/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 Calculate the wavelengths of the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Calculate the wavelengths of the first three lines in the Lyman series for hydrogen.

Short Answer

Expert verified
The wavelengths of the first three lines in the Lyman series for hydrogen are obtained using the formula for each with the respective values of n2. They are given by: λ1: 1 / (R * (1 - 1/4)), λ2: 1 / (R * (1 - 1/9)), λ3: 1 / (R * (1 - 1/16))

Step by step solution

01

Identify n1 and n2

For the Lyman series, n1 is always 1 because the transitions happen from higher energy levels down to the ground state. For the first three lines of the series, n2 will be 2, 3, and 4 respectively.
02

Use the Rydberg formula for the first line

Substitute n1=1 and n2=2 into the formula 1/λ = R * (1/n1² - 1/n2²) to find the wavelength of the first line in the Lyman series. After substitution, it becomes 1/λ = R * (1 - 1/4).
03

Solve for the wavelength of the first line

After the calculation in Step 2, it's necessary to solve the formula for λ to get the wavelength of the first line. λ = 1 / (R * (1 - 1/4))
04

Repeat steps 2 and 3 for the second and third lines

Repeat Steps 2 and 3 but replace n2 with 3 for the second line and 4 for the third line. Calculate separately for each line's wavelength.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A photon is emitted from a hydrogen atom that undergoes an electronic transition from the state \(n=3\) to the state \(n=2 .\) Calculate (a) the energy, (b) the wavelength, and (c) the frequency of the emitted photon.

(a) Construct an energy-level diagram for the \(\mathrm{He}^{+}\) ion, for which \(Z=2\). (b) What is the ionization energy for \(\mathrm{He}^{+} ?\)

A hydrogen atom is in its ground state \((n=1)\). Using the Bohr theory of the atom, calculate (a) the radius of the orbit, (b) the linear momentum of the electron, (c) the angular momentum of the electron, (d) the kinetic energy, (e) the potential energy, and (f) the total energy.

Calculate the frequency of the photon emitted by a hydrogen atom making a transition from the \(n=4\) to the \(n=3\) state. Compare your result with the frequency of revolution for the electron in these two Bohr orbits.

Liquid oxygen has a bluish color, meaning that it preferentially absorbs light toward the red end of the visible spectrum. Although the oxygen molecule \(\left(\mathrm{O}_{2}\right)\) does not strongly absorb visible radiation, it does absorb strongly at \(1269 \mathrm{~nm}\), which is in the infrared region of the spectrum. Research has shown that it is possible for two colliding \(\mathrm{O}_{2}\) molecules to absorb a single photon, sharing its energy equally. The transition that both molecules undergo is the same transition that results when they absorb \(1269-\mathrm{nm}\) radiation. What is the wavelength of the single photon that causes this double transition? What is the color of this radiation?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.