5}{54} \]Now solve for \(v\):\[ v = \frac{54}{5} = 10.8 \mathrm{~cm} \]The image is located 10.8 cm from the mirror on the same side as the object (since \(v\) is positive).
05

- Determine the Nature and Size of the Image

The positive value of \(v\) indicates the image is real and on the same side as the object. To find the magnification \(m\):\[ m = \frac{v}{u} = \frac{10.8}{-27} \approx -0.4 \]Since \(|m| < 1\), the image is diminished. The negative sign indicates the image is inverted.
06

- Predict Screen Adjustment When Candle Moves Closer

When the object (candle) is moved closer to the mirror, it means \(u\) increases (less negative). Hence, solving the mirror equation results in a larger \(v\). Therefore, the screen would need to be moved further away from the mirror to reposition for the sharply focused image.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mirror Formula
When working with concave mirrors, the mirror formula is a fundamental equation that helps us determine important parameters like object distance, image distance, and the focal length of the mirror.
The formula is expressed as:
  • \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \]
Here, \(f\) is the focal length, \(v\) is the image distance, and \(u\) is the object distance from the mirror.
This equation is invaluable for predicting where an image will form in relation to the mirror. It operates under the principle that concave mirrors converge light, thus allowing us to form real or virtual images based on the situation. To use the mirror formula effectively, remember:
  • Ensure correct sign conventions (e.g., object distance \(u\) is negative when the object is in front of the mirror).

  • The focal length \(f\), being half the radius of curvature, is always considered positive for concave mirrors.
Solving problems with this formula often involves first determining or rearranging for the missing variable, leading to insights about the image's location relative to the mirror.
Focal Length Calculation
Calculating the focal length of a concave mirror is straightforward once you know the radius of curvature, denoted as \(R\).
The relationship between them is:
  • \[ f = \frac{R}{2} \]
This equation shows that the focal length \(f\) is simply half the radius of curvature. Measuring \(R\) can often be done practically, but the simplicity of this formula allows for quick calculations.
For the given problem, since the radius of curvature is \(36\, \mathrm{cm}\), substituting into the formula gives us a focal length:
  • \[ f = \frac{36 \mathrm{~cm}}{2} = 18 \mathrm{~cm} \]
Having this value makes it easy to apply the mirror formula and analyze image formation. The focal length remains a key characteristic that influences how the mirror manipulates light, especially essential for determining object-image relationships.
Image Magnification
Magnification is an important concept when discussing image formation in concave mirrors. It gives a clear idea of the image size relative to the object's actual size. The magnification \(m\) can be calculated using:
  • \[ m = \frac{v}{u} \]
where \(v\) is the image distance and \(u\) is the object distance.
This formula reveals if an image is magnified or diminished:
  • If \(|m| > 1\), the image is enlarged compared to the object.
  • If \(|m| < 1\), the image appears smaller or diminished.
In our problem, with \(v = 10.8\, \mathrm{cm}\) and \(u = -27\, \mathrm{cm}\), the image magnification is:
  • \[ m = \frac{10.8}{-27} \approx -0.4 \]
A negative magnification indicates the image is inverted, and because \(|-0.4|\) is less than 1, the image size is smaller than the actual object.
Real vs Virtual Image
In optics, distinguishing between real and virtual images is crucial to understand image nature.
For concave mirrors, a real image occurs when the reflected light rays converge at a point, forming an actual image on a screen.
A virtual image, by contrast, appears where light rays do not physically meet but seem to diverge from a point behind the mirror. Key characteristics to help identify the image type:
  • **Real Image:** Formed on the same side as the object, inverted, and can be projected onto a screen.

  • **Virtual Image:** Formed on the opposite side of the object, upright, and cannot be projected.
In our example, with a calculated positive image distance, it indicates a real image formed by the concave mirror.
Understanding whether the image is real or virtual is essential for comprehending how mirrors interact with light and how they can be used in various optical applications.

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