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A short bar magnet of magnetic moment \(\mathbf{m}=\mathbf{0 . 3 2} \mathbf{J T}\) is placed in a uniform magnetic field of \(0.15 \mathrm{~T}\). If the bar is free to rotate in the plane of the field, which orientation would correspond to its (a) stable, and (b) unstable equilibrium? What is the potential energy of the magnet in each case?

Short Answer

Expert verified
The stable equilibrium orientation is when the bar is aligned against the field. The potential energy in this case is \( -0.048 \, J \). The unstable equilibrium orientation is when the bar is aligned with the field. The potential energy in this case is \( 0.048 \, J \).

Step by step solution

01

Determine the stable equilibrium

A magnetic moment aligns itself from the opposite direction to the field which means it is in a stable equilibrium. In the stable equilibrium, the angle between magnetic field and magnetic moment is 0. Set \( \theta = 0 \) for the stable equilibrium in equation for the potential energy of a magnet in a magnetic field \( U = -m \cdot B \cdot cos(\theta) \). Calculate the potential energy using the given values \( m=0.32 \, J/T \) and \( B=0.15 \, T \).
02

Determine the unstable equilibrium

A magnetic moment is in an unstable equilibrium when aligned in the same direction as the field. In this case, the angle between the magnetic field and magnetic moment is 180 degrees or \( \pi \) radians. Set \( \theta = \pi \) in the equation for potential energy \( U = -m \cdot B \cdot cos(\theta) \). Substitute the given values to find the potential energy in the unstable equilibrium.
03

Calculate the potential energies

Calculate the potential energy for the stable equilibrium using the equation from step 1: \(U = -m \cdot B \cdot cos(0) = -0.32 \cdot 0.15 \cdot 1\), and for the unstable equilibrium using the equation from step 2: \(U = -m \cdot B \cdot cos(\pi) = -0.32 \cdot 0.15 \cdot -1\) .

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stable Equilibrium in Magnetism
In the context of magnetism, stable equilibrium occurs when a magnetic dipole is aligned opposite to the direction of an external uniform magnetic field. This alignment minimizes the system's total potential energy, meaning any small disturbance still keeps it close to this equilibrium and the magnet tends to return to this position.
A key aspect of stable equilibrium is its tendency to resist changes. A small disturbance results in forces or torques that act to return the object to its original position.

When calculating the potential energy (\( U \)) of a magnetic dipole in a magnetic field, it is given by the formula: \[ U = -m \cdot B \cdot \cos(\theta)\] where:
  • \( m \) is the magnetic moment of the dipole,
  • \( B \) is the magnetic field strength,
  • \( \theta \) is the angle between the magnetic moment and the magnetic field direction.
For stable equilibrium, this angle \( \theta \) is \( 0 \), hence cosine of \( 0 \) is 1, making the potential energy: \[ U = -m \cdot B \] in this particular scenario.
In our given example, calculating with values \( m=0.32 \, J/T \) and \( B=0.15 \, T \), the result is \( U = -0.048 \, J \), shedding light on how the system has minimized energy at stable equilibrium.
Unstable Equilibrium of a Magnet
Unstable equilibrium, in magnetism, refers to the scenario where the magnetic dipole is aligned in the same direction as the external magnetic field. This represents a state of maximized potential energy, where even a slight disturbance can change the magnet's position significantly, causing it to move away from equilibrium.
In this situation, the angle between the magnetic moment and the magnetic field, \( \theta \), is \( 180^\circ \) or \( \pi \) radians. The cosine of \( \theta \) here is -1, turning the potential energy of the system into:\[ U = -m \cdot B \cdot \cos(\pi) = m \cdot B \]
  • This indicates that the system has the highest potential energy, indicative of an unstable state.
In our example, using given values \( m=0.32 \, J/T \) and \( B=0.15 \, T \), the calculation results in \( U = 0.048 \, J \). The positive value signifies the high energy state which the system tends to move away from when disturbed.
Potential Energy in Magnetic Fields
Potential energy in the context of magnetism describes the energy stored due to the position of a magnetic dipole within a magnetic field. It depends on the orientation of the magnetic moment relative to the magnetic field. Simply put, this is the energy that can potentially do work when the dipole reorientates.
The mathematical formula is given by: \[ U = -m \cdot B \cdot \cos(\theta) \] When \( \theta \) is 0 (stable equilibrium), potential energy is minimized. Conversely, when \( \theta \) is \( 180^\circ \) or \( \pi \) (unstable equilibrium), it reaches a maximum level.
This potential energy can be visualized as:
  • In stable equilibrium, the magnetic dipole feels a torque resulting in a re-alignment to lower the energy further.
  • In unstable equilibrium, the slightest rotation results in a re-alignment to drastically lower energy making this state less likely to persist spontaneously.

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Most popular questions from this chapter

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