/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 A hydrogen atom in its ground st... [FREE SOLUTION] | 91Ó°ÊÓ

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A hydrogen atom in its ground state \([(n, l, m)=(1,0,0)]\) is placed between the plates of a capacitor. A time-dependent but spatially uniform electric field (not potential!) is applied as follows: \(\mathbf{E}=\left\\{\begin{array}{ll}0, & \text { for } t<0 \\ \mathbf{E}_{0} e^{-t / \tau}, & \text { for } t>0\end{array} \quad\left(\mathbf{E}_{0} \text { in the positive } z \text { -direction }\right)\right.\) Using first-order time-dependent perturbation theory, compute the probability for the atom to be found at \(t \gg \tau\) in each of the three \(2 p\) states: \((n, l, m)=(2,1,\pm 1 \text { or } 0)\) Repeat the problem for the \(2 s\) state: \((n, l, m)=(2,0,0) .\) You need not attempt to evaluate radial integrals, but perform all other integrations (with respect to angles and time).

Short Answer

Expert verified
The probabilities for the \(2p\) states are non-zero, while the probability for the \(2s\) state is zero due to angular selection rules.

Step by step solution

01

Understanding the Initial and Final States

In this problem, we are dealing with a hydrogen atom initially in its ground state \((n, l, m)=(1,0,0)\). We are interested in the probability for transitions to the upper states \((n, l, m)=(2,1, \, -1, 0, +1)\) and \((n, l, m)=(2,0,0)\) after applying a time-dependent electric field.
02

First-order Time-dependent Perturbation Theory

According to first-order perturbation theory, the probability of transition from an initial state \(|i\rangle\) to a final state \(|f\rangle\) is given by \(P_{i\to f}=\left| (1/i\hbar)\int_{0}^{\infty}\langle f|H'(t)|i\rangle e^{i\omega_{fi}t} dt \right|^2\), where \(\omega_{fi} = (E_f-E_i)/\hbar\), and \(H'(t)\) is the perturbing Hamiltonian.
03

Write the Perturbing Hamiltonian

The interaction of the electric field with the hydrogen atom is given by \(H'(t) = -e\mathbf{r}\cdot\mathbf{E}(t)\). Here, \(\mathbf{r}\) is the position vector of the electron, and \(\mathbf{E}(t) = \mathbf{E}_0 e^{-t/\tau}\hat{z}\), leading to \(H'(t) = -eE_0 z e^{-t/\tau}\) for \(t > 0\).
04

Compute Matrix Elements

The transition matrix element is \(\langle f|H'(t)|i\rangle = -eE_0 e^{-t/\tau}\langle f|z|i\rangle\). We need to compute \(\langle n, l, m|z|1, 0, 0\rangle\) for the required final states. The only non-zero transitions will be to states where the change in \(l\) is \(\pm 1\), which are \((2,1,0)\), \((2,1,1)\), and \((2,1,-1)\).
05

Handle Time Integral

The time integral becomes \(\int_0^\infty e^{(i\omega_{fi} - 1/\tau)t} dt = \frac{1}{i\omega_{fi} - 1/\tau}\), assuming \(\omega_{fi} > 0\). This integral is to be evaluated for each transition. For large negative parts, it can be approximated as \(\tau\) when \(t \gg \tau\).
06

