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A 1 ns pulse of electromagnetic waves would be 30cmlong.

(a) Consider such a pulse of 633 nmwavelength laser light. Find its central wave number and the range of wave numbers it comprises.

(b) Repeat part (a), but for a 1nspulse of 100 MHzradio waves.

Short Answer

Expert verified

(a) The value of the wave number is9.93x106m-1and the range of the wave number is k1.67m-1.

(b) The value of the wave number is 20.9dm-1and the range of the wave number is k1.67m-1.

Step by step solution

01

Formula for expression for the uncertainty in the wave’s position and the relation between wave numbers.

The expression for the uncertainty in the wave鈥檚 position is given by,

xk12

The expression for the relation between the wave number k and is given by,k=2

02

Use the expression ΔxΔk≥12 and k=2πλ for calculation.

(a).

The wavelengthof the pulse is6.33nm.

The length xof the electromagnetic wave is30cm.

The wavenumber is calculated as,

role="math" localid="1659761406782" k=2=2633nm=2633nm10-9m1nm=9.93106m-1

The range of the wavenumber is calculated as,

xk1230cm10-2m1cmk12k1.67m-1

Therefore, the value of the wave number is 9.93x106m-1and the range of the wave number is k1.67m-1.

03

Formula for the expression for the relation between the wavenumber and the wave equation of the light.

The expression for the relation between the wave numberkandis given by,

k=2

The expression for wave equation of light is given by,

c=f

04

Use the expression k=2πλ and c=λf for calculation.

(b)

The frequency f of the pulse is 1Hz.

The expression for the wavenumber is evaluated as,

k=2=2c=2蟺蹿c

The value of wavenumber is calculated as,

k=2蟺蹿c=211ms3108m/s=211ns110-9s1ns3108m/s=20.9m-1

The range of the wavenumber is calculated as,

xk1230cm10-2m1cmk12k1.67m-1

Therefore, the value of the wave number is 20.9m-1and the range of the wave number is k1.67m-1

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