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Particle 1, of mass role="math" localid="1657551290561" m1, moving at role="math" localid="1657551273841" 0.8crelative to the lab, collides head-on with particle 2, of mass m2, moving at 0.6crelative to the lab. Afterward, there is a single stationary object. Find in terms of role="math" localid="1657551379188" m1

(a) m2

(b) the mass of the final stationary object; and

(c) the change in kinetic energy in this collision.

Short Answer

Expert verified
  1. The mass of m2 is 16/3 m1 .
  2. The mass of the final stationary object is mf = 25/3 m1 .
  3. The change in kinetic energy in this collsion is KE-2m1c2.

Step by step solution

01

Conservation of momentum and energy:

A property of a moving body that a body has by virtue of its mass and motion, which is equal to the product of the body's mass and velocity.

A fundamental law of physics and chemistry states that the total energy of an isolated system is constant despite internal changes.

02

(a) Applying Momentum Conservation:

As the collision is completely inelastic, kinetic energy will be lost, and the internal energy to increase.

Consider the known data as below.

The relativistic factors is 0.6c=54and 0.8c=53.

To determine m2 in this case of completely inelastic collision let鈥檚 apply momentum conservation as below.

1m1u1+2m2u2=fmfuf0.8cm10.8c+0.6cm2-0.6c=0530.8m1=540.6m2m2=163m1

03

(c) Determine the kinetic energy

Now applying relativistic kinetic energy conservation equation,

KE=0-1mfc2-0.8c-1m1c2+0.6c-1m2c2=0-53-1m1+54-1m2c2=-23m1+14163m1c2=-2m1c2

The change in relativistic kinetic energy will result in change in Internal energy which implies that mass will change.

04

(c) Determine the mass of the final stationary object

In this case, the mass will increase because kinetic energy decreases.

KE=-mc2

Put this term in above result, and you get,

-mc2=-2m1c2mf-m1+m2=2m1mf-m1-163m1=2m1

3mf-3m1-16m1=6m13mf=25m1mf=253m1

Hence, there is an increase in mass by 2m1of the system which is a result of decrease in the kinetic energy by 2m1c2 of the system.

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