Calculate Probability

The probability of finding the atom in a given excited state \((n, l, m)\) is \(P_{1\to 2, l, m} = \left|\frac{-eE_0}{\hbar} \langle 2, l, m|z|1,0,0\rangle \frac{e^{i\tau\omega_{fi}}}{i\tau\omega_{fi}-1}\right|^2\). Calculate these for each relevant \(2p\) and \(2s\) state. For \(2p\) states, use the angular part's orthogonality, and set the \(2s\) probability to zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Atom Transitions
In quantum mechanics, electrons in a hydrogen atom occupy specific energy levels or states, each identified by quantum numbers \( n \), \( l \), and \( m \). When subjected to an external influence, such as an electric field, electrons can jump from one energy level to another in what is known as a transition. For our hydrogen atom initially in its ground state \((n, l, m) = (1,0,0)\), we are particularly interested in transitions to the \(2p\) and \(2s\) states, represented by quantum numbers \((2,1,m)\) with \(m = -1, 0, 1\), and \((2,0,0)\) respectively.
This process involves absorption or emission of energy, corresponding to changes in the electron's energy state. The transitions of interest in this exercise are influenced by a time-dependent electric field, impacting the probability of electrons moving between these states.
Electric Field Interaction
When an external electric field is applied to a hydrogen atom, it interacts with the atom, affecting the electron's dynamics. In this scenario, a time-dependent electric field \( \mathbf{E}(t) = \mathbf{E}_0 e^{-t/\tau} \) is applied in the \( z \)-direction.
The interaction with the atomic electron is captured by the perturbation Hamiltonian, \( H'(t) = -e \mathbf{r} \cdot \mathbf{E}(t) \), where \( e \) is the electron charge, and \( \mathbf{r} \) is the electron's position vector. More specifically, the perturbation term simplifies to \( H'(t) = -eE_0 z e^{-t/\tau} \) due to the field's direction.
This perturbation changes the atom's state by providing or absorbing energy, facilitating transitions to higher energy levels. The perturbation depends on both the electron's position and the characteristics of the electric field, such as its strength (\( E_0 \)) and decay rate (\( \tau \)).
Transition Probabilities
In perturbation theory, the likelihood of an electron transitioning from an initial state \(|i\rangle\) to a final state \(|f\rangle\) due to an external influence is described by a probability. This transition probability \(P_{i \to f}\) is given mathematically by:
  • The square of the matrix element \( \left| (1/i\hbar) \int_{0}^{\infty} \langle f|H'(t)|i\rangle e^{i\omega_{fi}t} dt \right|^2 \), which includes the overlap between the initial and final states with respect to the perturbation, \( H'(t) \).
  • Here, \( \omega_{fi} = (E_f - E_i) / \hbar \) is the angular frequency associated with the energy difference between final and initial states.
  • The matrix element \( \langle f|z|i\rangle \) reflects the transition only occurs if \( \Delta l = \pm 1 \), showing non-zero probability for \((2,1,-1)\), \((2,1,0)\), and \((2,1,1)\) states, but zero for \(2s\).
The time integral evaluates to a simple form \( \frac{1}{i\omega_{fi} - 1/\tau} \), especially after time \( t \gg \tau \), helping to precisely estimate transition probabilities.
Perturbation Theory Calculations
Perturbation theory provides a structured approach for understanding how quantum systems behave under small disturbances. In this context, it helps calculate the transition probabilities induced by the electric field perturbing the hydrogen atom.
First-order perturbation theory simplifies the challenge of solving complex quantum systems by focusing on the primary order of change in the system caused by the perturbation. It's used here to compute the likelihood of finding the electron in different excited states after the electric field's influence.
By expressing the transition probability \( P_{1 \rightarrow 2, l, m} \) as
  • \[ P_{1 \rightarrow 2, l, m} = \left| \frac{-eE_0}{\hbar} \langle 2, l, m|z|1,0,0 \rangle \frac{e^{i\tau\omega_{fi}}}{i\tau\omega_{fi} - 1} \right|^2 \],
we incorporate the electric field's effect and the quantum states' properties for precise calculation. Notably, these calculations highlight the significance of the matrix elements and time integrations over the electron's transition probability during electric field exposure.

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Most popular questions from this chapter

Consider an atom made up of an electron and a singly charged \((Z=1)\) triton \(\left(^{3} \mathrm{H}\right)\) Initially the system is in its ground state \((n=1, l=0) .\) Suppose the system undergoes beta decay, in which the nuclear charge suddenly increases by one unit (realistically by emitting an electron and an antineutrino). This means that the tritium nucleus (called a triton) turns into a helium \((Z=2)\) nucleus of mass \(3\left(^{3} \mathrm{He}\right)\) (a) Obtain the probability for the system to be found in the ground state of the resulting helium ion. The hydrogenic wave function is given by \\[ \psi_{n=1, l=0}(\mathbf{x})=\frac{1}{\sqrt{\pi}}\left(\frac{Z}{a_{0}}\right)^{3 / 2} e^{-Z r / a_{0}} \\] (b) The available energy in tritium beta decay is about \(18 \mathrm{keV}\), and the size of the \(^{3}\) He atom is about 1 A. Check that the time scale \(T\) for the transformation satisfies the criterion of validity for the sudden approximation.

