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Chapter 12: Q30E (page 557)

Sketch Feynman vertex for the creation of a 鈫�d quark and c quark.

Short Answer

Expert verified

The Feynman diagram is shown in the figure as:

Step by step solution

01

Given data

The 鈫�d has charge +1/3, and c has charge +2/3 .

02

Concept of Feynman diagram 

A Feynman diagram describes the interactions in quantum field theory. Solid lines, and curved lines are used to represent different types of particle interactions.

03

Step 3:Sketch Feynman vertex 

The Feynman diagram is shown in figure 1.

Figure 1

Because the type of quark changed, it is a weak interaction.

Because鈫�dhas charge+1/3, and c has charge +2/3, they will exchange aW+ boson.

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Most popular questions from this chapter

In non-relavistic quantum mechanics, governed by the Schrodinger equation, the probability of finding a particle does not change with time.

(a)

Prove it, Begin with the time derivative of the total probability

ddt鈭�唯*(x,t)唯'(x,t)dx=鈭�(唯(x,t)鈭�鈭�t唯*(x,t)+唯*(x,t)鈭�鈭�t唯(x,t))dx

Then use the Schrodinger equation to eliminate the partial time derivatives, integrate by parts, and show that the result is zero. Assume that the particle is well localised, so that 蠄鈥塧苍诲鈥�鈭�蠄鈭�xare 0 when evaluated at .卤鈭�

(b) Does this procedure lead to the same conclusion if Wave function obeyKlein-Gordon rather than Shrodinger equation? Why and why not?

In the following exercises, two protons are smashed together in an attempt to convert kinetic energy into mass and new particles. Indicate whether the proposed reaction is possible. If not, indicate which rules are violated. Consider only those for charge, angular momentum, and baryon number If the reaction is possible, calculate the minimum kinetic energy required of the colliding protons.

p+p鈫�p+p+p+p炉

To produce new particle accelerators often smash two equal mass objects together proton and proton or electron and positron. The threshold energy is the kinetic energy before the collision needed simply to produce the final particle their mass thermal energy alone with no leftover kinetic energy. Consider a colliding beam accelerator in which two initial particles of mass m are moving at the same speed relative to the lab. Assume that the total mass of the stationary particles after the collision is M. Show that the threshold energy is M-2mc2.

From the masses of the weak bosons given in Table 12.1, show that range is of weak part of electroweak force should be about 10鈭�3鈥塮尘.

Equation (12-7) assumes a matter-dominated universe in which the energy density of radiation is insignificant. This situation prevails today and has to do with the different rates at which the densities of matter and radiation vary with the size of the universe. Matter density is simply inversely proportional to the volume, obeying 蚁mIR3 , where蚁m is the matter density now. Radiation density, however, would be proportional to I/R4(Not only does the volume increase, but also all wavelengths are stretched in proportion to R. lowering the energy density by the extra factor.) This density drops faster As the universe grows, but it also grows more quickly in the backward time direction. In other words, long ago, the universe would have been radiation dominated. Show that if the function used for matter density in equation (12-7) is replaced by one appropriate to radiation, but retaining the assumption that K' and惟A are both 0, then the scale factor Rwould grow ast1/2

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