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A rocket engine for space travel using photon drive and matter-antimatter annihilation has been suggested. Suppose the fuel for a short-duration burn consists of \(N\) protons and \(N\) antiprotons, each with mass \(m\). (a) Assume all of the fuel is annihilated to produce photons. When the photons are ejected from the rocket, what momentum can be imparted to it? (b) If half of the protons and antiprotons annihilate each other and the energy released is used to eject the remaining particles, what momentum could be given to the rocket? Which scheme results in the greatest change in speed for the rocket?

Short Answer

Expert verified
The greatest change in speed for the rocket can be achieved when all the protons and antiprotons are annihilated to produce photons, which yield a momentum of \(2Nm_0c\). If only half of the protons and antiprotons annihilate and the energy is used to eject the remaining particles, the resultant momentum is \(Nm_0c\sqrt{2}\), which is lower.

Step by step solution

01

Calculate the momentum for case (a)

In case (a), all fuel is converted into photons. The total energy of the \(N\) protons and \(N\) antiprotons can be calculated with the equation \(E=2Nm_0c^2\), where \(m_0\) is the rest mass of the proton (or antiproton). This energy becomes the energy of the photons. For photons, \(E=pc\), so we can solve for \(p\) and find that \(p=E/c\), which results in \(p=2Nm_0c\).
02

Calculate the momentum for case (b)

In case (b), half of the protons and antiprotons annihilate, producing a total energy of \(E=Nm_0c^2\). This energy is utilized to eject the remaining protons and antiprotons at speed \(v\). The momentum given to the rocket is the total momentum of the ejected particles, which is \(p=Nmv\). By energy conservation, the kinetic energy of the particles is equal to the energy released in the annihilation, \(Nmv^2/2 = Nm_0c^2\). Solving for \(v\) gives \(v=\sqrt{2m_0c^2/m}\) and substituting this into the momentum equation gives \(p=Nm_0c\sqrt{2}\).
03

Compare the momentums

Comparing the results from Step 1 and Step 2, we find that the momentum \(p\) in case (a) is larger than the momentum in case (b). Hence, more momentum, and thus speed, can be imparted to the rocket if all the particles are annihilated to produce photons (case a).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton and Antiproton Annihilation
The process of proton and antiproton annihilation is a fundamental concept in particle physics, where particles of matter and antimatter collide and destroy each other. This event is extremely energy-efficient, as it converts the entire mass of the particles into energy. When a proton encounters its antiparticle counterpart, the antiproton, they annihilate into high-energy photons, primarily gamma rays.

This follows Albert Einstein's famous equation, \( E=mc^2 \), stating that energy (E) and mass (m) are interchangeable, with \( c \) being the speed of light. In the context of our rocket engine, suppose we have \( N \) protons and \( N \) antiprotons, each with mass \( m \). The mass of these particles can be converted into pure photonic energy during annihilation, demonstrating how this process can be harnessed for propulsion.
Photon Drive in Space Travel
Photon drive is a theoretical propulsion system for spacecraft that utilizes the momentum of photons to generate thrust. Unlike conventional rocket engines, which expel mass to produce thrust, a photon drive expels light. Although photons have no mass, they carry momentum, which can be transferred to a spacecraft.

This technology would be revolutionary, enabling fuel efficiency and potentially high speeds since photons travel at light speed. In our example, if the rocket's fuel of protons and antiprotons annihilated into photons, the momentum imparted to the rocket would follow the relationship \( p=E/c \), where \( E \) is the total energy of the photons and \( c \) is the speed of light. The expelled photons would then propel the spacecraft forward, making it plausible for long-duration space exploration.
Momentum Conservation in Physics
Momentum conservation is one of the fundamental principles in physics. It states that the total momentum of a closed system remains constant if no external forces are applied. In the case of our photon drive system, when protons and antiprotons annihilate, producing photons that are ejected backwards, the rocket is propelled forward to conserve momentum.

