/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 A rocket with a lift-off mass \(... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A rocket with a lift-off mass \(20,000 \mathrm{~kg}\) is blasted upwards with an initial acceleration of \(5.0 \mathrm{~m} \mathrm{~s}^{-2}\). Calculate the initial thrust (force) of the blast.

Short Answer

Expert verified
The initial thrust of the blast is 296,000 N.

Step by step solution

01

Understand the problem

We need to find the initial thrust force applied to the rocket. This force is responsible for the upward acceleration of the rocket.
02

Write down the Known Values

We know the following:- Mass of the rocket, \( m = 20,000 \text{ kg} \)- Initial acceleration, \( a = 5.0 \text{ m/s}^2 \)
03

Recall Newton's Second Law

According to Newton's Second Law, the force acting on an object is given by the equation \( F = ma \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
04

Calculate Additional Forces

Remember that the rocket also has to overcome the gravitational force acting on it. The gravitational force \( F_g \) is calculated by \( F_g = mg \), where \( g = 9.8 \text{ m/s}^2 \).
05

Calculate Gravitational Force

Calculate the gravitational force using mass and gravity:\[F_g = 20,000 \times 9.8 = 196,000 \text{ N}\]
06

Combine Forces to Find Thrust

The initial thrust must overcome gravity and provide additional force for acceleration. Thus, total thrust \( F_t \) is:\[F_t = F_g + ma = 196,000 + (20,000 \times 5.0)\]Calculate \( ma \):\[\ma = 100,000 \text{ N}\]
07

Calculate Total Thrust

Add the two forces to find total thrust:\[F_t = 196,000 + 100,000 = 296,000 \text{ N}\]
08

Conclude the Calculation

The initial thrust required for the rocket to achieve the stated acceleration is 296,000 Newtons.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is a crucial fundamental principle in physics. It describes the relationship between the force acting upon an object, its mass, and its acceleration. In simple terms, it states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration:
  • Given as the equation: \( F = ma \)
  • \( F \) is the force in Newtons (N), \( m \) is the mass in kilograms (kg), and \( a \) is the acceleration in meters per second squared (m/s²).
In the context of our exercise, this law helps us understand how much initial thrust force we need to apply to a rocket in order to get it moving upward with a specific acceleration. It's important to remember that force needs to be greater to overcome any opposing forces, such as gravity. Newton's Second Law forms the foundation of much of classical mechanics, explaining why objects move the way they do when forces are applied.
Gravitational Force
Gravitational force is the force by which Earth attracts objects toward itself. It's what gives weight to physical objects and causes them to fall when dropped. This force is always directed downward towards the center of the Earth. The formula to calculate gravitational force is:
  • \( F_g = mg \)
  • Where \( g \approx 9.8 \text{ m/s}^2\) is the acceleration due to gravity.
For any object, the gravitational force depends on both its mass and the acceleration due to Earth's gravity. In the case of the rocket,
  • Gravitational force comes out to be 196,000 Newtons, calculated by multiplying the rocket's mass (20,000 kg) by Earth's gravity (9.8 m/s²).
This calculation helps us understand how much force the rocket must overcome just to counteract gravity and stay still.
Rocket Mass
The mass of a rocket is critical in determining how much force is needed to launch it. Rocket mass includes everything the rocket carries, such as fuel, engines, payload, and the structure itself.
  • Given in exercise: \( 20,000 \text{ kg} \)
Rocket mass plays a significant role when applying Newton’s Second Law. A heavier rocket requires more force to achieve the same amount of acceleration as a lighter one. Knowing the mass of the rocket allows us to calculate how much additional thrust will be needed
  • to both lift and accelerate it against gravitational forces.
Without accounting for mass, we can't determine how much energy and fuel needs to be expended for a successful launch.
Acceleration
Acceleration in physics is the rate of change of velocity of an object over time. When the rocket accelerates upwards, it means its speed increases with each passing second in the upward direction. In the exercise, we are given an initial acceleration of 5.0 m/s².
  • How it relates to force: As per Newton’s Second Law, acceleration is directly proportional to the net force and inversely proportional to mass, meaning if you apply more force or reduce the mass, an object accelerates faster.
This specific acceleration helps us design rockets that overcome gravity and gain speed to reach space. In rockets, acceleration is critical because it determines how quickly the spacecraft can escape Earth's gravitational pull and enter orbit. Calculating the initial thrust requires knowing how fast the rocket needs to accelerate away from the ground, ensuring it reaches the desired speed in a planned trajectory.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(70 \mathrm{~kg}\) man stands in contact against the inner wall of a hollow cylindrical drum of radius \(3 \mathrm{~m}\) rotating about its vertical axis with 200 rev/min. The coefficient of friction between the wall and his clothing is \(0.15 .\) What is the minimum rotational speed of the cylinder to enable the man to remain stuck to the wall (without falling) when the floor is suddenly removed?

Two bodies \(A\) and \(B\) of masses \(5 \mathrm{~kg}\) and \(10 \mathrm{~kg}\) in contact with each other rest on a table against a rigid wall (Fig. \(5.21\) ). The coefficient of friction between the bodies and the table is \(0.15 .\) A force of \(200 \mathrm{~N}\) is applied horizontally to \(A .\) What are (a) the reaction of the partition (b) the action-reaction forces between \(A\) and \(B ?\) What happens when the wall is removed? Does the answer to (b) change, when the bodies are in motion? Ignore the difference between \(\mu_{\mathrm{s}}\) and \(\mu_{\mathrm{k}^{-}}\)

A body of mass \(5 \mathrm{~kg}\) is acted upon by two perpendicular forces \(8 \mathrm{~N}\) and \(6 \mathrm{~N}\). Give the magnitude and direction of the acceleration of the body.

Explain why (a) a horse cannot pull a cart and run in empty space, (b) passengers are thrown forward from their seats when a speeding bus stops suddenly, (c) it is easier to pull a lawn mower than to push it, (d) a cricketer moves his hands backwards while holding a catch.

A truck starts from rest and accelerates uniformly at \(2.0 \mathrm{~m} \mathrm{~s}^{-2} .\) At \(t=10 \mathrm{~s}\), a stone is dropped by a person standing on the top of the truck \((6 \mathrm{~m}\) high from the ground). What are the (a) velocity, and (b) acceleration of the stone at \(t=\) 11s? (Neglect air resistance.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.