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When the planet Jupiter is at a distance of \(824.7\) million kilometers from the Earth. its angular diameter is measured to be \(35.72^{\prime \prime}\) of arc. Calculate the diameter of Jupiter.

Short Answer

Expert verified
Jupiter's diameter is approximately 142,820 kilometers.

Step by step solution

01

Identify the Formula

To find the actual diameter of a celestial object given its distance and angular diameter, use the Small Angle Formula: \[ D = 2d \tan\left(\frac{\theta}{2}\right) \] where \(D\) is the actual diameter, \(d\) is the distance to the object, and \(\theta\) is the angular diameter in radians.
02

Convert Angular Diameter to Radians

The given angular diameter \(\theta\) is \(35.72^{\prime \prime}\). First, convert this to degrees by dividing by \(3600\), since there are \(3600\) arcseconds in a degree. Then convert degrees to radians by multiplying by \(\frac{\pi}{180}\): \[ \theta = 35.72 \times \frac{1}{3600} \times \frac{\pi}{180} \]
03

Calculate the Tangent of Half the Angular Diameter

Compute the tangent of half the converted angular diameter, which is necessary for the Small Angle Formula: \[ \tan\left(\frac{\theta}{2}\right) \]
04

Calculate Jupiter's Diameter

Substitute the calculated tangent and the distance \(d = 824.7\) million kilometers into the Small Angle Formula to find \(D\): \[ D = 2 \times 824.7 \times \tan\left(\frac{\theta}{2}\right) \]
05

Compute the Final Result

Perform the calculations to arrive at the diameter \(D\) of Jupiter. After completing the arithmetic operations, you will find Jupiter's diameter in kilometers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Diameter
The concept of angular diameter plays a significant role in astronomy and is fundamental in understanding how we measure the size of celestial objects like planets and stars from Earth. Angular diameter refers to how large an object appears to an observer's eye or a telescope, expressed in angular units such as degrees, arcminutes, and arcseconds.
To visualize this, imagine the arc of a circle, where the object is at the circle's edge, and the observer is at the center. The angle subtended by the object on the observer's eye is the angular diameter.
To convert angular measurements into an understandable size aspect, we use the Small Angle Formula, which is suitable for small angles, typically less than a few degrees. The formula allows astronomers to derive a physical size or diameter of a planet like Jupiter, by relating it to its distance from Earth and its angular diameter.
Key aspects:
  • Angular diameter is crucial for estimating the size of distant, spherical bodies.
  • It is measured in arcseconds, where 1 degree = 3600 arcseconds.
  • Conversion to radians is often necessary for calculations, as radians are involved in trigonometric functions.
Trigonometry
In celestial measurements, trigonometry is a powerful tool that aids in quantitative analysis. By understanding the relationships between the angles and distances in a triangle, we can solve real-world astronomy problems like the one presented for Jupiter.
The Small Angle Formula relies on the tangent function, which is a trigonometric function. When we have the angular diameter in radians, we use \(\tan(\frac{\theta}{2}) \) to find half of the angular size, as seen from Earth. Multiplying by the distance to the celestial object provides us with the actual diameter.
Essential points include:
  • Tangent function: Uses the opposite over adjacent sides in a right triangle.
  • Radians: A way to express angles used frequently in trigonometry and physics.
  • Trigonometry allows astronomers to bridge between measured angles and tangible distances.
Celestial Measurements
Celestial measurements are crucial for understanding the universe and our place within it. These measurements allow us to determine the sizes, distances, and even the composition of heavenly bodies.
For objects like Jupiter, determining its true diameter requires precise measurements of its apparent size from Earth and leveraging mathematical formulas. The process typically involves:
  • Measuring the angular diameter of the object using telescopic instruments.
  • Calculating the actual diameter using angular measurements and known distances.
  • Applying the Small Angle Formula to work out the physical dimensions.
This method of measurement provides not only numerical values but also insights into the formation, behavior, and dynamics of celestial objects. It enables scientists to make comparisons between planets, understand their orbital paths, and even detect potential changes over time.

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Most popular questions from this chapter

A student measures the thickness of a human hair by looking at it through a microscope of magnification \(100 .\) He makes 20 observations and finds that the average width of the hair in the fleld of view of the microscope is \(3.5 \mathrm{~mm}\). What is the estimate on the thickness of hair?

Just as precise measurements are necessary in science, it is equally important to be able to make rough estimates of quantities using rudimentary ideas and common observations. Think of ways by which you can estimate the following (where an estimate is difficult to obtain, try to get an upper bound on the quantity) : (a) the total mass of rain-bearing clouds over India during the Monsoon (b) the mass of an elephant (c) the wind speed during a storm (d) the number of strands of hair on your head (e) the number of air molecules in your classroom.

A man walking briskly in rain with speed \(v\) must slant his umbrella forward making an angle \(\theta\) with the vertical. A student derives the following relation between \(\theta\) and \(v: \tan \theta=v\) and checks that the relation has a correct limit: as \(v \rightarrow 0, \theta \rightarrow 0\), as expected. (We are assuming there is no strong wind and that the rain falls vertically for a stationary man). Do you think this relation can be correct? If not, guess the correct relation.

A SONAR (sound navigation and ranging) uses ultrasonic waves to detect and locate objects under water. In a submarine equipped with a SONAR, the time delay between generation of a probe wave and the reception of its echo after reflection from an enemy submarine is found to be \(77.0 \mathrm{~s}\). What is the distance of the enemy submarine? (Speed of sound in water \(=1450 \mathrm{~m} \mathrm{~s}^{-1}\) ).

A book with many printing errors contains four different formulas for the displacement \(y\) of a particle undergoing a certain periodic motion: (a) \(y=a \sin 2 \pi t / T\) (b) \(y=a \sin v t\) (c) \(y=(a / T) \sin t / a\) (d) \(y=(a \sqrt{2})(\sin 2 \pi t / T+\cos 2 \pi t / T)\) \((a=\) maximum displacement of the particle, \(v=\) speed of the particle. \(T=\) time-period of motion). Rule out the wrong formulas on dimensional grounds.

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