/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 A yet-to-be-built spacecraft sta... [FREE SOLUTION] | 91Ó°ÊÓ

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A yet-to-be-built spacecraft starts from Earth moving at constant speed to the yet-to-be-discovered planet Retah, which is 20 lighthours away from Earth. It takes \(25 \mathrm{~h}\) (according to an Earth observer) for a spacecraft to reach this planet. Assuming that the clocks are synchronized at the beginning of the journey, compare the time elapsed in the spacecraft's frame for this one-way journey with the time elapsed as measured by an Earth-based clock.

Short Answer

Expert verified
The time elapsed in the spacecraft's frame for the one-way journey is approximately \( 41.7 \) hours as compared to \(25 \) hours measured by an Earth-based clock.

Step by step solution

01

Understand the Time Dilation Concept

In special relativity, time dilation occurs between two events for an observer as compared to another observer. It is given by the formula \( \Delta t' = \gamma \Delta t \) where \( \Delta t \) is time interval between two events by a stationary observer (Earth), \( \Delta t' \) is time interval between two events by a moving observer (spacecraft), and \( \gamma \) is Lorentz factor given by \( \gamma = \frac{1}{\sqrt{1- \frac{v^2}{c^2}}} \), where \( v \) is velocity of moving observer and \( c \) is speed of light.
02

Identify Given Values

Here, \( \Delta t = 25 \) hours is time interval as measured by Earth observer and the distance \( d = 20 \) lighthours.
03

Calculate Velocity v

Velocity \( v \) of the spacecraft as perceived by the earth observer can be calculated from the distance and time. \( v = \frac{d}{\Delta t} = \frac{20 \, lighthours}{25 \, hours} = 0.8c \) where \( c \) is speed of light.
04

Calculate Lorentz Factor

We can calculate Lorentz factor \( \gamma \) using the calculated velocity \( v \). \( \gamma = \frac{1}{\sqrt{1- \frac{v^2}{c^2}}} = \frac{1}{\sqrt{1- (0.8)^2}} = \frac{1}{\sqrt{1-0.64}} = \frac{1}{0.6} \).
05

Calculate Time Interval in Moving Frame

Finally, we can calculate time interval \( \Delta t' \) in spacecraft frame from Lorentz transformation. \( \Delta t' = \frac{\Delta t}{\gamma} = \frac{25 \, hours}{0.6} = 41.7 \) hours approx.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
In the realm of physics, the theory of Special Relativity, introduced by Albert Einstein in 1905, marks a cornerstone that reshaped our understanding of space and time. At its core, Special Relativity postulates that the laws of physics are the same for all non-accelerating observers, and that the speed of light in a vacuum is the same for all observers, regardless of their motion relative to the light source.

This revolutionary theory brings with it the concept of time dilation, which suggests that time can pass at different rates for different observers, depending on their relative velocities. It illustrates that an observer moving relative to a stationary clock will measure the clock ticking slower compared to when both the observer and the clock are stationary.

This is not a mere illusion but a real effect, as time effectively 'slows down' for the moving observer. This has profound implications, especially for objects moving at speeds close to the speed of light, and it has been confirmed by numerous experiments, such as those involving atomic clocks on fast-moving planes or in satellites.
Lorentz Factor
The Lorentz Factor, symbolized as \( \textstyle \bgamma \textstyle \) (gamma), is a crucial element in the equations of Special Relativity. It quantifies how much time, length, and relativistic mass change for an object moving at a significant fraction of the speed of light relative to an observer. Mathematically, the Lorentz Factor is given by the equation:
\( \bgamma = \frac{1}{\bsqrt{1- \frac{v^2}{c^2}}} \textstyle \)

where \( v \textstyle \) is the relative velocity of the moving object and \( c \textstyle \) is the constant speed of light. As \( v \textstyle \) approaches \( c \textstyle \), \( \bgamma \textstyle \) increases dramatically, causing more significant deviations from the classical Newtonian physics predictions.

  • The Lorentz Factor approaches infinity as an object's speed approaches the speed of light.
  • It affects the time dilation experienced by a moving clock compared to a stationary one—the greater the velocity, the more pronounced the time dilation.
  • The Lorentz Factor is also essential in the length contraction phenomenon, where an object's length appears shorter in the direction of motion to an outside observer.

For objects moving at everyday speeds, \( \bgamma \textstyle \) is very close to 1, which means the effects of Special Relativity are negligible. However, for high-speed scenarios such as in particle accelerators or astrophysical events, the Lorentz Factor becomes significant.
Spacecraft Timekeeping
Timekeeping on a spacecraft traveling at relativistic speeds is influenced by the effects of Special Relativity. When a spacecraft moves at a significant fraction of the speed of light, time aboard the spacecraft dilates relative to time on Earth. This time dilation can lead to differences in elapsed time as perceived by the spacefarers compared to those on Earth.

For spacecraft timekeeping, atomic clocks are often used due to their precision. These clocks measure the natural oscillation frequencies of atoms, which are constant and not affected by the motion of the spacecraft. However, from the perspective of an Earth-based observer, these oscillations (and thus time) seem to occur more slowly.

The exercise provided is a practical application of these concepts. It demonstrates how an astronaut on a spacecraft traveling to the distant planet Retah would experience a longer duration of passage (approximately 41.7 hours) than what is observed from Earth (25 hours), due to the relativistic effect of time dilation calculated using the Lorentz Factor. This outcome is essential for planning long-duration space missions, GPS satellite technology, and can even influence communication and synchronization systems between Earth and spacecraft.

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Most popular questions from this chapter

An electron moves to the right with a speed of \(0.90 c\) relative to the laboratory frame. A proton moves to the right with a speed of \(0.70 c\) relative to the electron. Find the speed of the proton relative to the laboratory frame.

Suppose our Sun is about to explode. In an effort to escape, we depart in a spaceship at \(v=0.80 c\) and head toward the star Tau Ceti, 12 lightyears away. When we reach the midpoint of our journey from the Earth, we see our Sun explode and, unfortunately, at the same instant we see Tau Ceti explode as well. (a) In the spaceship's frame of reference, should we conclude that the two explosions occurred simultaneously? If not, which occurred first? (b) In a frame of reference in which the Sun and Tau Ceti are at rest, did they explode simultaneously? If not, which exploded first?

A physics professor on Farth gives an exam to her students who are on a spaceship traveling at speed \(v\) relative to Earth. The moment the ship passes the professor, she signals the start of the exam. If she wishes her students to have time \(T_{0}\) (spaceship time) to complete the exam, show that she should wait a time (Earth time) of $$ T=T_{0} \sqrt{\frac{1-v / c}{1+v / c}} $$ before sending a light signal telling them to stop. (Hint: Remember that it takes some time for the second light signal to travel from the professor to the students.)

The identical twins Speedo and Goslo join a migration from Earth to Planet \(\mathrm{X}\). It is \(20.0\) ly away in a reference frame in which both planets are at rest. The twins, of the same age, depart at the same time on different spaceships. Speedo's ship travels steadily at \(0.950 c\), and Goslo's at \(0.750 c\). Calculate the age difference between the twins after Goslo's spaceship reaches Planet \(\mathrm{X}\). Which twin is the older?

A spacecraft moves at a speed of \(0.900 c\). If its length is \(L\) as measured by an observer on the spacecraft, what is the length measured by a ground observer?

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