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a) Taking the particle鈥檚 total energy to be 0, find the potential energy.

(b) On the same axes, sketch the wave function and the potential energy.

(c) To what region would the particle be restricted classically?

Short Answer

Expert verified

The potential energy is U=h2m3x2-a2m(x2+a2)2

Step by step solution

01

Potential energy

(a) If the total energy is 0, the potential energy will be the negative kinetic energy; the kinetic energyhas an operator.

E^=-h22md2dx2

The kinetic energy is

E^(2a3/21x2+a2)=-h22md2dx2(2a3/21x2+a2)

=h22m2a3/2a2-3x2(x2+a2)3

=h22m2a3/21x2+a22a2-3x2(x2+a2)2

The double derivative is calculated separately below:

d2dx2-1x2+a2=ddx2x(x2+a2)2

(x2+a2)2-x2(x2+a2)2x(x2+a2)2=2a2-3x2(x2+a2)3

Therefore, the potential energy isU=h2m3x2-a2m(x2+a2)2.

02

Sketch of potential energy and wave function

(b) The sketch is as follows. The blue line represents the potential energy, and the red line represents the wave function.

The unit length is

03

Find the region

The classical region is where the potential energy is smaller than 0, which is about (-0.6a,0.6a).

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Most popular questions from this chapter

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