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The probability of survival of a radioactive nucleus for one mean life is (a) \(\frac{1}{\mathrm{e}}\) (b) \(1-\frac{1}{e}\) (c) \(\frac{\ln 2}{\mathrm{e}}\) (d) \(1-\frac{\ln 2}{\mathrm{e}}\)

Short Answer

Expert verified
The probability of survival of a radioactive nucleus for one mean life is \(\frac{1}{e}\).

Step by step solution

01

Understand the Concept of Mean Life

Mean life, often denoted by the symbol \tau, is the average lifetime of a decaying particle before it decays. It is related to the decay constant \(\lambda\) of the particle by \(\tau = \frac{1}{\lambda}\).
02

Relate Mean Life to the Probability of Survival

The probability that a nucleus survives without decaying up to its mean life (\tau) can be found using the exponential decay law, which is given by \(P(t) = e^{-\lambda t}\). At the mean life \(t = \tau\), we substitute \(t = \frac{1}{\lambda}\) into the decay law.
03

Calculate the Probability of Survival for One Mean Life

Substituting \(\tau = \frac{1}{\lambda}\) into the exponential decay law yields \(P(\tau) = e^{-\lambda \tau} = e^{-\lambda \frac{1}{\lambda}} = e^{-1} = \frac{1}{e}\). This gives us the probability of survival for one mean life.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Life of Radioactive Nucleus
When delving into nuclear physics and specifically the behavior of radioactive decay, the concept of the mean life of a radioactive nucleus is pivotal. This characteristic time, often denoted by the symbol \tau, represents the average lifespan of an unstable atomic nucleus before it decays. It's important to visualize mean life as the 'expected value' of the time taken for a given nucleus to decay, and it's a statistical measure; some nuclei will decay faster, others more slowly, but on average, they will last for a time period equivalent to the mean life.

The mean life is universally related to the decay constant, \( \text{lambda} \), a number that reflects the probability of decay per unit time for a radioactive particle. The equation \( \tau = \frac{1}{\text{lambda}} \) succinctly describes this relationship. A higher decay constant means a shorter mean life, indicating a quick-decaying substance, whereas a lower decay constant is indicative of a substance that typically takes longer to decay.

To calculate mean life can be counterintuitive; it does not represent a moment in time when all the nuclei will have decayed, but rather it's a measure of centrality for the time before decay across a whole population of nuclei.
Exponential Decay Law
The exponential decay law models how the quantity of a radioactive substance decreases over time. This mathematical description is essential in understanding how radiation works in practice. The law asserts that the decrease is neither linear nor straightforwardly predictable on an individual level; instead, it follows an exponential pattern characterized by a steady but gradual reduction rate.

The exponential decay law is quantified by the formula \( P(t) = e^{-\text{lambda} t} \), where \( P(t) \) represents the probability of a nucleus surviving without decaying until time \( t \), \( e \) is the base of the natural logarithm and \( \text{lambda} \) is the decay constant. Time, \( t \) is usually measured from the moment when observation begins, often the time when the substance was first measured.

As time proceeds, the probability of survival diminishes exponentially, which means that while the rate of decay is steady, the actual number of particles decaying within each time interval will decrease as there are fewer undecayed particles remaining.
Decay Constant
The decay constant is a term that beautifully encapsulates the inherent instability of a radioactive substance. It is denoted by the Greek letter \( \text{lambda} \) and is fundamental to the mathematics of radioactive decay. As previously mentioned, it is inversely related to the mean life of a radioactive nucleus but what does it convey on its own?

The decay constant provides the probability per unit time that an undecayed nucleus will decay. To put it differently, it’s a measure of the rapidity with which atoms of a radioactive substance will transform into a different nuclear state or a different element altogether by emitting radiation.

In more mathematical terms, if one were to observe a large number of identical nuclei at time zero, the decay constant would be the fraction of the total number of nuclei expected to decay in the next infinitesimally small time interval. Therefore, a high decay constant means a substance will decay quickly and has a high level of radioactivity, while a low decay constant indicates a more stable substance that decays more slowly.

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Most popular questions from this chapter

Two radioactive materials \(\mathrm{X}_{1}\) and \(\mathrm{X}_{2}\) have decay constants \(11 \lambda\) and \(\lambda\), respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of \(X_{1}\) to that of \(X_{2}\) will be \(1 / e\) after a time (a) \(\frac{1}{10 \lambda}\) (b) \(\frac{1}{11 \lambda}\) (c) \(\frac{11}{10 \lambda}\) (d) \(\frac{1}{9 \lambda}\)

The compound unstable nucleus \({ }_{92}^{236} U\) often decays in accordance with the following reaction \({ }_{92}^{236} U \rightarrow{ }_{54}^{140} \mathrm{Xe}+{ }_{38}^{94} \mathrm{Sr}+\) other particles In the nuclear reaction presented above, the 'other particle' might be (a) An alpha particle, which consists of two protons and two neutrons (b) Two protons (c) One proton and one neutron (d) Two neutron

If a nucleus such as \({ }^{226} \mathrm{Ra}\) that is initially at rest undergoes alpha decay, then which of the following statements is true? (a) The alpha particle has less kinetic energy than the daughter nucleus. (b) The alpha particle has less Momentum than the daughter nucleus. (c) The alpha particle and daughter nucleus both have same kinetic energy (d) We cannot say anything about kinetic energy of alpha particle and daughter nucleus.

A neutron of energy \(1 \mathrm{MeV}\) and mass \(3.2 \times 10^{-27} \mathrm{~kg}\) passes a proton at such a distance that the angular momentum of the neutron relative to the proton approximately equals \(10^{-23} \mathrm{Js}\). The distance of closest approach neglecting the interaction between particles is (a) \(3.125 \times 10^{-2} \mathrm{~m}\) (b) \(3125 \mathrm{~m}\) (c) \(31.25 \mathrm{~m}\) (d) \(3.125 \times 10^{4} \mathrm{~m}\)

A helium atom, a hydrogen atom and a neutron have masses of \(4.003 \mathrm{u}, 1.008 \mathrm{u}\) and \(1.009 \mathrm{u}\) (unified atomic mass units), respectively. Assuming that hydrogen atoms and neutrons can fuse to form helium, what is the binding energy of a helium nucleus? (a) \(2.01 \mathrm{u}\) (b) \(3.031 \mathrm{u}\) (c) \(1.017 \mathrm{u}\) (d) \(0.031 \mathrm{u}\)

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