/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 A police van moving on a highway... [FREE SOLUTION] | 91Ó°ÊÓ

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A police van moving on a highway with a speed of \(30 \mathrm{~km} \mathrm{~h}^{-1}\) fires a bullet at a thiefs car speeding away in the same direction with a speed of \(192 \mathrm{~km} \mathrm{~h}^{-1}\). If the muzzle speed of the bullet is \(150 \mathrm{~m} \mathrm{~s}^{-1}\), with what speed does the bullet hit the thiefs car? (Note: Obtain that speed which is relevant for damaging the thief's car).

Short Answer

Expert verified
The bullet hits the thief's car at a speed of 105 m/s.

Step by step solution

01

Convert Speeds to a Common Unit

To solve this problem, we need to express all speeds in meters per second (m/s). The speed of the police van is given as \(30 \text{ km/h}\). We convert this to m/s using the conversion factor \(1 \text{ km/h} = \frac{5}{18} \text{ m/s}\).\[ 30 \text{ km/h} = 30 \times \frac{5}{18} \text{ m/s} = \frac{150}{18} \text{ m/s} = 8.33 \text{ m/s} \]Similarly, the speed of the thief's car is given as \(192 \text{ km/h}\).\[ 192 \text{ km/h} = 192 \times \frac{5}{18} \text{ m/s} = \frac{960}{18} \text{ m/s} = 53.33 \text{ m/s} \]
02

Calculate the Relative Speed of the Bullet

The muzzle speed of the bullet is given in meters per second as \(150 \text{ m/s}\). To find the speed of the bullet relative to the stationary ground, add the muzzle speed of the bullet to the speed of the police van (since they are in the same direction).\[ v_{\text{bullet relative to ground}} = 150 \text{ m/s} + 8.33 \text{ m/s} = 158.33 \text{ m/s} \]
03

Determine the Relative Speed to the Thief's Car

To find out with what speed the bullet hits the thief's car, we need to calculate the relative speed between the bullet and the thief's car. This is found by taking the bullet's speed relative to the ground and subtracting the thief's car speed, as they are both moving in the same direction. \[ v_{\text{relative}} = v_{\text{bullet relative to ground}} - v_{\text{thief}} = 158.33 \text{ m/s} - 53.33 \text{ m/s} = 105 \text{ m/s} \]
04

Finalize and Check Units

The relative speed we just calculated, \(105 \text{ m/s}\), is the speed at which the bullet impacts the thief's car. It is appropriate to report this final speed in meters per second, the standard unit for speed in physics problems.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed Conversion
When dealing with problems involving motion, it's crucial to express all speeds in the same unit to simplify calculations and avoid confusion. This process is known as speed conversion. Often speeds are provided in kilometers per hour (km/h), especially in everyday scenarios. However, in scientific contexts, speeds are typically converted to meters per second (m/s) for consistency and accuracy.

Here’s how you can convert speeds from km/h to m/s:
  • Use the conversion factor: \( 1 \text{ km/h} = \frac{5}{18} \text{ m/s} \).
  • To convert km/h to m/s, multiply the speed in km/h by \( \frac{5}{18} \).
For example, if a vehicle is traveling at 30 km/h, the speed in m/s is:
\( 30 \times \frac{5}{18} = 8.33 \text{ m/s} \).
Similarly, a speed of 192 km/h is:
\( 192 \times \frac{5}{18} = 53.33 \text{ m/s} \).

By converting to m/s, comparisons and calculations in physics, like calculating relative speed, become much more straightforward.
Muzzle Speed
The concept of muzzle speed is fascinating, particularly if you're interested in physics or ballistics. Muzzle speed refers to the velocity of a projectile (such as a bullet) at the exact moment it leaves the muzzle of a gun. It is a critical parameter as it affects the projectile's subsequent path and impact velocity.

In the given exercise, the muzzle speed of the bullet was mentioned as 150 m/s. This means that when the bullet exits the gun mounted on the police van, it's already traveling at this speed in addition to the speed of the van itself.

