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What is the product of uncertainties determined in Exercise 60 and 61? Explain.

Short Answer

Expert verified

The product of uncertainty in position and momentum is 2, which is in accordance with the uncertainty principle.

Step by step solution

01

The concepts and formulas used to solve the given problem.

The uncertainty principle states that the position and momentum of an atom cannot be measured simultaneously. It gives uncertainty in position if we have uncertainty in momentum.

The expression for the uncertainty principle.

xph2

Here,xis the change in position, pis the change in momentum and h is the reduced Planck's constant. Write the expression for uncertainty in position.

x=12h2mk1/4 鈥︹ (1)

Here, xis the uncertainty in position, h is reduced Planck's constant, m is the mass and k is the constant.

The expression for uncertainty in momentum.

p=h2(mk)1/4 鈥︹ (2)

Here, pis the uncertainty in momentum, is reduced Planck's constant, m is the mass and k is the constant.

02

Step 2:Product

Multiply equation (1) and (2).

xp=12h2mk1/4h2(mk)1/4

=h2

The product of uncertainties is equal to h2which is in accordance with the Uncertainty principle.

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Most popular questions from this chapter

Outline a procedure for predicting how the quantum-mechanically allowed energies for a harmonic oscillator should depend on a quantum number. In essence, allowed kinetic energies are the particle-in-a box energies, except the length Lis replaced by the distance between classical tuning points. Expressed in terms of E. Apply this procedure to a potential energy of the form U(x) = - b/x where b is a constant. Assume that at the origin there is an infinitely high wall, making it one turning point, and determine the other numing point in terms of E. For the average potential energy, use its value at half way between the tuning points. Again in terms of E. Find and expression for the allowed energies in terms of m, b, and n. (Although three dimensional, the hydrogen atom potential energy is of this form. and the allowed energy levels depend on a quantum number exactly as this simple model predicts.)

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Show that the uncertainty in a particle鈥檚 position in an infinite well in the general case of arbitrary nis given by

L11212n22

Discuss the dependence. In what circumstance does it agree with the classical uncertainty of discussed in Exercise 55?

What is the probability that the particle would be found between x = 0and x = 1/a?

In Section 5.5, it was shown that the infinite well energies follow simply from=hp the formula for kinetic energy, p2/2m; and a famous standing-wave condition, =2L/N. The arguments are perfectly valid when the potential energy is 0(inside the well) and L is strictly constant, but they can also be useful in other cases. The length L allowed the wave should be roughly the distance between the classical turning points, where there is no kinetic energy left. Apply these arguments to the oscillator potential energy, U(x)=12kx2.Find the location x of the classical turning point in terms of E; use twice this distance for L; then insert this into the infinite well energy formula, so that appears on both sides. Thus far, the procedure really only deals with kinetic energy. Assume, as is true for a classical oscillator, that there is as much potential energy, on average, as kinetic energy. What do you obtain for the quantized energies?

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