The Hamiltonian matrix for a two-state system can be written as \\[ \mathcal{H}=\left(\begin{array}{ll} E_{1}^{0} & \lambda \Delta \\ \lambda \Delta & E_{2}^{0} \end{array}\right) \\] Clearly, the energy eigenfunctions for the unperturbed problems \((\lambda=0)\) are given by \\[ \phi_{1}^{(0)}=\left(\begin{array}{l} 1 \\ 0 \end{array}\right), \quad \phi_{2}^{(0)}=\left(\begin{array}{l} 0 \\ 1 \end{array}\right) \\] (a) Solve this problem exactly to find the energy eigenfunctions \(\psi_{1}\) and \(\psi_{2}\) and the energy eigenvalues \(E_{1}\) and \(E_{2}\) (b) Assuming that \(\lambda|\Delta| \ll\left|E_{1}^{0}-E_{2}^{0}\right|\), solve the same problem using timeindependent perturbation theory up to first order in the energy eigenfunctions and up to second order in the energy eigenvalues. Compare with the exact results obtained in (a). (c) Suppose the two unperturbed energies are "almost degenerate"; that is, \\[ \left|E_{1}^{0}-E_{2}^{0}\right| \ll \lambda|\Delta| \\] Show that the exact results obtained in (a) closely resemble what you would expect by applying degenerate perturbation theory to this problem with \(E_{1}^{0}\) set exactly equal to \(E_{2}^{0}\)

Consider a particle in a two-dimensional potential \\[ V_{0}=\left\\{\begin{array}{ll} 0, & \text { for } 0 \leq x \leq L, 0 \leq y \leq L \\ \infty, & \text { otherwise } \end{array}\right. \\] Write the energy eigenfunctions for the ground state and the first excited state. We now add a time-independent perturbation of the form \\[ V_{1}=\left\\{\begin{array}{ll} \lambda x y, & \text { for } 0 \leq x \leq L, 0 \leq y \leq L \\ 0, & \text { otherwise } \end{array}\right. \\] Obtain the zeroth-order energy eigenfunctions and the first-order energy shifts for the ground state and the first excited state.

Consider the spontaneous emission of a photon by an excited atom. The process is known to be an \(E 1\) transition. Suppose the magnetic quantum number of the atom decreases by one unit. What is the angular distribution of the emitted photon? Also discuss the polarization of the photon, with attention to angular-momentum conservation for the whole (atom plus photon) system.

Consider a two-level system with \(E_{1}0\) by exactly solving the coupled differential equation \\[ i \hbar \dot{c}_{k}=\sum_{n=1}^{2} V_{k n}(t) e^{i \omega_{k n} t} c_{n}, \quad(k=1,2) \\] (b) Do the same problem using time-dependent perturbation theory to lowest nonvanishing order. Compare the two approaches for small values of \(\gamma\). Treat the following two cases separately: (i) \(\omega\) very different from \(\omega_{21}\) and (ii) \(\omega\) close to \(\omega_{21}\) Answer for (a): (Rabi's formula) \\[ \begin{aligned} \left|c_{2}(t)\right|^{2} &=\frac{\gamma^{2} / \hbar^{2}}{\gamma^{2} / \hbar^{2}+\left(\omega-\omega_{21}\right)^{2} / 4} \sin ^{2}\left\\{\left[\frac{\gamma^{2}}{\hbar^{2}}+\frac{\left(\omega-\omega_{21}\right)^{2}}{4}\right]^{1 / 2} t\right\\} \\ \left|c_{1}(t)\right|^{2} &=1-\left|c_{2}(t)\right|^{2} \end{aligned} \\]

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