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From the abundances and atomic masses given in Appendix I of the two naturally occurring isotopes of boron. Determine the average atomic mass of natural boron. Compare this with the value given in the periodic table of Chapter 8.

Short Answer

Expert verified

Atomic mass and average mass of boron both are equal to 10.811u.

Step by step solution

01

Given data

Two major naturally occurring isotopes of boron are given as:

Atomic mass of boron-,10.mB−10=10.012937u

Atomic mass of boron-,11 .mB−11=11.009305u

%Natural abundance boron-10is19.9%.

%Natural abundance boron- 11is80.1% .

Atomic mass of boron in periodic table, mB=10.811u.

02

Concept of Isotopes

Isotopes are members of a family of an element that all have the same number of protons but different numbers of neutrons.

03

Comparison of atomic mass and average mass of boron

The average atomic mass of boron is given as:

maverage=mB−10×19.9%+mB−11×80.1%maverage=(10.012937u)×19.9%+(11.009305u)×80.1%maverage=10.811u

Since, the atomic mass of boron in periodic table, mB=10.811u.

On comparing the atomic mass and average mass of boron, one can say that both are equal to .mB=10.811u

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