The law of conservation ensures that the rocket’s gained momentum is equal in magnitude and opposite in direction to the momentum of the ejected photons. This allows us to calculate the propulsion force and potential speed increase for the rocket. In terms of equations, for every action, there is an equal and opposite reaction, expressed as \( p_{rocket} = - p_{photons} \). This concept is crucial in designing engines and predicting the behavior of spacecraft.
Energy-Mass Equivalence
Energy-mass equivalence, represented by Einstein's equation \( E=mc^2 \), is vital in understanding nuclear processes like matter-antimatter annihilation. It explains how energy can be converted into mass and vice versa. In our space travel context, this principle is what allows the annihilation of matter (protons) and antimatter (antiprotons) to release an immense amount of energy.

When transforming the mass of protons and antiprotons into energy for the rocket, the total energy calculated is \( 2Nm_0c^2 \), considering the annihilation of each pair of particle and antiparticle. This energy is then released as photons in case (a) or as the kinetic energy of the remaining particles in case (b), propelling the rocket in space. The ability to harness this energy efficiently can lead to advances in space travel propulsion systems, potentially enabling us to reach distant parts of the cosmos.

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Most popular questions from this chapter

An unstable particle, initially at rest, decays into a proton (rest energy \(938.3 \mathrm{MeV}\) ) and a negative pion (rest energy \(139.5 \mathrm{MeV}\) ). A uniform magnetic field of \(0.250 \mathrm{~T}\) exists perpendicular to the velocities of the created particles. The radius of curvature of each track is found to be \(1.33 \mathrm{~m}\). What is the rest mass of the original unstable particle?

When a high-energy proton or pion traveling near the speed of light collides with a nucleus, it travels an average distance of \(3 \times 10^{-15} \mathrm{~m}\) before interacting. From this information, estimate the time required for the strong interaction to occur.

(a) Show that baryon number and charge are conserved in the following reactions of a pion with a proton. $$ \begin{array}{l} \pi^{-}+\mathrm{p} \longrightarrow \mathrm{K}^{-}+\Sigma^{+} \\ \pi^{-}+\mathrm{p} \longrightarrow \pi^{-}+\Sigma^{+} \end{array} $$ (b) The first reaction is observed, but the second never occurs. Explain these observations.

The most recent naked-eye supernova was Supernova Shelton \(1987 \mathrm{~A}\) (Fig. P15.23). It was 170,000 ly away in the next galaxy to ours, the Large Magellanic Cloud. About \(3 \mathrm{~h}\) before its optical brightening was noticed, two continuously running neutrino detection experiments simultaneously registered the first neutrinos from an identified source other than the Sun. The Irvine-Michigan-Brookhaven experiment in a salt mine in Ohio registered eight neutrinos over a 6 -second period, and the Kamiokande II experiment in a zinc mine in Japan counted 11 neutrinos in \(13 \mathrm{~s}\). (Because the supernova is far south in the sky, these neutrinos entered the detectors from below. They passed through the Earth before they were by chance absorbed by nuclei in the detectors.) The neutrino energies were between about \(8 \mathrm{MeV}\) and \(40 \mathrm{MeV}\). If neutrinos have no mass, then neutrinos of all energies should travel together at the speed of light-the data are consistent with this possibility. The arrival times could show scatter simply because neutrinos were created at different moments as the core of the star collapsed into a neutron star. If neutrinos have nonzero mass, then lower-energy neutrinos should move comparatively slowly. The data are consistent with a \(10-\mathrm{MeV}\) neutrino requiring at most about 10 s more than a photon would require to travel from the supernova to us. Find the upper limit that this observation sets on the mass of a neutrino. (Other evidence sets an even tighter limit.)

Determine which of the following reactions ean occur. For those that cannot occur, determine the conservation law (or laws) that is violated. (a) \(\mathrm{p} \rightarrow \pi^{+}+\pi^{0}\) (b) \(\mathrm{p}+\mathrm{p} \rightarrow \mathrm{p}+\mathrm{p}+\pi^{0}\) (c) \(\mathrm{p}+\mathrm{p} \rightarrow \mathrm{p}+\pi^{+}\) (d) \(\pi^{+} \rightarrow \mu^{+}+v_{\mu}\) (e) \(\mathrm{n} \rightarrow \mathrm{p}+\mathrm{e}^{-}+\bar{\nu}_{\mathrm{e}}\) (f) \(\pi^{+} \rightarrow \mu^{+}+\mathrm{n}\)

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