Understanding muzzle speed helps not only in solving relative motion problems but also in real-world applications, such as:
  • Predicting the bullet's trajectory and range.
  • Determining the kinetic energy at the point of impact.
When a firearm is in motion, such as being fired from a moving vehicle, the muzzle speed contributes to the total speed of the bullet relative to stationary objects or other moving objects, like the thief's car in this exercise.
Relative Speed Calculation
Relative speed is an essential concept when analyzing problems that involve multiple moving objects. It refers to the speed one object has concerning another object. This type of calculation is necessary to understand how fast something is moving from the perspective of another moving entity.

In the exercise, we calculate how fast the bullet travels relative to the thief's car. Here's the process:
  • Determine the bullet’s speed concerning the ground by adding the muzzle speed to the speed of the police van since both are moving in the same direction: \( v_{\text{bullet relative to ground}} = 150 \text{ m/s} + 8.33 \text{ m/s} = 158.33 \text{ m/s} \).
  • Calculate the relative speed between the bullet and the thief's car. Subtract the thief’s car speed from the bullet's relative speed since both move in the same direction: \( v_{\text{relative}} = v_{\text{bullet relative to ground}} - v_{\text{thief}} = 158.33 \text{ m/s} - 53.33 \text{ m/s} = 105 \text{ m/s} \).
Thus, the bullet hits the thief’s car at a speed of 105 m/s, indicating how effectively it will impact the car. This calculation helps understand real-world scenarios, such as how the perceived speed changes when observing from a moving vehicle.

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Most popular questions from this chapter

In which of the following examples of motion, can the body be considered approximately a point object: (a) a railway carriage moving without jerks between two stations. (b) a monkey sitting on top of a man cycling smoothly on a circular track. (c) a spinning cricket ball that turns sharply on hitting the ground. (d) a tumbling beaker that has slipped off the edge of a table.

A boy standing on a stationary lift (open from above) throws a ball upwards with the maximum initial speed he can, equal to \(49 \mathrm{~m} \mathrm{~s}^{-1}\). How much time does the ball take to return to his hands? If the lift starts moving up with a uniform speed of \(5 \mathrm{~m} \mathrm{~s}^{-1}\) and the boy again throws the ball up with the maximum speed he can, how long does the ball take to return to his hands?

On a two-lane road, car A is travelling with a speed of \(36 \mathrm{~km} \mathrm{~h}^{-1}\). Two cars \(\mathrm{B}\) and C approach car \(\mathrm{A}\) in opposite directions with a speed of \(54 \mathrm{~km} \mathrm{~h}^{-1}\) each. At a certain instant, when the distance \(\mathrm{AB}\) is equal to \(\mathrm{AC}\), both being \(1 \mathrm{~km}, \mathrm{~B}\) decides to overtake \(\mathrm{A}\) before \(\mathrm{C}\) does. What minimum acceleration of car \(\mathrm{B}\) is required to avoid an accident?

On a long horizontally moving belt (Fig. \(3.26\) ), a child runs to and fro with a speed \(9 \mathrm{~km} \mathrm{~h}^{-1}\) (with respect to the belt) between his father and mother located \(50 \mathrm{~m}\) apart on the moving belt. The belt moves with a speed of \(4 \mathrm{~km} \mathrm{~h}^{-1}\). For an observer on a stationary platform outside, what is the (a) speed of the child running in the direction of motion of the belt?. (b) speed of the child running opposite to the direction of motion of the belt? (c) time taken by the child in (a) and (b) ? Which of the answers alter if motion is viewed by one of the parents?

A jet airplane travelling at the speed of \(500 \mathrm{~km} \mathrm{~h}^{-1}\) ejects its products of combustion at the speed of \(1500 \mathrm{~km} \mathrm{~h}^{-1}\) relative to the jet plane. What is the speed of the latter with respect to an observer on the ground 2

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